The code on lines 44-53 is suppose to display a message when the user enter a negative number, however, when a correct positive number is entered the message is display again.
#include<iostream>
#include<cctype>
using namespace std;
int main() {
char carType;
int A, B, C;
I am getting strings from an HTTP request that will have hex values and I must convert those strings to a signed decimal.
//typical string inside response: //0E1D052BFBB711C1002C0042007A014DFE44022B270F7FFF8000000000000000 //every 4 characters above are a signed decimal value for (a = 0; a <= 63; a+=4){ sprintf(vval,"0X%c%c%c%c",response[a],response[a+1],response[a+2],response[a+3]); ds = strtol(vval, NULL, 16); sprintf(vval,"%d",ds); }
The problem is I never see a negative number. Decoding 0x8000 gives me 32768 but not -32768.
In this exercise:The C Programming Language Exercise 3-4..It states the following: "In a two's complement number representation, our version of itoa does not handle the largest negative number, that is, the value of n equal to -(2 to the power (wordsize - 1)) ."
A char is one byte (255 bits). The range of an 8 bit variable using a two's complement representation is -128 to 127. Therefore -128 is the largest negative value. The statement in book suggests that the itoa function will not output -128 if we pass -128 as a parameter, because in itoa when we try to convert -128 to positive -128, the inverse of -128 is -128. However, I just ran this code in my computer and it successfully outputted -128.
Code:
#include <stdio.h> #include <string.h> #define SIZE 10 void reverse(char s[]) { int c, i, j; }
My program uses a while loop to eventually get to an error of zero and a root of sqrt(3). I'm not understand why after the third iteration the program fails to compute a new x value. I'm using Visual Studio 2013. The code tag instructions were dubious.
Code:
#include <stdio.h> #include <math.h> main() { /*This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots.*/ printf("This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots. Enter your estimate of the root. "); float x,y,z; int num; num = 0;
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{ int vectorLength = 10; vector<int> bothSigns(vectorLength); cout << " Input vector: "; for (int i = 0; i < vectorLength; i = i + 1) { bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream> using namespace std; int Max(int x); int main() { int x;
Why my program is returning a negative number at the end...attached is the program:
/*Write a recursive function recursiveMinimum that takes an integer array and the array size as arguments and returns the smallest element of the array. The function should stop processing and return when it receives an array of 1 element.*/
#include <stdio.h> #include <time.h> #include <iostream> using namespace std; float recursiveMinimum (int ARRAY[], int n);
here's one more thing id like to do to make the input even better able to handle user error, but im not sure if its possible or at least easy. I need the function to return a large positive number. As of right now, it can handle users entering characters, but what if the user enters a negative number? is there a way to check to see if what is coming in is negative before the sign gets lost in conversion to unsigned"ness"?
Code: unsigned long getNum(char prompt[80]) { unsigned long darts; printf("%s", prompt); while((scanf("%lu", &darts)) != 1) { [code]....
I can have at most 3 structs in array, but it could be 0,1,2 or 3 structs in array. I am trying to avoid dynamic memory allocation. I initialize sensors to 3 to reserve space for them in memory, since there may be at most 3 elements in the array. But I am testing a condition where there will only be 2 elements:
Code:
#include <stdio.h>#include <stdlib.h> #include <string.h> typedef struct { unsigned long long int address; float current; unsigned char pressure_units; } sensor;
[Code]...
The problem is even though there are only 2 sensors out of 3 in the array, sizeof(sensors)/sizeof(sensors[0]) returns 3. I assume because when it allocates memory for 3, it includes that allocated memory even though it really doesn't contain the struct. How can I figure out how many elements were really inserted into array, not just allocated to array?
I am making a number base conversion program in c++, suppose that user enters an base 2 number and want to convert that number in base 4. when he enter the number (which he wants to be converted), how can i detect that number is belongs to base 2 number system or not.
For example: if user enter 1001011001 , program should continue and convert that number to base 4. and if user enter 1200101 or 1001012 , program should not convert that number and output that this number is not belongs to base 2 number system.
fstream infile1(argv[1]); if(!infile1.is_open()) cout << "Could not open file"; else { char listNum; while(infile1.get(listNum)) cout << listNum; }
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list): 1 is odd 3 is odd 8 is even 9 is odd
But it should print: 138 is even 9 is odd
I tried using getline, but it keeps giving me the errors: invalid conversion from 'void*' to 'char**' invalid conversion from 'char' to 'size_t*' too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]); if(!infile1.is_open()) cout << "Could not open file"; else { char listNum; getline(infile1, listNum); cout << listNum; }
I have to obtain a check number from a datafile and then also get company information also from a datafile.
So my first question is about the:
Code: char outputFilename[]= "out.list"
Is this the name of the output file I'm going to write to? And also the file has to be created before being used...is that line of code creating the file or do i have to create it in notepad?
Whenever I run the program I get no errors yet it doesn't return a value for total it just exits the program. The program is supposed to output the number of the day based on the month day and year and check whether it is a leap year.
#include <iostream> using namespace std; int totaldays(); int days(); int month, day, year; bool leap(); int main() { char dash; cout << "Enter the date in mm-dd-yyyy format to find out what day this is in the year." << endl;
I have a program where the user inputs a line of numbers, and the two highest ones are displayed. It works fine, until negative values are entered at which point it shows 0 as the result.
Code: #include <iostream> using namespace std; int main( ) { int num = 0; int highest = 0;
I have a c program that I partially have working. The problem is basically writing a program that allows the user to input the amount of calories they plan to eat a meal and disperse the calories from top to bottom. My program produces the output in the example if I enter 1050 but the issue I noticed if the number of calories is just enough to cover the burgers I get negatives in the other variables.
For example, if I enter a total amount of calories of 1050, I can eat: Output: 2 burgers @ 770 calories (1050 - 770 = 280 calories remain) 1 bag of pretzles @ 170 calories (280 - 170 = 110 calories remain) 1 pear @ 80 calories (110 - 80 = 30 calories remain) 6 tsp. ketchup @ 30 calories If I input 1050 I get the above output but if I input a different integer such as 2000 this is my output 5 burgers @ 1925 calories 0 bag of pretzles @ 0 calories -1 apple @ -80 calories -35 tsp. ketchup @ -175 calories I can't give the full code since this assignment holds a lot of points and was up all night getting it work.
So I'll provide pseudocode
define all 4 variables burger 385, pretzel 170, pear 80, ketchup 5 print out text How many calories can you eat prompt user input Divide user input into burger How many burgers can bet eaten subtract calories eaten from original user input Divide calories left into pretzel How many bags can bet eaten subtract burger calories from pretzel calories Divide calories left after preztel into pear How many pretzels can be eatn subtract pretzels calories from pear calories Divide calories left over into ketchup how much ketchup can i use show on screen (int total)of burgers @ (int calorie total) calories show on screen (int total)bags of pretzels @ (int calorie total) calories show on screen (int total)pears @ (int calorie total) calories show on screen (int total)teaspoons of ketchup @ (int calorie total) calories
The problem I see is that subtracting the calories from the pear from the left over calories of the pretzel calories leads to a negative. If leftover calories minus 80(pear int) its less then 0 . The calculations from the pear onward to ketchup become incorrect resulting in negative output.
What are positive and negative infinity for different data types in c++, are they represent maximum and minimum limit of a type? or positive infinity is not a finite value.can some explain this positive and negative infinity paradigm