My program closes after the out even though i've used cin.get():
I want the program to stay open at least until you press enter, even after the whole output.
Code:
#include <iostream>#include <string>
int main()
{
std::cout << "Please enter your name";
std::string name;
std::cin>> name;
// build the message that we intend to write
[Code] .....
Code:
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main() {
clrscr();
int i=0,flag=1;
cout<<"Enter the password.";
[Code] ....
When I input the password, the Backspace and the Enter keys are not working as they should. Also, I want to know if I can press enter only once to input the password, not twice.
Compiler is Turbo C++ 3.0 on Windows 7.
How can i jump from textBox to next texBox when i press enterKey in c# , what i the event for that .....
View 2 Replies View RelatedWhen the user gives no input, they have to press enter twice before "Done." is printed.
cout << "What do you want the name of your page to be? ";
std::getline(cin, pageTitle);
if (cin.get() == '
')
pageTitle = "Welcome to Website.";
cout << "Done.
";
Is there a way to print "Done." after pressing enter once?
I'm stuck because I can make the calculator just find but the user will have to press enter after every number, what is s solution to this?
#include <iostream>
#include <string>
using namespace std;
int a = 1, b, c;
string symbol;
int multiplyFunction();
[Code] .....
So I have been assigned a program that counts keystrokes, alphabetical characters, and vowels. I have the program working as desired but I just can't figure out how to make it end upon ONLY the "return" key being pressed.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main ( void ) {
[Code] .....
Code:
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<string.h>
int main(void) {
int i;
char *str;
int len = 1;
[Code]...
I have been trying to make a small program that I will be using in a larger program that will make the user press space to see the next line of output.
Not exactly sure what I'm doing wrong, but I'm pretty sure that I need to put the space that the user would enter into an output file, and the read the input file
It runs, but it doesn't allow me press space before showing the next line.
I added a getline(cin, charVar) before, but I got a whole bunch of errors.
#include <iostream>
#include <string>
#include <cctype>
#include <cstdlib>
#include <fstream>
using namespace std;
// function for dialouge
[Code] ....
Write a program that computes and displays the charges for a patient's hospital stay. First, the program should ask if the patient was admitted as an in-patient or an out-patient. If the patient was an in-patient the following data should be entered:
-Number of Days spent in a Hospital
-The daily rate
-Charges for the hospital services(lab test, etc)
-Hospital medication charges
If the the patient was an out-patient the following data should be entered:
-Charges for Hospital services(lab test, etc)
-Hospital medication charges
The program should use two functions to calculate the total charges. One of the functions should accept arguments for the in patient data, while the other function accepts arguments for out-patient data. Both functions should return the total charges.
I dont know why but the result always gives me 0??? This is what I have.
#include<iostream>
using namespace std;
double in_patient(int Numdays, double dailyRate, double Charge_hospServices, double HospMed_Charge);
double out_patient(double Outcharge_Service, double OuthospMed_Charge);
int main() {
double dailyRate, Charge_hospServices,HospMed_Charge,Outcharge_Service,OuthospMed_Charge;
[Code] .....
I am altering this program to include some alterations for a class. When I run it with start without debugging, it just skips to press any key to continue. It will not display the cout << "Volume of box1 = " <<boxVolume1.
#include "stdafx.h"
#include <iostream>
using std::cout;
using std::endl;
class CBox {
public:
double m_Length;
double m_Width;
[Code] .....
I have a problem where I need to add the ability to input numbers into a calculator program through either a form button press or keyboard press. I have the button press working fine though I can't seem to get the program to start with the cursor active in the textbox for keyboard input. I've use this.ActiveControl = result; "result" being the textbox. Though the issue here is the program starts off with the cursor active but only for the first instance of keyboard inputs.
Perhaps its the way I wrote the program but is there a way I can achieve this? I found a way to write this calc by having a single event for all button presses, opposed from an event for 1-9. Not sure if this is a good approach but here is some of the code.
private double num = 0;
private string calculate;
bool pressed = false;
private void button_Click(object sender, EventArgs e) {
if ((result.Text == "0")||(pressed == true)) {
[Code] ....
I would like to know how to press a key as if it had been pressed on the keyboard in a program. I would also like to know how to read input from a xbox 360 controller. I want to know how to do this so that I can add joystick support to a few mmos that I play that do not already have it.
BTW I am using C 99
How to fix this when i run the program and enter my name then output my name in vertical position using the for loop and press enter the program do not stop
#include<stdio.h>
#include<conio.h>
#include<dos.h>
main() {
char name,n;
clrscr();
printf("Enter Your Name:");
scanf("%c",&name);
[Code] ....
