C++ :: Return A Pointer To The Character At The Index Given
Nov 5, 2014
I need understanding the logic behind this function. The function is supposed to "Return a pointer to the character at the index given" . For example, what exactly are we declaring at "(char * const c, int index)"? where does "index" come from or equal to in the body of the function?
Code:
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char * GetValueAtIndex(char * const c, int index)
{
int i = 0;
char *p = c;
while (i++ != index)
p++;
return p;
}
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Jan 10, 2015
Here's my code
bitIndex = 5;
Code:
bool getBS(PBitSet _this, int bitIndex) {
if(_this->bits & (1 >> bitIndex))
return true;
else
return false;}
I want this code to return the value of the bit at position bitIndex. It can be either false or true. The problem is, that it always returns false, even thought I enter 16 as my number, so the 5th bit should be true.
0000|0000 = 0
0001|0000 = 16
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Oct 10, 2014
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream>
#include <istream>
#include <cstdlib>
#include <cassert>
#include <string>
using namespace std;
int getIndex(int, int);
[Code] .....
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Oct 28, 2014
I've been typed out a C program to let the user define the size of their string , and key in characters for this string , the program would then prompt the user for a character to search for in the string and return it's index value. Eg. Index of c in abc is 2. My code is as shown:
#include<stdio.h>
#define SIZE 20
int search(char x[SIZE+1] , int n , char s);
int main(void){
char x[SIZE+1] , s;
int n , index;
[Code] ....
However , after I key in my characters for the string , the program does not prompt me to input a character to look for, it just prints it out and returns some funny number. But the program works just fine is I move this portion to the top :
printf("Enter alphabet to find: ");
scanf("%c",&s);
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Apr 17, 2014
Here is my code to find the index of a string array whose string is equal to the query string. I have checked the program can return the correct index, but the cout result is totally wrong.
#include <iostream>
#include <string>
using namespace std;
[Code].....
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Dec 23, 2013
I am trying to write a light weight printf style function.
I have got this far:
Code:
void println(const char *txData){
LOG(__PRETTY_FUNCTION__);
UARTPuts (LPC_UART0, txData);
}
void miniPrint(const char *format, ...)
{
unsigned int index = 0;
va_list argptr;
va_start(argptr, format);
[Code]....
I understand why I think. When I am passing the reference to the array possion it is outputting everything up to the next /0. So my question is how do I stop it?
I dont have much choice as to how the output wants it:
Code: void UARTPuts(LPC_UART_TypeDef *UARTx, const void *str)
Thats library code, so I dont want to change it. I.e I have to pass an address into println.
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Oct 10, 2014
I'm working on an assignment where I have to read an image in the PPM format. This format consists of a header that contains the parameters and the rest is raw bits.
I have to work with a modified PPM image that contains a secret message. This message is stored in the first X number of bytes. To decode a single character I would have to look at the lowest level bit of 8 bytes and return that as a character, then repeat this for the length of the message.
The code below is what I have so far, but I do not get the expected output but instead I get smiley-faces.... or other ASCII characters depending on the shift.
char buffer = 0;
int MsgSize =(size*8);
int nRead = 0;
printf("The secret message is displayed below: ");
for(i; i<MsgSize; i++) {
[Code] ....
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Apr 18, 2014
I cannot get the following to compile. The problem is the printf on the last line. I understand that printf requires a char (or pointer to char). I understand that I can convert between datatypes by putting the target data type in parenthises in front of the variable. But how do I cast the integer into a character and then get it's pointer to pass into printf?
Following is my code. I compile with gcc temp.c -o temp.
Note that I have tried many attempts at that last line and this is just the one that I really, really think should work (or is at least the closest to the correct answer).
This code shown below, using printf("%s", &(char)nextChar); returns
temp.c:26: error: lvalue required as unary '&' operand
If I try to use printf("%s", *(char)nextChar); I get the error
temp.c:26: error: invalid type argument of 'unary *' (have 'int')
This line printf("%s", (char)nextChar); returns the obvious
format '%s' expects type 'char *', but argument 2 has type 'int'
Code:
#include <stdio.h>
int main() {
printf("hello, world
");
#if defined(SUNDIALS_EXTENDED_PRECISION)
[Code] ....
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Apr 1, 2013
Here is what's up:
struct Square {int number, myClass* myclass};
int main() {
vector<myClass> classes;
myClass unrelated;
classes.push_back(unrelated);
Square newClass = {3, &classes.at(0)};
.
.
.
myClass is a class I have. Now, in the class, I have a function what_value and I need to get the classes.at(0) from the pointer to it in another function. But the problem is, how can I do it? I'm completely stumped, here's what I thought of:
newClass.*myclass.what_value();
And it I get an error from the compiler. Basically, how can I do this in another function with a pointer:
classes.at(0).what_value();
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Mar 6, 2015
Here is the part of my code that I need to return two values. I am working on a roulette program and I need to return the choice and the number they are betting on. How can I use a pointer to achieve this?
Code:
int makeBet(char choice, int num){
printf("
What type of bet would you like to place? ");
printf("
Type n for number.
Type e for even/odd.
Type d for dozen.
[Code] ....
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Aug 1, 2014
How to return as a pointer to a string?
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May 1, 2013
I am trying to return a pointer from a method. Below is a sample of my code.
CSubnode * CTest::GetSubNode() {
return m_psubnode;//this is declared in CTest as CSunbnode * m_psubnode
}
//in another class
m_subnode = m_ptest->GetSubNode(); //m_subnode is declared as a pointer
Is this the correct why to return a pointer?
