I am attempting to write a program that takes a number(picked by the user) of test scores in an array then calculates the average and outputs the number of passed and failed tests.
On a side note I am attempting to use array notation in the main function and pointer notation in the other functions
#include<iostream>
#include<iomanip>
using namespace std;
int numScores;
int counter = 0;
double *scores;
//Function Prototypes
I'm trying to write a program that will allow a user to enter infinite numbers (one at a time) with a way to stop entering values, and once it stops it immediately displays:
Lowest number: Highest number: Number of values entered: Average of numbers:
what I can't figure out is:
-how to end the loop with something other than a number, preferably a char, so that it doesn't affect the average/lowest/highest
-how to output the lowest and highest numbers in a loop (would be easier to figure out were it finite and I could just type a bunch of printf/scanf)
What I have so far:
Code:
#include <stdio.h>#include <stdlib.h> #define pause system("pause") main(){ //n = amount of numbers input //x = number given by user //s = smallest number //l = largest number }
We were discussing how to find average time complexity of different algorithms. Suppose I've a the following nested loop
for(int i=0;i<n;i++) { min = i;
[Code].....
Now the outer loop will iterate N times. the inner loop will always iterate 3 times no matter what the value of N is. so the worst case time complexity should be O(n^2) but what about the average case and the best case? I mean in terms of searching we can figure out and distinguish between the worst,best and average as it depends upon the number of comparisons. But here how can the average and best case be different then the worst case.
I must write a function that has a one dimensional double array and the number of values in the array as its arguments. Normalize the values. I must also print the maximum, minimum, average and numbers of values above the average in the array.
The equation that computes the normalized value from a value x is:
My code does not print the correct normalized value, average and values above average.
Code: #include <stdio.h> int findMax( double array1[], int num_elements) // This function computes the maximum value of the array { int i, max=-32000; for (i=0; i<num_elements; i++)
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) { int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0; for (auto i : array) { sum += i; if (i > 0) { pos_sum += i; ++pos_count; }
I was trying to make a program that asks the number of grades, get the grades and then get the average. I know I have to save the grades in an array but i don't know exactly how.
I am getting the hang of it pretty well. I created a program that asks the user to input arrays. Now, I need to calculate the average of the inputted arrays, and I need to place them in order from low to high. I have been struggling with doing these two parts for a while now and now decided that the book is not useful, I need some from some actual programmers. I attached my program.
My program printed here!
Code: #include <iostream> using namespace std; int main()
i wrote following code to calculate average of the values entered to the array.After displaying the output following error was displayed.
"Run-Time Check Failure #2 - Stack around the variable 'marks' was corrupted.
A buffer overrun has occurred in q 3 410005111.exe which has corrupted the program's internal state. Press Break to debug the program or Continue to terminate the program. "
//Average mark of student 1 cout<<"Avarage mark of the student 1 :"<<(marks[0][0]+marks[1][0]+marks[2][0]+marks[3][0]); cout<<endl;
My program thus far is: (omitted code to shorten post and remove irrelevant information.
I don't know if it is because I have been working on other things and forgot how to proceed with the calculations and display, but I am just stuck. I'm not sure how to have the program read the numbers from columns 2 through 5 and then divide by 3. As you can see in my DisplayAverages() method I should have the ConsoleWrite and WriteLines done properly.
i'm having trouble trying to make this code works .. the program must repeatedly asks user for the age of a person until user enters -1 ,, once he/she entered -1 the program calculates ( smallest value entered, largest value , and average )excluding -1 from calculation
i've been working on this for a weeks this is the best i could do.i know average must add all the entered values , not only smallest and largest but how can i do that here ?
Code:
#include<stdio.h> int main(void) { int age ; int v; int counter; int l=0; int s=0; int limit; }
I have written two separate programs; Program 1 calculates the average of an array of numbers which has been hard-coded into the program. Program 2 reads an array of numbers from a text file and displays them on the output.
