C :: Program To Convert A Number Into A More Readable Format
Oct 14, 2014
I wanted to write a program to convert a number into a more readable format. It's like, if the input enters the number as 2361263 the output should be like 2,361,263. I went about this problem like extraction the number first and then if the count was equal to multiple of three i'd print ',' instead of the number.
But initially when i wrote the code for extracting a single digit from the number
Code:
#include<stdio.h>
void main() {
unsigned long long num=pow(2,50);
int count=0;
while(num!=0) {
int last_digit;
[Code]....
I know that I'd lose the number when i finish printing it, but still I only end up printing the entire number in reverse order.
As in if the input is 1234 the output is 4,321 which is not what i want.
One way of overcoming this problem is to store the values in an array and then reading then back from the end. But i wanted to know if there is a better solution than this? To extract the digits from the number in the same order as it is in the number
a few pointers in building an assembler in C for a 68hc11 micro controller I'm struggling on a way to convert the assembly language in a txt file to s19 format.
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
I have almost a hundred names in a text file that I want to convert to email addresses and save to another file. I seem to have it working, but it doesn't print the full names in the email prefix. The output I'm looking for is Doe_John@livebrandm, but I'm only getting D_J@livebrandm. I'm not sure what I should specifically be reading up on that applies to this directly.
these function do the same of the sprintf() function. but instead we use a variable for add the result, i want to return the result. when i use it:
string f; f=ToString("hello world"); gives me several errors: "error: crosses initialization of 'std::string f'" "error: jump to case label [-fpermissive]"
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111 Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010 Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102 Number entered is not a binary number
#include <iostream> using namespace std; int main() { int num;
I want to create a program where you enter today's date, in the following format: 02/04/2013. As well as your birth date in the following format: 27/09/1994. After doing that I want to assign the day, month and year of the present date, as well as the day, month and year of the birth date in to their own variables (for example, Day, Month, Year), and then calculate your age.
I have tried doing this with cin.get(), but this method is way too long, and I'm looking for a shorter method
using namespace std; void Conversion (int n); int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
How do you convert a number float in a range of -10.0f to 17.0f to a eqivalent number in the range of 0.0f to 1.0f?The code does not work well. floaty is the float to change.
//change range to 0..1 diamond[x][y] = (floaty - minY) / (maxY - minY);
#include "stdio.h" #include <stdarg.h> #include <math.h> // Main Function int main(void){ int number; printf(" Please enter a number from 1-10? "); scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
i want to convert the Digits in words.I have already a code but in my code the value is coming like for ex:-540000(Five hundered and Fourty Thousand ).but i want Five Lakh and Fourty thousand.
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){ char* binNum = decToBin(25); int i = 0; while(binNum != NULL){
What I'm trying to do is have the user input a hex number this number will then be converted to a char and displayed to the monitor this will continue until an EOF is encountered.I have the opposite of this code done which converts a char to a hex number. The problem I'm running into is how do i get a hex number from the user I used getchar() for the char2hex program. Is there any similar function for hex numbers?
this is the code for the char2hex program
#include <stdio.h> int main(void) { char myChar; int counter = 0; while(EOF != (myChar = getchar())) { if (myChar == '')
[Code] .....
This is what i want to the program to do except it would do this continuously
#include<stdio.h> int main() { char myChar; printf("Enter any hex number: "); scanf("%x",&myChar); printf("Equivalent Char is: %c",myChar); system("pause"); return 0; }
