Here is the code:
int unsigned long a,b;
scanf("%lu",&a);
scanf("%lu",&b);
printf("%lu",a*b);
suppose we input a very large number on a and b (no more than 1000 digit)
like a = 1234567890123456789012345678901234567890
and b = 9876543210987654321098765432109876543210
it outputs 1, why is it?
It is probably the answer is too big, is there any way to show a*b?
here's one more thing id like to do to make the input even better able to handle user error, but im not sure if its possible or at least easy. I need the function to return a large positive number. As of right now, it can handle users entering characters, but what if the user enters a negative number? is there a way to check to see if what is coming in is negative before the sign gets lost in conversion to unsigned"ness"?
Code:
unsigned long getNum(char prompt[80])
{
unsigned long darts;
printf("%s", prompt);
while((scanf("%lu", &darts)) != 1)
{
[code]....
is there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c
", m, ' ',*);
}
this is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
This is supposed to output t=m and then m is plugged into a function say for -3, plugging it into function f gives 23, well i want 22 blank spaces and then a asterik and go to next line. that is why i put -1 after %'f(m)-1's i
The asterisk appear right next to the t value here but they are way to the right of it when i made this post.
I would like the following code to print: "Why doesn't this print?" and "I would like to print the sum of nc: 5". What am I doing wrong.
#include <stdio.h>
//Use to test ideas and formats//
main() {
int c, nc;
nc = 0;
[code]....
My result as compiled by gcc -o testing testing.c
This prints.
test
t1,e2,s3,t4,
5,
I have not figured out how to sum and print as the above code indicates, which complicates my ability to do many of the exercises in "The C Programming Language". I am using a MacBook gcc compiler and X code as well. I cannot get the last two printf functions to work. I did the temperature example with "while (fahr <= upper)" and the printf printed.
This code runs. However, when I run it, the text from printf doesn't appear until after I type in the two numbers.
I use Wascana, will it run correctly on other compilers?
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main() {
fflush(stdout);
[Code].....
And this is how it turns out on the screen:
Code:
6
3
What size is the die:
how many dice to roll:
Numbers are 3d6
Rolling die no.1...
RolledDie: 4 DieTotal: 4
Rolling die no.2...
RolledDie: 5 DieTotal: 9
Rolling die no.3...
RolledDie: 5 DieTotal: 14
The total is: 14
how to print the result on screen without using printf in C...?
View 6 Replies View RelatedHow do I print an unsigned char in c++? E.g.
unsigned char a[100] = "acdef";
wprintf(L"a is %u
", a);
wcout << "a is " << a << endl;
gives
a is 2880488
a is 002BF3E8
and not
a is acdef
a is acdef
??
what is the difference between unsigned char and char?
So I have been given and as part of the solution I need to count the number of digits in a long long variable. To do this I use a while loop, but it is behaving strangely. Here is the code.
#include <stdio.h>
#include <cs50.h>
#include <math.h>
int main (void) {
printf("What is the card number?");
long long card = GetLongLong();
if(card <= 0)
[Code] .....
When I execute the program it asked for the number, but then nothing happens. Of course, my first instinct was that the program was caught in an infinite loop somehow, but could not figure out how. I commented out the while loop and the program completed (albeit returning the incorrect value), so I was further convinced that there was an infinite loop that I was not seeing. I ran the program throug gdb. Strangely, the program did not loop infinitely, instead it got to line 16 [while(card1 > 0] and then just stopped, it was not executing the next line of code at all.
How can I read a file that contains numbers only, but read it by three digits at a time? I have a long string of numbers and every three digits corresponds to a particular number in itself. i.e. a string of 064045154 would need to be read as '064' '045' and '154'. I need to then subtract one from each of these numbers and the new values I need to convert into their ASCII characters and place these in a new file. This is what I have (focusing on the 'Decrypt' function) but all it does is in the new file place a string of the same character repeated over and over a total number of times equal to the number of integers in the numbers file.
Code:
#include "stdio.h"
#include "stdlib.h"
#include "string.h"
#include "limits.h"
int Encrypt(char * FILENAME)
[Code]..
I have a long long int k=0x0000888804eaad0e
And i need the reverse of this (nibble wise) in other long long int variable.