I wish to combine these two programs into one by making Program 1 read the array of numbers from the file and then calculate the average using that instead of the array { 84, 92, 76, 81, 56 } as outlined below. I only wish to display the average in the output, not the number array as Program 2 does.
I have tried to do most of the work, I just need modifying the code slightly so it reads the number array from the file and calculates the average.
Program 1
#include <iostream> #include <cmath> #include <math.h> #include <fstream> #include <string> #include <numeric> using namespace std; int main() { const int nNumStudents = 5;
I am facing a problem which i could not obtain the total numbers which is greater than the average value. For example:
#include <iostream> using namespace std; int main (){ int size , count; double no, max, min ,total, sum , average;
[Code] ....
In this case im able to compute the average of the numbers but when it comes to capture the total of numbers which is greater than the average value, how to compile the code , because the average number is only been compute once all the value capture by the input of user is sum up.
I am attempting to write a program " that has a function that is passed an array of int and its size, and with that it prints out only the numbers that are above average. "
I have included my code so far, but I am only getting one value as output, and that value seems to be completely off. I keep trying, but I am really stuck.
#include <iostream> using namespace std; int average(int values[],int size); int main(){ int size; int values[] = {1,2,3,4,5,6};
[Code] ....
Added the floats in the average() function. But there is still a value problem.
How to traverse through this array and output each student and score that falls below the average. I think I may have the method down for traversing through the list to find the "total score" however, before proceeding under a possible wrong presumption, I would like confirmation as to whether or not I'm understanding this or botching this concept.
void dispLowScore(struct payload *arrayStart , //first element of array struct payload *arrayEnd ) //last element of array { int studentCount; //total number of students in list/array int totalScore ; //accumulated value of all scores added together float averageScore; //totalScore / studentCount
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/ #include <stdio.h> int main(void) { /* Declare an array of integers */ int Grades[5]; int nCount; int nTotal = 0; /* Declare and initialise the value */ float fAverage;
im trying to write a source code that find the smallest, largest and average of numbers in array. the code runs fine, but it is not giving the highest number and the the average should include only four number excluding highest and smallest number from the array.
void OlympicJudging() // Olympic Judging { int numbers [6]; double average, sum = 0; int temp; for(int i = 0; i < 6; i++){ cout << "Please type a value for scores: "; cin >> numbers[i];
So for a project I'm working on, I'm using an array and generating it's values randomly but unique. Currently I'm working on a 3X3 array and the generated values are in the range from 1-9. So I wrote a function that will tell me the position of the cell whose value is 9. This is the function I wrote:
Code: void Llogaritje1(int t[3][3],int &i, int &j){ int y,l; for(y=0;y<3;y++){ for(l=0;l<3;l++){ if(t[y][l]==9){ i=y; j=l; break; } }if(t[y][l]==9) break; } }
But it doesn't work on all cells. Seems like at cells t[1][0] and t[2][0] the values that i and j take are 0 0 since when I print them after excecuting the function that's what it returns. I really don't understand why.
I am trying to make my program read a bunch of numbers in an array to find its maximum and minimum. the program will ask the user to enter in as much number as possible until they enter a non number/letter. i got my program to find the maximum value but the program couldn't read the minimum value. it always says zero. also everytime i enter the number 0, the program will just finish its loop statement. If i typed in a negative number, it'll read the negative number as its minimum.
Code: #include <stdio.h> int main() { //-------variables------------------ double list[1000]; // can hold 1000 items int i; char letter; int max = list[0]; int min = list[0];
Most of this program is working correctly, however when I get to the part on lines 70 to 78 to try and use the function on lines 103 to 113 to find out each diagonals value and then print each one back. But when this runs it only returns the value for [0][0] for each run through the loop and I'm not really sure why. I know its probably something simple but I'm just missing it,
Code: 1 #include<stdio.h> 2 #include<stdlib.h> 3 #include<time.h> 4 #define MAX 100 5 6 void display_menu(); 7 int check_option(int);
