C++ :: Program To Enter Today Date In Certain Format?
Apr 2, 2013
I want to create a program where you enter today's date, in the following format: 02/04/2013. As well as your birth date in the following format: 27/09/1994. After doing that I want to assign the day, month and year of the present date, as well as the day, month and year of the birth date in to their own variables (for example, Day, Month, Year), and then calculate your age.
I have tried doing this with cin.get(), but this method is way too long, and I'm looking for a shorter method
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Dec 4, 2014
I don't know how to ask the user to enter the date in this format (DD/MM/YY) and ISBN number with hyphens.
After user enter date and ISBN number, it should look like this:
Date: 5/24/12
ISBN: 0-000-12345-0
#include <iostream>
#include <string>
using namespace std;
int main() {
string date;//MM/DD/YY Format
[Code] ....
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Jul 24, 2014
The problem is that I need to figure out the user's birthday in months, days, hours, and minutes from today's date.
Here's what I have so far.
#include<iostream>
#include<cmath>
#include<ctime>
using namespace std;
int main() {
int todayDay, todayMonth, todayYear;
int birthDay, birthMonth, birthYear;
[Code] ....
I haven't initialized all the variables, yet. And it's very unfinished. I need to figure out how to convert years from the age into months only. And I need to figure out how to calculate the hours, seconds, and minutes.
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Oct 26, 2014
So I have a programming assignment which is for getting a user input in the format of m/d/yyyy. This is stored as d/m/yyyy. I have been able to code all the rest of the requirements of the program but the thing that is giving me trouble is this. The year is allowed to go from 1-3000. The format of the displayed date is:
a zero-filled, two-digit day number, a dash, full name of month, a dash, zero-filled, four-digit year.
I am able to use a switch statement in order to get my name of the month. What I am struggling to figure out is the whole zero filled two digit day and zero filled four digit year. From the way the input is store it appears to me that it will be stored as yyyy which means if you were to enter 0001 for year 1 then it should output it as that (this is an assumption based on format). What I don't get is that the day is entered and stored as d which means if you put in 12 how would it be stored. However if you put in 6 to print the output I would need to add a zero and I dont know how to do that either.
Here is the code for getting the input. The function must stay formated this way as per the instructor. The / is stored but ignored hence the char for second and fourth since / is a char
Code:
void getDate (int& day, int& month, int& year){
char second;
char fourth;
cout << "Please enter a date in the format of m/d/yyyy" << endl;
cin >> month >> second >> day >>fourth >> year;
}
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Dec 16, 2014
how my code should work is a console screen in which the user enters a date using format dd/mm/yyyy
Regardless of logical errors (checking days if bigger than 31 or negative values or.. etc) My code should be able to validate the following:
- if the user enters a letter, the program should output an error message
- if the user typed the date as 8/2/2014 the program should convert it to 08/02/2014 without returning an error message
Here's my code so far, I really can't find the bugs in it
#include<iostream>
using namespace std;
main(){
char d[2], m[2], y[4], br1, br2, dx, mx;
bool end, nobr1, nobr2;
[code]....
as you notice, I tried two different validating formats in the days and months, unfortunately they both failed..
Here's how my program is outputting so far:
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Jun 8, 2013
How do I convert date in integer format to DateTime without using DateTime?
I have tried:
Regex regex = new Regex(@"^(0[1-9]|1[012])(0[0-9]|1[0-9]|2[0-9]|3[01])(1[789]|[2-9][0-9])dd+$");
if (regex.IsMatch(txt_fromdate.Text) == true)
{
DateTime dt = DateTime.ParseExact(txt_fromdate.Text, "MMddyyyy", null);
}
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Mar 14, 2013
Currently I am working on a program where you enter in a date 14 03 2013 (Day, Month, Year) and you get the next day. I seem to be coming stuck with months with less than 31 days, and the whole leap year thing. Here is my code so far.
Code:
#include <stdio.h>
int day, month, year, next_day, next_month, next_year, calculation;
int main() {
printf("Enter a date in the form day/month/year: ");
scanf("%d %d %d", &day, &month, &year);
[Code] .....
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Oct 11, 2012
i'm making a program that, given a person's birthdate or any other date, will display the day of the week of the person was born.
There is this part where it says "use a switch statement to make this calculation, If desired month is 12, add the number of days for November, if desired month is 11 add the number of days for october....
So it's suppose to start with "case 12 :...
I can't figure out what to write for the statement....
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Oct 14, 2014
I wanted to write a program to convert a number into a more readable format. It's like, if the input enters the number as 2361263 the output should be like 2,361,263. I went about this problem like extraction the number first and then if the count was equal to multiple of three i'd print ',' instead of the number.
But initially when i wrote the code for extracting a single digit from the number
Code:
#include<stdio.h>
void main() {
unsigned long long num=pow(2,50);
int count=0;
while(num!=0) {
int last_digit;
[Code]....
I know that I'd lose the number when i finish printing it, but still I only end up printing the entire number in reverse order.
As in if the input is 1234 the output is 4,321 which is not what i want.
One way of overcoming this problem is to store the values in an array and then reading then back from the end. But i wanted to know if there is a better solution than this? To extract the digits from the number in the same order as it is in the number
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Oct 21, 2013
Write a program that determines the day number (1 to 366) in a year for a date that is provided as input data. As an example, January 1st, 1994, is day 1. December 31, 1993, is day 365. December 31, 1996 is day 366, since 1996 is a leap year. A year is a leap year if it is divisible by four, except that any year divisible by 100 is a leap year only if it is divisible by 40. Your program should accept the month, day, and year as integers. Include a function leap that returns 1 if called with a leap year, 0 otherwise. Extend the requested solution so that your program continues to prompt the user for new dates until a negative year is entered. This is what I have so far.
