C++ :: Calculate User Birthday In Months / Days / Hours And Minutes From Today Date
Jul 24, 2014
The problem is that I need to figure out the user's birthday in months, days, hours, and minutes from today's date.
Here's what I have so far.
#include<iostream>
#include<cmath>
#include<ctime>
using namespace std;
int main() {
int todayDay, todayMonth, todayYear;
int birthDay, birthMonth, birthYear;
[Code] ....
I haven't initialized all the variables, yet. And it's very unfinished. I need to figure out how to convert years from the age into months only. And I need to figure out how to calculate the hours, seconds, and minutes.
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Nov 23, 2012
I have an extra credit project where I'm supposed to calculate an approximate the user's age based on the current date and their birthday. My problem is that I am not getting the proper date and time. C++ keeps giving me some random date. I looked up c++ time format on the internet because this is extra credit and not in my book.
I am currently using dev C++ 4.9.9.2. Here is my current code :
// included libraries
#include <cstdlib>
#include <iostream>
#include <iomanip>
#include <time.h>
#define cls system("cls")
#define pauseOutput system("pause")
void printM(int x);
void age(int m, int d, int y, int &yearAge, int &monthAge, int &dayAge);
[Code] ....
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Oct 23, 2014
I am currently working on a lab for my intro to programming class and the lab is asking for a long distance call calculator. Based on the times that you start your rate will change. If the call starts from 00:00 to 07:59, Rate = $0.07. If the call starts from 08:00 to 18.59, Rate = $0.12. Lastly if the call starts from 19:00 to 23:59, your rate is $0.28.
Then on the output you must show the start time, end time, rate, and total cost of the call.
My confusion is on the end part of the code (the output).
I know you have to use the % operator to convert minutes to hours, but I don't completely understand it which is why I am here. How does the modulus do that? And how will it go over to the next hour if the call starts at 1:35 and ends after 30 minutes (2:05)?
Here is what I have so far.
#include <iostream>
#include <string>
using namespace std;
int main() {
float callStart, minutes;
double cost;
char choice('Y');
string rate;
[Code] ....
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Feb 20, 2013
I have to write a c++ program with my own function which consists of two parameters (day, month). Function have to return number of days since the begining of this year. Using this function i have to find out how many days are left till birthday (or how many days have passed since last birthday)
This is how far i am:
Code:
#include <iostream>
using namespace std;
int cikDienu(int diena, int menesis);
int main()
[Code] ....
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Apr 2, 2013
I want to create a program where you enter today's date, in the following format: 02/04/2013. As well as your birth date in the following format: 27/09/1994. After doing that I want to assign the day, month and year of the present date, as well as the day, month and year of the birth date in to their own variables (for example, Day, Month, Year), and then calculate your age.
I have tried doing this with cin.get(), but this method is way too long, and I'm looking for a shorter method
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Feb 22, 2014
Create a class to store a value that represents number of hours worked and number of days worked. Must ensure that the two representations are always consistent. I have to create 2 files, I'm pretty sure: a .cpp and a .h
This is what I have so far for my .h file (I know it's NOT functional...yet):
#include <iostream>
using namespace std;
class NumDays {
private:
double hours;
double days;
[Code] ...
I don't know how to start / create this .cpp file to define the variables.
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Jul 10, 2013
I want to convert seconds into hours, min and seconds. I was able to test it with a small equation turning seconds into hours but now it returns zeros for every entry.
Code:
#include <stdio.h>
void secCount(int *seconds, int *hours, int *min, int *sec);
int main(int argc, const char * argv[]) {
int sec=0, hours=0, min=0, seconds =0;
[Code] .....
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Mar 22, 2014
How do I read a date from a file to determine different of days
For example my date.txt contains:
1 23/01/2012 05/02/2012
Currently my code is:
#include<iostream>
#include<fstream>
using namespace std;
[Code].....
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Mar 21, 2014
How do I read a date from a file to determine different of days
For example my date.txt contains:
1 23/01/2012 05/02/2012
Currently my code is:
#include<iostream>
#include<fstream>
using namespace std;
class Date {
public:
int day;
int month;
int year;
int total_day;
Date();
[Code] ....