My program accepts strings, places them in a vector and then "bleeps!" out words of my choosing, in this case, "broccoli". But I'm having trouble keeping the output window open even with my Keep_window_open() implementation.
#include "iostream"
#include "string"
#include "vector"
#include "algorithm"
#include "cmath"
using namespace std;
[code]....
/* Program is to let the user enter a string and will output the sting in all uppercase letters. */
#include <cctype>
#include <iostream>
#include <string>
using namespace std;
char str1[80];
[Code] ....
I am trying to get the cin.get working where the user is allowed to enter an 80 character string and how to do that.
So I've been trying to write a good update loop,
if (SDL_GetTicks() - startTime >= 1000) {
fps = loops;
startTime = SDL_GetTicks();
loops = 0;
[Code] ....
It's based off of deWitter's 4th game loop. [URL]....
However, there's one major flaw. If the update() function takes a long time to execute, the timer slows down, a "second" doesn't last 1000 milliseconds, and the fps counter spits out numbers like 100 and 120 when the limit should be 60. Is there a way to make a timer that always runs with constant speed no matter how long the update function takes?
I have a function that rotates a vector 90 degrees. Only problem is, i never get negative values. For some strange reason, no matter what i do, the value of x is positive. And even if the x is negative. Once i put it into direction (struct with 2 values x and y) it turns again to positive. Im using VSC++2013 ultimate. At first direction was SDL_Point, so i thought it was SDL problem, but now it seems its something else.
if (c == '-') {
int x = direction.y;
x *= -1;
int y = direction.x;
direction = { x, y };
}
I am writing a game that is 2 to 4 players. i am wondering how to ask how many players, and make the score stay with each player. it is a rip off of zombie dice, this is what i have so far the playerScore array is to hold the score for each player and the turn array is hold hold the values that they rolled that turn, i also dont know how to clear out the turn array when it goes to the next player.
#include <iostream>
#include <cstdlib>
#include <cmath>
#include <ctime>
using namespace std;
int main() {
int playerScore[4];
[Code] ....
I am trying to make a program that will allow a user to enter their name, from this point, three options should be present for the user to choose, then from that point, two more options should be present. I have if else statements in a switch case and I get the "undeclared" error for the a in the first " if(specificage == a) ".
NOTE: I use Code::Blocks.
Here is the code:
Code:
#include <stdio.h>
#include <string.h>
int main(){
char name[50];
char ageclass[50];
char specificage[50];
[Code] ....
I'm trying to end my program when the user presses the enter/return key.
I'm trying to do this with a break statement.
I have two different situations, one when it is a string, and the other one when it is a char.
for (int i = 0; i < 80; ++i)
{
string s;
cin >> s;
if (s == "
")
break;
S.PushStack(s);
}
I'm doing the same thing for char just replacing string with char.
I'm not sure what I am doing wrong but pressing enter does not end the program.
How to write a code that will let me input how many variables I want.
Write a program that will enable you to enter a certain amount of values
Eg. 4
And then add the corresponding integers. Ex.
Choice: 4 12 34 56 78
The sum of the integers is: 180.
I need a program in c++ that will enter a limit of the loop. using nested for loop with a limit of 3 loops only.
like this !
for (){
for (){
for (){
cout
}
}
}
Sample output:
Enter a number : 3 [enter]
1 2 3
4 5 6
7 8 9
2 3 4
5 6 7
8 9 10
3 4 5
6 7 8
9 10 11
I am wondering how can i open a .exe file with my c++ program. What is the source code?
View 6 Replies View RelatedI have a batch of .pdf files (~1000) with names 001.pdf 002.pdf ...etc. Still pretty new to C, but would it be possible to write a program that would open a PDF, prompt a new name from user, and when entered, close the .pdf and open the next one in the list?
View 14 Replies View RelatedI am creating a console based application which needs to be dual tasking, which prompts me to share a single console for the GUI console based and inputs from the user.
I want to know if there is a mechanism through I can open more than one command prompt so that I would use efficiently both of them.
Furthermore, I would need also to know how to control on which to print and on which not to be printed.
Is there such a thing?
I am using Visual Studio 2012 Ultimate on a Windows 8.1 Professional PC.
I am fairly new to programming and I am writing a small POS system which in the background creates a receipt. I guess the relevant code would be this:
#include <stdio.h>
int main() {
FILE *receipt;
receipt = fopen("receipt.txt", "w");
fprintf(receipt, "Coffee Bar
[Code] ....
Of course the last bit wont be running for you, since the variables are missing. My question now is, that I like to open this file in a text editor. The file should be opened with a command withing the code. Is that possible at all? As you might can tell the receipt should pop up after the program ran and the user should be able to print it afterwards.