That is i want the result to be = q=0x0000e0daae408888;
Or the result also can be like this = q=0xe0daae4088880000;
How to accomplish the above?
I was going through the following statement in a c book:
"interpreting -1 as unsigned int leads to a big +ve number"
-1 is already unsigned .... then what does the above statement mean ??
How do I convert just the number from position 4 to 15 from this char array and convert to int and save to variable
char numbers[]="54155444546546545643246543241465432165456";
the real char got 1000 digits this is just example how do i convert chars from numbers[4] to numbers[15] and save them as one number ? in this case i will get int x = 5444546546545643 as u can see char numbers as a example above
I'm having an issue with the following assignment:
Program is supposed to take in an unsigned number and afterwards return the 'n-th' member of the following recursive function:
f(1) = 1, f(2) = 2; f(3) = 3; f(n+3) = f(n+2) + f(n+1) + f(n), n>0;
When I worked with Fibonacci it was pretty easy since I just had to decrement the next member for each step. I used the following:
#include <stdio.h>
#include <stdlib.h>
#define MAX 100
int fib(int n) {
static int memorize[MAX] = {1,1};
if(memorize[n])
return memorize[n];
[Code] ....
My main problem is that I have no visual of the current function, as well as the fact that it takes the f(n+3) = f(n+2) + f(n+1) + f(n), whilist I've only got f(n) to begin with.
How can i write a function that will read an "unsigned integer" into a variable of type "unsigned short int"? i can not use cin >> inside the function.. so i am looking for atleast a hint!
View 16 Replies View Relatedis there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c", m, ' ',*);
}
This is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
How to reserved int number and print as float number ?
View 1 Replies View RelatedI can not understand huge pointer, how its working.
#include<stdio.h>/ *How its working &decleration*/
int main(){
int huge *a =(int huge *)0x59990005;
int huge *b =(int huge *)0x59980015;
if(a == b)
printf("power of pointer");
else
printf("power of c");
return 0;
}
I’m writing an application for raw image processing but I cannot allocate the necessary block of memory, the following simple code gives me an allocation error.
double (*test)[4];
int block = 32747520;
test = new double[block][4];
off course with smaller block size (i.e. int block = 327475;) it works fine. Is there an allocation limit? How it is possible to deal with big blocks of memory?
I have been coding a while on a 2D random terrain game. How would I go about saving the maps? I have an array for blocks, lighting, background and background lighting. The lighting is done in real-time, so exclude that.
But with two 32000x3200 arrays, I still need to store 204800000 separate numbers in a file. Oh god. How can I have this? I could write down the separate numbers, but...yeah.
If it matters, this is made in freeglut.
Im trying to implement a way to use really big numbers to be able to add, substract and multiply them with the class I made. for example:
huge a = "45646464646455464654656"
huge b = "456464564646544646"
huge c = a+b;
[Code]....
I want to build a server which holds hundreds of thousands of active users in memory. To keep all the users organized i would like to store them in a Vector.
The problem is how i could quickly and easy find the object whenever i need it? All users will have a unique ID. Would it be possible to keep some form of a Vector Index on the unique id number?
i have a spec for fetch the files from server and predict the un-used files from the directory in this situation i am going to fetch the files from server it will return huge files, the problem is the cpu usage will increase while i am fetching large files, so i like to eliminate this scenario.
View 1 Replies View RelatedI am trying to understand what techiques can be used to sort really huge files (larger than available memory). I did some googling and came across one technique.
1. Are there any better ways to get this done?
2. Is there some tweaking that can be done to make this itself better?
Large enough so that you get a lot of records, but small enough such that it will comfortably fit into memory
3. How do you decide on this value? Consider, memory is 4 GB and currently about 2GB is consumed, and file to sort is 10GB in size. (Consumed memory could of course change dynamically during execution - consumed more/less by other apps.)
How can i print out the SECOND MIN number and MAX number without using array?
cout << "Please input a positive integer: ";
cin >> input;
min = input, max = input, secondmin = input;
do {
cout << "Please input a positive integer: ";
cin >> input;
[Code] .....
#include<stdio.h>
#define TRUE 1
int formOddInt(int n);
[Code]....