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May 20, 2012
I have a file, 'date-list.txt' which has date in it. For example , 20 May 2012 .
Now I want to compare this date with current system date and show the difference in days .
How can i compare dates and shows difference in days in C++.?
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Nov 11, 2014
I need to make a program to calculate the business days (Monday-Friday) in a year in C. As example:
Input
2026
Output
261
I need to consider that the year could be a leap year and that every year can start with a different day. My Problem is that i dont know how to implement the right number of business days in C. I wrote down the business days in Excel for 2010-2040. I cant see any system behind it, some years have 261 business days, some have 260 or 262 but in no order.
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Oct 8, 2013
Write a program in C++ that calculates the amount to be paid to an employee based on the hours worked and rate per hour. A user will enter hours worked and rate per hour for an employee. Your program should have a function payCheck that calculates and returns the amount to be paid. The formula for calculating the salary amount is as follows: for the first 40 hours, the rate is the given rate (the rate that a user has entered); for hours over 40, the rate is 1.5 times the given rate.
I had write my own coding, but it keeps error. it is okay. But i still don't think i could share here? Still running... I will update my coding for you alls to check for any syntax or logic error. The problem is i need to calculate if the employee work for more than 40 hours which 1.5 times.
Code:
#include <stdlib.h>
#include <stddef.h>
#include <string.h>
#include <stdio.h>
#include <iostream.h>
using namespace std;
int main(void) {
char *empname, *test, *final_output;
[Code] .....
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Mar 24, 2014
I have an assignment to write a program that will calculate the number of days between two dates (including leap years). We have to read the data from a file and in my current input file I have:
1 1 2000 1 5 2004
5 2 2005 2 5 2009
1 15 1998 1 15 2001
for testing purposes. When I run the program the console runs continuously spouting out "The days between your two dates are 1097." Which would be the correct output for the last set of dates entered, but I need to find out where I've messed up in my main.
#include <iostream>
#include <fstream>
using namespace std;
bool isLeap(int x) {
if (x % 400 == 0) {
[Code] .....
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Mar 26, 2013
I am a beginner trying to write a program that would state a user's chinese zodiac and horoscope sign after inputing his or her birthday. I have been, however, having trouble getting the program to run correctly.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#define CAPRICORN "G"
#define AQUARIUS "W"
#define PISCES "F"
[Code] ......
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Oct 22, 2013
I have to write a program for class in which users will be inputting:
start time = startTime
number of minutes = callDuration
so first off, teacher wants us to input time as a floating point number such as 09.00
How do I validate the time so that users cant input i.e. 09.61 for every hour? In other words, so the user cant input minutes 60-99 for every hour.
then, when calculating:
endTime = startTime + callDuration
how would I make endTime display a correct time in such a situation: endTime = 09.45 + 00.30
so that it displays 10.15 not 09.75
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Oct 26, 2014
So I have a programming assignment which is for getting a user input in the format of m/d/yyyy. This is stored as d/m/yyyy. I have been able to code all the rest of the requirements of the program but the thing that is giving me trouble is this. The year is allowed to go from 1-3000. The format of the displayed date is:
a zero-filled, two-digit day number, a dash, full name of month, a dash, zero-filled, four-digit year.
I am able to use a switch statement in order to get my name of the month. What I am struggling to figure out is the whole zero filled two digit day and zero filled four digit year. From the way the input is store it appears to me that it will be stored as yyyy which means if you were to enter 0001 for year 1 then it should output it as that (this is an assumption based on format). What I don't get is that the day is entered and stored as d which means if you put in 12 how would it be stored. However if you put in 6 to print the output I would need to add a zero and I dont know how to do that either.
Here is the code for getting the input. The function must stay formated this way as per the instructor. The / is stored but ignored hence the char for second and fourth since / is a char
Code:
void getDate (int& day, int& month, int& year){
char second;
char fourth;
cout << "Please enter a date in the format of m/d/yyyy" << endl;
cin >> month >> second >> day >>fourth >> year;
}
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Apr 12, 2012
Some example to validate date accepted by user in variable as follows:
int day;
int month;
int year;
It must validate entered details are correct or not ans
It must check that date is more than System date or not
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Jan 20, 2013
I am writing a C++ program which takes date & time input from the user. This is then parsed into a struct such as:
struct time
{
short year;
short month;
short day;
short hour;
short min;
};
My question is: how can I convert such a struct into a time_t object, which is an unsigned long giving the time as the number of seconds elapsed since the epoch Jan 1st 1970, 00:00, as set out in time.h.
