I receive a negative number but in big endian order. ntohl seems work for unsigned only.
Is there a method for me to translate it back to the original negative number from big endian?
Having error . I multiplied 0 by -4 and my result is -0 instead of 0. I tried to change the data type put It won't work. This is my code:
#include <iostream>
int main () {
double b, c;
std::cout<<"b: ";
std::cin>>b;
std::cout<<"c: ";
std::cin>>c;
std::cout<<b*c<<std::endl;
return 0;
}
I nead to define an a negative number a normal posetive number i defined like #define RSSI_UP 1 can i write #define RSSI_DOWN -1???
View 2 Replies View RelatedThe code on lines 44-53 is suppose to display a message when the user enter a negative number, however, when a correct positive number is entered the message is display again.
#include<iostream>
#include<cctype>
using namespace std;
int main() {
char carType;
int A, B, C;
[Code] ....
I am getting strings from an HTTP request that will have hex values and I must convert those strings to a signed decimal.
//typical string inside response: //0E1D052BFBB711C1002C0042007A014DFE44022B270F7FFF8000000000000000
//every 4 characters above are a signed decimal value
for (a = 0; a <= 63; a+=4){
sprintf(vval,"0X%c%c%c%c",response[a],response[a+1],response[a+2],response[a+3]);
ds = strtol(vval, NULL, 16);
sprintf(vval,"%d",ds);
}
The problem is I never see a negative number. Decoding 0x8000 gives me 32768 but not -32768.
In this exercise:The C Programming Language Exercise 3-4..It states the following: "In a two's complement number representation, our version of itoa does not handle the largest negative number, that is, the value of n equal to -(2 to the power (wordsize - 1)) ."
A char is one byte (255 bits). The range of an 8 bit variable using a two's complement representation is -128 to 127. Therefore -128 is the largest negative value. The statement in book suggests that the itoa function will not output -128 if we pass -128 as a parameter, because in itoa when we try to convert -128 to positive -128, the inverse of -128 is -128. However, I just ran this code in my computer and it successfully outputted -128.
Code:
#include <stdio.h>
#include <string.h>
#define SIZE 10
void reverse(char s[])
{
int c, i, j;
}
[code].....
My program uses a while loop to eventually get to an error of zero and a root of sqrt(3). I'm not understand why after the third iteration the program fails to compute a new x value. I'm using Visual Studio 2013. The code tag instructions were dubious.
Code:
#include <stdio.h>
#include <math.h>
main() {
/*This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots.*/
printf("This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots. Enter your estimate of the root.
");
float x,y,z;
int num;
num = 0;
[Code]...
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{
int vectorLength = 10;
vector<int> bothSigns(vectorLength);
cout << " Input vector: ";
for (int i = 0; i < vectorLength; i = i + 1)
{ bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream>
using namespace std;
int Max(int x);
int main() {
int x;
[Code] ....
Why my program is returning a negative number at the end...attached is the program:
/*Write a recursive function recursiveMinimum that takes an integer array and the array size as arguments and returns the smallest element of the array. The function should stop processing and return when it receives an array of 1 element.*/
#include <stdio.h>
#include <time.h>
#include <iostream>
using namespace std;
float recursiveMinimum (int ARRAY[], int n);
[Code] .....
So I tried creating a test code for reading a negative number and positive number but whenever I enter a negative number it read it as being positive.
#include <stdio.h>
#include <iostream>
#include <iomanip>
[Code].....
PS: I am using char over int because the program that I am testing for requires me to use 8 bit variable.
here's one more thing id like to do to make the input even better able to handle user error, but im not sure if its possible or at least easy. I need the function to return a large positive number. As of right now, it can handle users entering characters, but what if the user enters a negative number? is there a way to check to see if what is coming in is negative before the sign gets lost in conversion to unsigned"ness"?
Code:
unsigned long getNum(char prompt[80])
{
unsigned long darts;
printf("%s", prompt);
while((scanf("%lu", &darts)) != 1)
{
[code]....
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
#include <iostream>
using namespace std;
int main()
{
int num;
[code]....
Here's the part of the codes where I tried to use boolean expression:
Code:
#include <iostream>
using namespace std;
int main() {
int num;
cout << "8-bit Binary Number=";
cin >> num;
[Code] .....
How can I get started with the body?
Here's the part of the codes where I tried to use boolean expression:
#include <iostream>
using namespace std;
int main()
[Code].....
May I know that how can I get started with the body?
I want to convert image to number.
View 12 Replies View RelatedHow to convert e.g. number 75 to base 4 representation? The result should be 1023. I plan to use uint32_t
x = a3.43 + a2.42 + a1.41 + a0.40 = a3.64 + a2.16 + a1.4 + a0
I had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
#include <iostream>#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
How do you convert a number float in a range of -10.0f to 17.0f to a eqivalent number in the range of 0.0f to 1.0f?The code does not work well. floaty is the float to change.
//change range to 0..1
diamond[x][y] = (floaty - minY) / (maxY - minY);
#include "stdio.h"
#include <stdarg.h>
#include <math.h>
// Main Function
int main(void){
int number;
printf(" Please enter a number from 1-10? ");
scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
i want to convert the Digits in words.I have already a code but in my code the value is coming like for ex:-540000(Five hundered and Fourty Thousand ).but i want Five Lakh and Fourty thousand.
View 4 Replies View RelatedI wanted to write a program to convert a number into a more readable format. It's like, if the input enters the number as 2361263 the output should be like 2,361,263. I went about this problem like extraction the number first and then if the count was equal to multiple of three i'd print ',' instead of the number.
But initially when i wrote the code for extracting a single digit from the number
Code:
#include<stdio.h>
void main() {
unsigned long long num=pow(2,50);
int count=0;
while(num!=0) {
int last_digit;
[Code]....
I know that I'd lose the number when i finish printing it, but still I only end up printing the entire number in reverse order.
As in if the input is 1234 the output is 4,321 which is not what i want.
One way of overcoming this problem is to store the values in an array and then reading then back from the end. But i wanted to know if there is a better solution than this? To extract the digits from the number in the same order as it is in the number
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
#include <iostream>
#include <math.h>
using namespace std;
void main() {
double numOfDig, num, newNum;
[Code] ....
I want to convert a decimal number to binary and store it in a string so that I can use that binary output for later computation. Here is what I did
Code:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void main()
[Code] ....
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){
char* binNum = decToBin(25);
int i = 0;
while(binNum != NULL){
[Code].....
What I'm trying to do is have the user input a hex number this number will then be converted to a char and displayed to the monitor this will continue until an EOF is encountered.I have the opposite of this code done which converts a char to a hex number. The problem I'm running into is how do i get a hex number from the user I used getchar() for the char2hex program. Is there any similar function for hex numbers?
this is the code for the char2hex program
#include <stdio.h>
int main(void) {
char myChar;
int counter = 0;
while(EOF != (myChar = getchar())) {
if (myChar == '')
[Code] .....
This is what i want to the program to do except it would do this continuously
#include<stdio.h>
int main() {
char myChar;
printf("Enter any hex number: ");
scanf("%x",&myChar);
printf("Equivalent Char is: %c",myChar);
system("pause");
return 0;
}
