I am getting strings from an HTTP request that will have hex values and I must convert those strings to a signed decimal.
//typical string inside response: //0E1D052BFBB711C1002C0042007A014DFE44022B270F7FFF8000000000000000
//every 4 characters above are a signed decimal value
for (a = 0; a <= 63; a+=4){
sprintf(vval,"0X%c%c%c%c",response[a],response[a+1],response[a+2],response[a+3]);
ds = strtol(vval, NULL, 16);
sprintf(vval,"%d",ds);
}
The problem is I never see a negative number. Decoding 0x8000 gives me 32768 but not -32768.
The code on lines 44-53 is suppose to display a message when the user enter a negative number, however, when a correct positive number is entered the message is display again.
#include<iostream> #include<cctype> using namespace std; int main() { char carType; int A, B, C;
In this exercise:The C Programming Language Exercise 3-4..It states the following: "In a two's complement number representation, our version of itoa does not handle the largest negative number, that is, the value of n equal to -(2 to the power (wordsize - 1)) ."
A char is one byte (255 bits). The range of an 8 bit variable using a two's complement representation is -128 to 127. Therefore -128 is the largest negative value. The statement in book suggests that the itoa function will not output -128 if we pass -128 as a parameter, because in itoa when we try to convert -128 to positive -128, the inverse of -128 is -128. However, I just ran this code in my computer and it successfully outputted -128.
Code:
#include <stdio.h> #include <string.h> #define SIZE 10 void reverse(char s[]) { int c, i, j; }
My program uses a while loop to eventually get to an error of zero and a root of sqrt(3). I'm not understand why after the third iteration the program fails to compute a new x value. I'm using Visual Studio 2013. The code tag instructions were dubious.
Code:
#include <stdio.h> #include <math.h> main() { /*This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots.*/ printf("This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots. Enter your estimate of the root. "); float x,y,z; int num; num = 0;
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{ int vectorLength = 10; vector<int> bothSigns(vectorLength); cout << " Input vector: "; for (int i = 0; i < vectorLength; i = i + 1) { bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream> using namespace std; int Max(int x); int main() { int x;
Why my program is returning a negative number at the end...attached is the program:
/*Write a recursive function recursiveMinimum that takes an integer array and the array size as arguments and returns the smallest element of the array. The function should stop processing and return when it receives an array of 1 element.*/
#include <stdio.h> #include <time.h> #include <iostream> using namespace std; float recursiveMinimum (int ARRAY[], int n);
here's one more thing id like to do to make the input even better able to handle user error, but im not sure if its possible or at least easy. I need the function to return a large positive number. As of right now, it can handle users entering characters, but what if the user enters a negative number? is there a way to check to see if what is coming in is negative before the sign gets lost in conversion to unsigned"ness"?
Code: unsigned long getNum(char prompt[80]) { unsigned long darts; printf("%s", prompt); while((scanf("%lu", &darts)) != 1) { [code]....
i wrote this program to display even number from 100-200. But visual c gives me this error with undeling the "a" in if statement. Error1error C2106: '=' : left operand must be l-value
I have been stuck at a dead end,I got it to display a single asterik for an inputted number, but how would i go about in adding that asterik for each number?
my code is the following
int userinput = int.Parse(InputOutput.GetInput("Enter values into array")); Int32[] inputChoices = new Int32[9]; for (int x = 0; x < inputChoices.Length; x++) { inputChoices[x] = 0; } if (userinput == 1)
If the user puts in a 6. I need the array to display the even number from 0 - 6. Right now what it does is it displays the first six even numbers. Okay as I'm writing this I'm starting to see where my problem might be..
Code: void sumIntegers () { int arr[50]; int i = 0; int num = 0; int sum = 0;
With the loop below, is there a way to display the actual number without the leading zeros (scientific notation) or will it just display 0 since there are so many leading zeros?
num = 1; while (num > 0){ num /= 2; } cout << num;
IF statement. Really new, so this will be simple I'm sure. I'm essentially just trying to roll a 6 and 20 sided die. I want the statement to run "If 20,then display the randomly selected number for 20".
// auto dice roller #include <iostream> #include <string> #include <ctime> #include <cstdlib> using namespace std;
My assignment is "Search Benchmarks: Write a program that has a sorted array of at least 20 integers. It should call a function that uses the linear search algorithm to locate one of the values. The function should keep a count of the number of comparisons it makes until it finds the value. The program then should call a function that uses the binary search algorithm to locate the same value. It should also keep count of the number of comparisons it makes. Display these values on the screen."
I'm unsure how to make it show the number of comparisons it takes to find the value for the binarySearch function. Also, where to put the selectionSort function the teacher said we need. This is what I have...
#include <iostream> using namespace std; int linearSearch(const int a[], int num); int binarySearch(const int a[], int num); void selectionSort(int a[]);
Write a program that will generate, but not display, a three-digit "target" number that has three distinct digits. (Hint: use random number generator.) Then, input a maximum of ten user guesses and for each guess, output the number of hits and matches in the guess. Stop when the user guesses the number or runs out of guesses. For example, if the target is 427, the guess 207 has one hit (7) and one match (2).
Program to read in 15 numbers and display them as follows //each number on a separate line
Code:
# include <stdio.h> # define MY_ARRAY 15 int main(){ int i ; printf("please enter 15 numbers
[Code] ....
Error that i get from compiler: Error E2062 array1.c 14: Invalid indirection in function main() Error E2062 array1.c 19: Invalid indirection in function main() both pointing to the separate "scanf"
What I'm trying to do is have the user input a hex number this number will then be converted to a char and displayed to the monitor this will continue until an EOF is encountered.I have the opposite of this code done which converts a char to a hex number. The problem I'm running into is how do i get a hex number from the user I used getchar() for the char2hex program. Is there any similar function for hex numbers?
this is the code for the char2hex program
#include <stdio.h> int main(void) { char myChar; int counter = 0; while(EOF != (myChar = getchar())) { if (myChar == '')
[Code] .....
This is what i want to the program to do except it would do this continuously
#include<stdio.h> int main() { char myChar; printf("Enter any hex number: "); scanf("%x",&myChar); printf("Equivalent Char is: %c",myChar); system("pause"); return 0; }
I am having one issue with my project. We are making a game of Nim code.I'm 99% done with it, i worked hard on it and i feel like i did a good job, however my project is not displaying the matches i want. For example, it display's the inital number of them 23. But once the first player subtracts a number, it doesn't display matches for player 2, just the number of matches remaining. Then as i keep running the program the same thing happens. This is what it's supposed to output:
"Input/Output sample WELCOME TO NIM ------- -- --- Enter the starting player's name (no spaces)-->John Enter the second player's name (no spaces)-->Mary There are 23 matches. ooooooooooooooooooooooo ||||||||||||||||||||||| Player John please enter the number of matches to remove-->2 There are 21 matches. ooooooooooooooooooooo ||||||||||||||||||||| Player Mary please enter the number of matches to remove-->3 There are 18 matches. oooooooooooooooooo |||||||||||||||||| Player John please enter the number of matches to remove-->1 "
This is entire code.
#include <iostream> #include <string> using namespace std; int main() { // Holds variables.