I am wondering if this can be achieved using the standard library, or whether I just need to write a function to perform the appropriate arithmetic.
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Mar 22, 2013
I'm having a problem with my homework. The task is to write a program that will take time and date typed by user, and increase it by 1 minute. I should write 3 functions - first calls second function that updates time and calls third function, if time is 00:00.Time update works, but date update does not.My whole written code:
Code:
#include<stdio.h>
struct DateAndTime {
struct date {
int day;
int month;
int year;
[code]....
I should check if inputs are numbers only, so I tried including isdigit function from ctype.h library, but that didn't work either, after I was trying it for a good hour or so, but I kinda rage quit that...
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Dec 4, 2014
I don't know how to ask the user to enter the date in this format (DD/MM/YY) and ISBN number with hyphens.
After user enter date and ISBN number, it should look like this:
Date: 5/24/12
ISBN: 0-000-12345-0
#include <iostream>
#include <string>
using namespace std;
int main() {
string date;//MM/DD/YY Format
[Code] ....
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Sep 27, 2014
I have an assignment in which i must create a program which prompts for user input of current and birth date, which will compare said dates and output if its your birthday or not. I've completed a large portion of it, but cannot figure out how to get the user input of month as an integer such a 2 into February.
#include <iostream>
using namespace std;
class DayOfYear {
public:
void input();
[code]....
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May 18, 2013
How can i implement a simulator that computes the populations for a given number of months for all sectors.
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May 5, 2014
I have to print out which months have the lowest and highest amount of rainfall. I know how to find the lowest and highest value but how do I match them with there month?
#include <iostream>
using namespace std;
int main() {
const int rainfall = 12;
double months[rainfall];
int count;
[Code] .....
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Mar 29, 2013
I need my code to display Month but it seems my code is skipping month's and not displaying 1, 2 3. It's going 1 , 3 ,5 and so on. This is the code i have for it
Code:
int month = 1;
And later on the code i have month++ That's my first mistake and i'm not sure how to possibly fix it. My second mistake is my Interest Paid output. This is the code i have for it
Code:
interestPaid = loanBalance*i;
This is on the while loop, but i'm not sure why it's not displaying the correct amount. It should display for month 1 = 500.00 , Month 2 = 498.28 and Month 3 = 496.55 and so on... However my code display's something close to it, but not that. i is my monthly interest rate. My code for it seems to be fine. If i can fix this two things i'll be able to finish the project. This is my entire code, how i can fix it so that my month is displayed in 1, 2, 3, etc.... and not 1, 3, 5, etc... And why my interest is not displaying what my professor has on his output screen (i provided the first three months on top in bold) If i can fix those things i'll have the rest. Here's my entire code
#include <iostream>
#include <iomanip>
using namespace std;
int main ( ) {
int month = 1;
// Holds the user's amount of loan.
double loanAmount;
// Holds the user's interest rate.
double i;
[Code] ....
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Oct 11, 2012
i'm making a program that, given a person's birthdate or any other date, will display the day of the week of the person was born.
There is this part where it says "use a switch statement to make this calculation, If desired month is 12, add the number of days for November, if desired month is 11 add the number of days for october....
So it's suppose to start with "case 12 :...
I can't figure out what to write for the statement....
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Oct 16, 2014
Write a program that maintains a database containing data, such as name and birthday, about your friends and relatives. You should be able to enter, remove, modify, or search this data. Initially, you can assume that the names are unique. The program should be able to save the data in a fi le for use later.
Design a class to represent the database and another class to represent the people. Use a binary search tree of people as a data member of the database class. You can enhance this problem by adding an operation that lists everyone who satisfies a given criterion.
For example, you could list people born in a given month. You should also be able to list everyone in the database.
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