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Jul 30, 2014
Ok here is the code
//assuming that all the directives have been included here
void ptrPointer(vector<string>* const p, int n);
int main() {
vector<string> inventory;
vector.push_back("sword");
vector.push_back("knife");
[Code] .....
Well...my question is how come the last statement or cout statement to be accurate won't work and display? Since we can do something like this below?
string text = "some text";
string *p = &text;
cout << p;
I passed the address of the vector to the function. And then display the address. It is a pretty common operation. But it just won't work. But then we do something simple similar to that of the vector. But it works.
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Sep 29, 2012
I was trying to write a character controller but when I went to add my pointer to my character I get error
C2143: syntax error : missing ';' before '*'
I've looked at all my classes involved but I don't see any errors and Visual Studio doesn't report any other specific errors. Is there any way of finding the source of this type of error?
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Jul 13, 2014
/*
* symboltable.c
*/
#include "symboltable.h"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "include/utlist.h"
[Code] ....
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Sep 26, 2013
question from chapter 11, qn 8 modern C programming by king
Write the following function: Code: int *find_largest(int a[], int n); When passed an array a of length n, the function will return a pointer to the array's largest element
Code:
#include <stdio.h>
int *find_largest(int a[], int n)
{
int i, x;
x = 0;
[Code].....
have traced the code line by line and it prints correctly up to line 31. However, when the program exits (line 35) , it goes to some other screen with very complex code and my output disappears.
Just to clarify: If I just run the code as is, there is no output. However, when I trace the code line by line, the output appears, but then disappears as the program exits My input was 1 2 3 4 5 6
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Jun 29, 2014
I'm trying to write a function that returns a pointer to a dynamically allocated array. Here's my code:
#include <iostream>
using namespace std;
void IndexArray(int, int);
int main(){
int *arr, n;
[Code] ....
When I try running the program, I get the error
"Unable to start program 'D:C++FilesdynamicArraySolReleasedynamicArray.exe'. The system cannot find the file specified."
I'm honestly not sure if the issue is my program, or something with C++. At the moment, I cannot debug any of my programs or else I get the same exact error. I basically need to release everything without debugging it. I last used C++ about a year ago and I'm finally back in school, and so trying to get back into it. I use Microsoft Visual C++ 2010.
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Sep 21, 2013
I have a function that I want to exit gracefully when an "error" occurs in an input file. My function declaration is:
Code: BSTnode *buildTree(FILE *fp)
The few lines that are causing the problems are:
Code: if(regcomp(®ex, to_find, REG_EXTENDED | REG_NEWLINE) != 0) {
fprintf(stderr, "Failed to compile regex '%s'
", to_find);
return EXIT_FAILURE;
}
I know that if I just use "return" by itself the warning goes away but fails to exit when the error occurs. I also believe this may not be the correct use of stderr. But I need the program to exit when an error has occurred.
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Feb 7, 2014
I am making a function that will return a pointer to a long long variable. For example, I have the next variable prototype: Code: long long funcName(long long x, int s); I want to change the return value, and the first parameter to pointers to long long.
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Mar 17, 2013
i need to return a struct pointer dynamically allocated inside a function call void function() which is done using 'out parameters' in following code
struct my_struct {
int x;
} void my_function( my_struct** result ) {
my_struct* x = new my_struct{ 10 };
//...
*result = x;
}
Now i have a doubt, so if i want to print the return value from struct pointer, should i need to print it in the void function() or in the caller the function...
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Apr 25, 2014
I am writing a class Player which has several char arrays as private fields. I am trying to write a method which returns an array as a pointer, but doesn't alter the array in any way, thus the const.
Here is a snippet:
Code: class Player
{
private:
char state[MAX_STATE_CHAR + ONE_VALUE];
int rating;
char last[MAX_NAME_CHAR + ONE_VALUE];
char first[MAX_NAME_CHAR + ONE_VALUE];
int groupNumber = NEG_ONE;
public:
char * GetFirst() const
{
return first;
}
Visual studio is saying that the return type doesn't match.
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May 21, 2013
The code below is supposed to fill, show, and revalue property. The fill function is supposed to return a pointer that creates a range of property values. The show function is supposed to show the property values entered and the revalued property values. I think part of the problem is the returned pointer from the fill function. Once that is cleared up, I think I will find more problems.
Code:
#include <iostream>
const int Max = 5;
// function prototypes
double fill_array(double ar[], int limit);
void show_array(double * begin, double * end);
[Code] .....
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Sep 14, 2014
I keep getting this warning message and I do not know how to fix it. Is it because I'm using char to instead of strings to replace all 't' with 'lp'?
#include<iostream>
#include<string>
#include <stdio.h>
using namespace std;
char * scanf(char * a) {
[code]....
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Jul 25, 2012
Double values are stored in text file. 23.5 36.8 34.2 ... My teacher told me to read them character by character and then make words, like i have to read "2" "3" "." "5" and now have to make it or treat it as word and then using atoi(). I have to convert it into double. but i dont know how to do this....
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Nov 10, 2013
I have to optimize a code for below scenario. I am reading stdin (a file redirected to stdin) character by character. How many chars are going to come is not known. After every few chars there is a seaparator. e.g $ as below
rhhrkkj$hghjhdf$ddfkrjt
While reading, if the separator arrives I'm processing the string stored before that separator and then continue reading stdin in same fashion, till EOF. I am using getc(stdin) to read chars.
Using gprof I can see most of the program time is spent inside main() , for this reading logic. Rest of the program is just some insert and search operations. I am getting time of 0.01 secs at the moment, want to reduce further.
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Aug 10, 2012
How do I write an a program that will read an input file character by character?
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