I keep getting this warning message and I do not know how to fix it. Is it because I'm using char to instead of strings to replace all 't' with 'lp'?
#include<iostream>
#include<string>
#include <stdio.h>
using namespace std;
char * scanf(char * a) {
[code]....
Here's my code. The error's at the last line.
Code:
#include <stdio.h>
#include <string.h>
#include <ctype.h>
#define max_con 30
void add_contact();
void edit_contact();
void del_contact();
void list_contact();
[Code] .....
Here's the line of code with the warning
Code: if((addressbook[3][num][4]=='-')&&(strlen(addressbook[3][num])=='10'))
Or what might be the possible causes of such a warning?
When i am entering single character instead of 'miz' then it is working great. But when i am using multi character like 'miz' it is showing error output. i did this program with c++ it is working but not working in c.When i am running this program it is showing {warning] multi character constant.
Code:
#include<stdio.h>
#include<string.h>
main()
{
char a;
printf("Please Enter your First Name: ");
scanf("%s",&a);
[Code]....
Can distinguish between character constant and string constant giving examples
View 1 Replies View RelatedHow to do this?
View 10 Replies View RelatedDouble values are stored in text file. 23.5 36.8 34.2 ... My teacher told me to read them character by character and then make words, like i have to read "2" "3" "." "5" and now have to make it or treat it as word and then using atoi(). I have to convert it into double. but i dont know how to do this....
View 5 Replies View RelatedI have to optimize a code for below scenario. I am reading stdin (a file redirected to stdin) character by character. How many chars are going to come is not known. After every few chars there is a seaparator. e.g $ as below
rhhrkkj$hghjhdf$ddfkrjt
While reading, if the separator arrives I'm processing the string stored before that separator and then continue reading stdin in same fashion, till EOF. I am using getc(stdin) to read chars.
Using gprof I can see most of the program time is spent inside main() , for this reading logic. Rest of the program is just some insert and search operations. I am getting time of 0.01 secs at the moment, want to reduce further.
How do I write an a program that will read an input file character by character?
View 1 Replies View RelatedIn my program, I'm supposed to read a text file (the name of which is given to me as a command line paramater, as long with an integer), and display the text in a specific format (each line can only be as long as the integer). However, I'm having trouble even reading the text file. I don't know the syntax. I'm only allowed to edit the function that does the formatting, and the code in that is
void typeset (int maxWidth, istream& documentIn)
I don't know how to 'read' the file, as most examples online are ifstream, or openFile or something like that. What I want to do is just read the first character of the file, and continuously keep reading characters until the end of the file.
So I'm trying to create a function that replaces any instance of a character in a string with another. So first I tried the replace() string member function:
In my implementation file
void NewString::ReplaceChar(const char& target,const char& entry)
{
this->replace(this->begin(),this->end(), target, entry);
};
Main program
#include "NewString.h"
using namespace ...;
int main()
[Code].....
Instead of replacing the the l's with y's it outputted a long string of y's. Also, NewString is derived from the string class (it's for the assignment). the header and whole implementation file, already tested.
I've also tried, instead, to use a for loop in ReplaceChar() but I need to overload the == operator and I don't know how I should exactly:
bool NewString::operator ==(const char& target)const {
if(*this == target)
return true;
[Code]....
I want the == operator to test if the value in the char array is equal to target but I'm not sure how to pass in the position. I'm guessing the this pointer in ReplaceChar() is not the same as the one dereferenced in ==() because target is never replaced by entry in the string.
I am trying to record some information in a file and allow user to delete a record. I am facing this message in Autos section of MVS (Error reading character of string). Here is the code:
int removeRecord(string name, int &row)//remove a record
{
const string data="database.txt";
fstream records;
records.open(data.c_str());
const string cpData="temp.txt";
[code].....
If I delete the any row (except last roe) it works but then add a copy of last record (sometimes fully sometimes partially) at the end of the file!! if i delete the last record it does not do anything.
I am suppose to make a program that when the user is asked "Enter a Letter for the day:" if the user enters M or m then the screen will output "The day of the week is Monday" and so on until Sunday. I looked over my code and everything looks right but I still get errors saying Missing terminating character " and int function main error.
#include <iostream>
using namespace std;
int main() {
char day;
cout << "Enter a letter for a day of the week: ";
[code]....
I was trying to write a character controller but when I went to add my pointer to my character I get error
C2143: syntax error : missing ';' before '*'
I've looked at all my classes involved but I don't see any errors and Visual Studio doesn't report any other specific errors. Is there any way of finding the source of this type of error?
How can i make my program to accept only numerical values and gives a error notice if a character or a symbol is entered???
View 4 Replies View RelatedI'm new in programming, and trying to write a code in C. The requirement is following - to write a text, and to find frequency of 1 chosen character in it. The main thing is that program should check user input (for example, I want to check if user entered "char" --> then correct, or if entered "int" --> not correct). But the program still doesn't check. So I have:
Code:
#include <stdio.h>
int main(){
char c[1000], ch;
char i, count=0;
printf("Enter a text: ");
gets(c);
[Code] ....
Am I on my right way using if/else?
Can we do this :
Code:
char strings[][100]={"ABC","EFG","IJK","LKM"};
char temp[100];
temp=strings[1];
I have this code for a computer project... (store management) but the character strings are not copied on text file..
#include<iostream.h>
#include<conio.h>
#include<fstream.h>
class Store {
public:
char *item_name[5];
store()
[Code] .....
Now when i run the program, it gives a error :::
ERROR
address 0x0
How can i write these strings to the text file?
I am currently reading several values one after another from a file like so:
Code: ifstream f;
double x;
double a, b, c, d;
f.read((char *)&x, sizeof (double));
a = x;
f.read((char *)&x, sizeof (double));
b = x;
//etc ... for several other values Question:
How can I read every (lets say) 3rd value instead of every next value from the file
I'm trying to get the int value of each character in a string and then add them all together so I can do a 1's complement of the total value. I'm trying to do simple checkum kinda of thing for verification of data.
For example: string DPacket = "Hello World!";
I would like to have each character added and do the ones complement. Will it be easier to convert first to int and then add or any other easier way? So my result should be the decimal value addition of each character and then do the ones complement to that.
How can I move a character around a 2D map? After some research and a bunch of work I made a function for movement:
unsigned int gamespeed = 100;
unsigned int stage = 1;
void controls()
{
[Code]....
Maps are stored in a different .cpp file
So this code works, but is complicated, ugly and evil (I have to make a pointer to the first map and change the pointer to the next map every time the user reaches the exit, without the pointer this code is, of course, incompatible). How can I reduce this code to be less evil/ugly or at least smaller?
Also it would be nice if the user could move around with arrows as well as with WASD
Why TAB with ASCII value 9 is non printable character and SPACE with ASCII value 32 is printable?I can open any editor and press any of them and I see it on screen(If I press tab cursor is moved by tab, and space if I press space)....
Then why one of them is printable and other non printable?
I know how to remove certain characters from a string by using something like this:
Code: string str ("Hello world!");
erase (0, 6);
That's great if I want to do that manually, but say if someone entered a string, how would I automatically remove every other character they entered?
I want to check whether a certain character is in a string or not but my code is not working
Code:
#include<stdio.h>
#include<string.h>
int main()
{
[Code].....
Here is my program to look up words. How do I use character pointers instead of using arrays?
Code:
#include <stdio.h>
struct entry
{
[Code].....
Let's say i have a string "file.txt" and i want to insert "_out" to make it look like "file_out.txt"
I don't know how to do this ....
