C/C++ :: Display Number Of Comparisons Using Binary Search

Apr 23, 2015

My assignment is "Search Benchmarks: Write a program that has a sorted array of at least 20 integers. It should call a function that uses the linear search algorithm to locate one of the values. The function should keep a count of the number of comparisons it makes until it finds the value. The program then should call a function that uses the binary search algorithm to locate the same value. It should also keep count of the number of comparisons it makes. Display these values on the screen."

I'm unsure how to make it show the number of comparisons it takes to find the value for the binarySearch function. Also, where to put the selectionSort function the teacher said we need. This is what I have...

#include <iostream>
using namespace std;
int linearSearch(const int a[], int num);
int binarySearch(const int a[], int num);
void selectionSort(int a[]);

[Code] .....

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I want to display the numbers in a bst but all I get are 0s, what is wrong with my code that is causing this?

#include <iostream>
using namespace std;
class binarySearchTree {
private:
class TreeNode {
friend class binarySearchTree;
int value;

[Code] ....

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Sep 3, 2013

Basically i need to make a number guessing game where user thinks of a numbver from 1 - 100 and the machine will try to guess it in the least number of times. Once it guesses the number it will also say how many tries it took to guess.

My code so far is

#include<iostream>
using namespace std;
const int MAX = 100;
int main() {
char ch;

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[Code] ....

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int main()
{
int FirstPosition;

[Code]....

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Mar 27, 2014

I have to made a programme which will search for given number and it must work in O(log(n)). The problem is that this programme beside finding this number have to find how many times this given number is used in this sequence.

Sequence is from lowest to highest only one possibility to use binary search algorithm

For example when we have squence
-1 -2 3 3 3 3 4 5 6 7 7 8 9 9 9 9 10

The numbers we need to search are
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The answer is
0 , 4 , 2 , 4 , 0 , 0

So we need to find the sum of used number in sequence.

I have written algorithm Code: int start = 0;
int end = sequencelenght - 1;
int mid = 0;
/// Binary serach
while (start<=end) {
int mid=(start+end)/2;
if (sequence[mid]==givennumber) {

[Code] .....

As u see i search for given numer with binary with O(log(n)) but when i have to sum the duplicates the only good way i see is using loop to right and left but this have got log(n) specification (because when sequence would be for example 7 7 7 7 7 7 7 7 7 and given number to search will be 7 this will be O(n) loop).

How would look the most optimal algorithm look for this exercise? I mean O(log(n)) the fastest algorithm....

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Write a program to find the number of comparisons using the binary search and sequential search algorithms

//main.cpp
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int main() {
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[code]....

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#include <iostream>
#include <iomanip> //for setprecision
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[Code].....

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// Session5.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
using namespace std;
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Aug 9, 2012

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Code:
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#include <iostream>
#include <string>
#include <conio.h>
using namespace std;
int main() {
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[Code] ....

Error code..

1>------ Build started: Project: bake, Configuration: Debug Win32 ------
1> bake.cpp
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[Code] .....

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int buscarNumOrdenado (int x [MAX]) //MAX is the define {
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Code:
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[Code].....

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Code:
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[Code] ....

Is this the correct way to call the print function?

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[Code].....

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[Code]...

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Quote

Node<T>* search(T value, Node<T>* subtree)

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Here is my code:

#include <iostream>
using namespace std;
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void selection(int);
int binarySearch(int,int,int);

[code]....

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john doe 3/21/1920 tech support review team 45,000

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john doe 3/21/1920 tech support review team 45,000

I can figure out how to search for a word, but no clue how to get it to then print out the row. This is all I can figure out to do.

ifstream FileSearch;
FileSearch.open("employee");
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