I need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
#include<iostream>
#include<conio.h>
using namespace std;
int main(void){
clrscr();
[Code] ....
I am trying to print ascii characters but problem is If i put a limit in for loop to 255 or more than 126 the output don't stop it keeps on going
I know there is another way to this program but what i want to know this why this happen in this logic....it doesn't happen if a<=125 or less then 125.
getline is not readable after first time through loop. It skips that line and goes to Do you want stop entry? line.
#include<iostream>
#include<string>
#include<cstring>
#include<cctype>
using namespace std;
void upr(const string& str);
[Code] ....
i just want to break the loop when user hit ENTER.But after that programm is stil working, i don't know why, becouse i have a code just like in book, i spend a lot of time with it.
int getinfo(student pa[], int n){
cout << "START" << endl;
int i = 0;
for(i; i < n; i++) {
cout << "Studetn name";
char name[SLEN];
[code].....
Suppose you want to develop a program to play lottery. The program randomly generates a Lottery of a three-digit number( any number from 100 to 999), prompts the user to enter a three-digit number, and determines whether the user wins according to the following rule:
1. If the user matches the lottery in exact order , the awards is $100,000.
2. If the user input matches the lottery digits, the awards is $50,000.
3. If two digit in the user input matches a digit in the lottery, the awards is $30,000.
4. If one digit in the user input matches a digit in the lottery,
the awards is $10,000.
Sample:
The winning number is 865.
Your ticket is 865 then 100000
Your tickect is 686, or 568,.. all digits are right but not in order
You get 50000
Your ticket is 860, or 186 .. then 30000
Your ticket is 800, 706, 600.. just one digit much you get
10000
Else
0
Im using if/else statements. Which syntax would I use to figure out the limit between 100-99?
I wondering how to stop a infinite loop. The program clears a file then opens it and refreshes it over and over(the file is going to be modified by another program). I want it to start from the beginning anytime i press enter or escape, it doesn't really matter as long as you can restart it.
Here is the complete code:
#include <cstdlib>
#include <iostream>
#include <fstream>
#include <conio.h>
#include <windows.h>
using namespace std;
void x() {Sleep(1000);}
[Code] .....
it will produce the answer above..when user enter a nonnumberic character it will force the user to reenter again
do
{
cout<<"Min of the secret number : ";
cin>>min;
}while(cin>>min);
cout<<"Max of the secret number : ";
cin>>max;
this is my coding but it will auto jump out when i enter non-numberic character
How to fix this when i run the program and enter my name then output my name in vertical position using the for loop and press enter the program do not stop
#include<stdio.h>
#include<conio.h>
#include<dos.h>
main() {
char name,n;
clrscr();
printf("Enter Your Name:");
scanf("%c",&name);
[Code] ....
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main ( void ) {
[Code] .....
Code:
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<string.h>
int main(void) {
int i;
char *str;
int len = 1;
[Code]...
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
I'm trying to end my program when the user presses the enter/return key.
I'm trying to do this with a break statement.
I have two different situations, one when it is a string, and the other one when it is a char.
for (int i = 0; i < 80; ++i)
{
string s;
cin >> s;
if (s == "
")
break;
S.PushStack(s);
}
I'm doing the same thing for char just replacing string with char.
I'm not sure what I am doing wrong but pressing enter does not end the program.
How to write a code that will let me input how many variables I want.
Write a program that will enable you to enter a certain amount of values
Eg. 4
And then add the corresponding integers. Ex.
Choice: 4 12 34 56 78
The sum of the integers is: 180.
We are making a program--but every time we input a value for scanf, the following for loop does not work and the program quits without displaying the for loop's function. We are not getting any errors.
View 11 Replies View RelatedI want to create a program where you enter today's date, in the following format: 02/04/2013. As well as your birth date in the following format: 27/09/1994. After doing that I want to assign the day, month and year of the present date, as well as the day, month and year of the birth date in to their own variables (for example, Day, Month, Year), and then calculate your age.
I have tried doing this with cin.get(), but this method is way too long, and I'm looking for a shorter method
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
View 1 Replies View RelatedWrite a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
Code:
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main() {
clrscr();
int i=0,flag=1;
cout<<"Enter the password.";
[Code] ....
When I input the password, the Backspace and the Enter keys are not working as they should. Also, I want to know if I can press enter only once to input the password, not twice.
Compiler is Turbo C++ 3.0 on Windows 7.
My program closes after the out even though i've used cin.get():
I want the program to stay open at least until you press enter, even after the whole output.
Code:
#include <iostream>#include <string>
int main()
{
std::cout << "Please enter your name";
std::string name;
std::cin>> name;
// build the message that we intend to write
[Code] .....
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
View 4 Replies View RelatedYou enter decimal number into the program and what base you want. The integer part of the decimal is being handled fine, but the decimal is not.
For example, I enter 15.6847 and base 10, which means I'm going from base 10 to base 10. It spits out 68469999999999 for the decimal part. (Do not worry about the first block of numbers. The second block seperated from the first by a space is where the decimal will appear in order.)
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
int baseConverter(int, int, int *, int *);
[Code] ....
a program that allows the user to enter a statement and outputs statistics; number of vowels, number of constants, percentage of vowels and constants, number of words, number of punctuation characters
View 2 Replies View RelatedWrite a program that prompts the user to enter an integer and then displays that integer as a product of its primes and if it is a prime then it should say so? Above is the question I have been given
#include <iostream>
#include <vector>
using namespace std;
int main () {
int num, result;
cout << "Enter A Number " << endl;
system ("pause");
return 0;
}
This is what I have so far, do I have to use a for loop, a while loop or a do loop,
Write a program that asks the user to enter a student’s grades on four exams. The program should display the four grades and the average of the four grades,rounded to the nearest tenth. To add the grades, use a variable called total_grade, which you should initialize to zero.As the program prompts for and obtains each grade, add the grade to total_grade using the += operator.
View 3 Replies View RelatedWrite a program that prompts the user to enter an item#, the program should determine if the item is in the file and print the price of the corresponding item. If the item is not in the file an error message should be printed.
All I have so far is
string item_no=0;
cout<<"Enter a item#";
getline(cin,item_no);
if stream openData;
I need to finish the rest in pseudo code
