C :: Cast To Character Pointer For Printf

I cannot get the following to compile. The problem is the printf on the last line. I understand that printf requires a char (or pointer to char). I understand that I can convert between datatypes by putting the target data type in parenthises in front of the variable. But how do I cast the integer into a character and then get it's pointer to pass into printf?

Following is my code. I compile with gcc temp.c -o temp.

Note that I have tried many attempts at that last line and this is just the one that I really, really think should work (or is at least the closest to the correct answer).

This code shown below, using printf("%s", &(char)nextChar); returns

temp.c:26: error: lvalue required as unary '&' operand

If I try to use printf("%s", *(char)nextChar); I get the error

temp.c:26: error: invalid type argument of 'unary *' (have 'int')

This line printf("%s", (char)nextChar); returns the obvious

format '%s' expects type 'char *', but argument 2 has type 'int'

Code:

#include <stdio.h>
int main() {
printf("hello, world
");
#if defined(SUNDIALS_EXTENDED_PRECISION)

[Code] ....