C :: Read 15 Numbers And Display Each Number On Separate Line
Oct 21, 2014
Program to read in 15 numbers and display them as follows //each number on a separate line
Code:
# include <stdio.h>
# define MY_ARRAY 15
int main(){
int i ;
printf("please enter 15 numbers
[Code] ....
Error that i get from compiler:
Error E2062 array1.c 14: Invalid indirection in function main()
Error E2062 array1.c 19: Invalid indirection in function main()
both pointing to the separate "scanf"
I need to write a ANSI program to print out each command line argument on a separate line using a for-loop. also it need to print the name of the executable .so far I have
Code:
#include <stdio.h> int main(int argc, char **argv) { int i; printf("")
i'm reading from a text file which includes a dictionary in UTF8. it has the following structure:
word, bla "bla" translation
so there's a word and a translation seperated by tab. both can include any kind of charactars, excluding tab of course, especially blanks (found one code that claimed to seperate a string at tab, but also did at blank).
how can i seperate one line into two (or more) strings at the tab? i've been searching for a while, but can't find anything useful...
My C programming class wants us to write a program to read integers into an array, sort the numbers and print out the occurrence of each number. I've tried everything that I can think of but the core dump is still occurring.
void countValues ( FILE *inf, int list[], int size ); /* Function prototypes. */ void printFrequencies( const int list[], int size ); int main (void) { int status = EXIT_SUCCESS; /* defaulting status to success. */ FILE *inf = fopen( "numbers.txt", "r" ); /* input data file */
So I have to read from a file, and store the information in separate variables. My problem is that for some of the information I need multiple words, and for others I don't, so I cant simply store 1 word into a variable and store the next in another in so on. To demonstrate what I mean let me give an example.
Dog Cat Blue Bird Snake White Horse
I am able to store "Dog","Cat","Blue","Bird"...etc in variables but I don't know how to make it so I can store "Dog" in one variable, "Cat" in a second variable. and "Blue Bird" in a third variable. "Snake" would be the 4th and "White Horse" would be the fifth. How can I read a file and manipulate the pointer to grab what I need?
I have a set range, say 10 to 100, and I'm trying to separate the numbers evenly into 5 arrays. So there are 90 numbers, how can I assign 10 - 27 to the first array and the next 18 numbers to the next array without creating separate loops for each one?
I'm using fgets which will read a single line at a time, but unlike fgets I don't want it to return the new line char ( ) ?I want to be able to use printf to display the lines next to each other.
I need to read a text file which has various lines containing integers. I need to write those integers separately in a vector. Example, the first line of the text file contains 3 9 8 7 6 so vector[4]=3, vector[3]=9, vector[2]=8 and so on. Next read the second line 4 1 2 3 4 5 and write to another vector vector[5]=4, vector[4]=1...
I tried the code below but it will write from the second line, the whole line in one vector index.
int str; // Temp string to cout << "Read from a file!" << endl; ifstream fin("functions.txt"); // Open it up! string line; // read line count from file; assuming it's the first line getline( fin, line );
I have an external file with one column of data. If I have a counter value let say counter =1, and counter++ and so on. How I can write such a c++ code that if the value of counter and value from the external file are same then generate an action let say cout both values i.e. value of counter and value from external file.
for more information, here is an example:
data in file(in one column): 2 6 8 9 10... value of counter : 1 2 3 4 5 6 7 8 9...
then cout values only if value of counter and value from the file is same.
Here is my code so far, but it does not seem to work;
#include<iostream> #include<fstream> using namespace std; int main() { const int SIZE = 10; //Size declaration of array int hours[SIZE]; //Array declaration
I am reading my file (20GB) line by line using boost like this
PHP Code:
boost::interprocess::file_mapping* fm = new boost::interprocess::file_mapping("E:Mountain.7z", boost::interprocess::read_only); boost::interprocess::mapped_region* mr = new boost::interprocess::mapped_region(*fm, boost::interprocess::read_only);
I working on a big program, and it involves character arrays. What I want my function to do is create a seperate array that consists of the same number of "*" as there are letters in the word from the text file. For example, if the word sarc was up, the function show make ****. This was my attempt at it. I managed to reach this far. I can only fit in one "*". This is part of jumble game program I'm trying to make, and its in C language.
insert Code: void partialWord(char current[]){ int n; int i; n = strlen(current); for (i = 0; i < n; i++){ current[i] = strcpy(current,"*"); } printf("%s ", current); }
I have program that is supposed to read in a story from an input file and separate the words and output the lines on which the word occurs. It needs to read in another input file that has a list of words (1 per line) to ignore. i.e. skip them when running through the story. This is what I have so far, I've changed multiple things trying to get it running....
Im trying to figure out how to print a random number of asterisks on two separate lines at the same time. So every time you press a key it prints a different amount of random number of integers between1 and 10 until one of the lines reaches 70. I have the code to do one line but can't figure out how to do two at once.
#include <stdio.h> #include <time.h> #define MINR 1 #define MAXR 70 #define MINM 1 #define MAXM 10 int main (void)
How can i display a string per line on the .txt i made? There are 2 .txt files, the one has: John Finn Xach The other is: password1 password2 password3 Question is: How can i display, let's say, i input "John" so it will display something like this "John's password is password1" or if i input Xach, "Xach's password is password3" When i use something like :
I am having problems printing "->" on the beginning of each line, im trying to do it as a loop and ending it when the user types "q". also i would like to know how to ignore text from the user when the input begings with a specific character. heres what ive done so far, and not currrently working as expected.
Code: #include <stdio.h> int main (void) { char prompt; printf("~~~ FRACTION CALCULATOR ~~~
#include <stdio.h> /* function that will identify if line is empty or not */ is_empty(char *buffer) { while(isspace(*buffer)) buffer++; if(*buffer==0x00) return 1;
I want to store the address of a customer (with spaces) in a char variable (say cadd). First I tried to use "cin", as we know it reads until it sees any whitespace. So it reads only first word before a white space. So, I used "getline()" function. But when I used it, It didn't wait for the I/P (it skipped it).
I have been working on a program to scanfile and whenever it encounters what the user wanted it prints it, and it is all right less the first line of the file that the program jumps,