Code:
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int d,m,y;
int days=0;
int k;
[Code] .....
I am unsure how to make this a loop so that it keeps asking for dates?
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May 30, 2013
Write a well-commented C++ program that reformats and outputs the date. Prompt the user to input the date in the format dd/mm/yyyy and outputs it in this format month, dd, yyyy. For example, 07/06/2012 is displayed as June 07, 2012. You are provided with the file months.txt containing the months and their corresponding numbers, for example 01January 02February etc. Use getline(monthsFile,monthString) to read in a string from the file, and use the monthString.find() function to search for the number and extract the corresponding month.
-confused by the way she told me to use getline(monthsFile,monthString) => if I just do it like this I only get the first line from the txt file (01January)
-if I try putting all the months on one line in the txt file (which i'm not even sure i'm allowed to do), I'm not sure what to do for the length of my substring output. if I make it long enough to fit longer months like September, someone entering may gets both may and june in the output
-if I input all the months into separate variables, I'm not sure how to make it only output the month entered by the user
the months.txt file is as follows:
01January
02February
03March
04April
05May
06June
07July
08August
09September
10October
11Novmber
12December
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Jan 20, 2013
I am writing a C++ program which takes date & time input from the user. This is then parsed into a struct such as:
struct time
{
short year;
short month;
short day;
short hour;
short min;
};
My question is: how can I convert such a struct into a time_t object, which is an unsigned long giving the time as the number of seconds elapsed since the epoch Jan 1st 1970, 00:00, as set out in time.h.
I am wondering if this can be achieved using the standard library, or whether I just need to write a function to perform the appropriate arithmetic.
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Mar 22, 2013
I'm having a problem with my homework. The task is to write a program that will take time and date typed by user, and increase it by 1 minute. I should write 3 functions - first calls second function that updates time and calls third function, if time is 00:00.Time update works, but date update does not.My whole written code:
Code:
#include<stdio.h>
struct DateAndTime {
struct date {
int day;
int month;
int year;
[code]....
I should check if inputs are numbers only, so I tried including isdigit function from ctype.h library, but that didn't work either, after I was trying it for a good hour or so, but I kinda rage quit that...
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Apr 23, 2014
I'm trying to write a program that uses the Boost library to input a string date in the format mm/dd/year and outputs to the string its corresponding day of the week. I wrote the program that I thought would accomplish this, but it doesn't seem to work. Below is the code I wrote:
#include <string>
#include <iostream>
#include "boost/date_time/gregorian/gregorian.hpp"
[Code]....
When I compile this using codeblocks it gives me the error "In function `ZN5boost9date_time19month_str_to_ushortINS_9gregorian10greg_monthEEEtRKSs':|
C:Users
osaDesktop est3........Liboost_1_55_0oostdate_timedate_parsing.hpp|67|undefined reference to `boost::gregorian::greg_month::get_month_map_ptr()'". And it takes me to the file date_parsing.hpp and highlights line 67. I don't understand why this isn't working.
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Jul 2, 2013
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
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Feb 11, 2014
I'm trying to end my program when the user presses the enter/return key.
I'm trying to do this with a break statement.
I have two different situations, one when it is a string, and the other one when it is a char.
for (int i = 0; i < 80; ++i)
{
string s;
cin >> s;
if (s == "
")
break;
S.PushStack(s);
}
I'm doing the same thing for char just replacing string with char.
I'm not sure what I am doing wrong but pressing enter does not end the program.
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Mar 28, 2014
I have two date/time structures which I'm populating, but when I populate the second one it sets the same values in the first. This is what I've got so far
tm *FirstDate = gmtime(&now);
tm *SecondDate = gmtime(&now);
cout <<"Enter your first date in the format dd/mm/yyyy" << endl <<">";
getline (cin,tempstring);
[Code] .....
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Feb 16, 2013
i need to display the current time and date in my program and use variable to store each of the time values like
a = 10
b = 29
c = 31
printf(``%d : %d : %d``, a,b,c);
which then give the output as - 10:29:31
How to save the time in variables in C....
i am using C in windows 7 and my complier is Bloodshed Dev C++
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Sep 27, 2014
I have an assignment in which i must create a program which prompts for user input of current and birth date, which will compare said dates and output if its your birthday or not. I've completed a large portion of it, but cannot figure out how to get the user input of month as an integer such a 2 into February.
#include <iostream>
using namespace std;
class DayOfYear {
public:
void input();
[code]....
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Sep 29, 2014
How to write a code that will let me input how many variables I want.
Write a program that will enable you to enter a certain amount of values
Eg. 4
And then add the corresponding integers. Ex.
Choice: 4 12 34 56 78
The sum of the integers is: 180.
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Feb 20, 2013
I need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
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Feb 11, 2013
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
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Mar 23, 2014
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
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Jan 16, 2013
Code:
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main() {
clrscr();
int i=0,flag=1;
cout<<"Enter the password.";
[Code] ....
When I input the password, the Backspace and the Enter keys are not working as they should. Also, I want to know if I can press enter only once to input the password, not twice.
Compiler is Turbo C++ 3.0 on Windows 7.
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Oct 10, 2013
My program closes after the out even though i've used cin.get():
I want the program to stay open at least until you press enter, even after the whole output.
Code:
#include <iostream>#include <string>
int main()
{
std::cout << "Please enter your name";
std::string name;
std::cin>> name;
// build the message that we intend to write
[Code] .....
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Apr 23, 2014
how can i make a program which allows a user to enter an input for a time interval for example i ask a question and sets the input to be entered within 10 seconds...
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