This program with DLL that check number enter in textbox and use RGB for change color
example: if user enter 000 (000:black) changed color automatic textbox to black, and other 111 ....
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Drawing;
[Code]....
How can i jump from textBox to next texBox when i press enterKey in c# , what i the event for that .....
View 2 Replies View RelatedAll I want is to let the user enter a value such as .55 or say, .34 and use that in a calculation.
I cannot get passed the errors.
double theRate;
double totalMileage;
double amountOwed;
private void btnCalculate_Click(object sender, EventArgs e)
[Code] ....
So how do you get numeric input from a user?
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I have a small program to calculate the value of salary. I want to user to be able to enter more than one user using array and finally calculates the average salary of all users.
Here is the code
Code:
#include <iostream>#include <conio.h>
using namespace std;
int main() {
const int months=3;
double net_pay;
string EmpName;
[Code].....
I am trying to write up something to have a user to enter a four digit number. Only four digits, Ex: 0001, 0116, or 9999. There is no getting around the selection 0001 or 0002. I understand if not done correctly, the first three 0's will be ignored.
I've been just playing around with what I have below but I just don't remember how to do it nor can I find a good example online to figure it out. I know it is not correct just typing to try to remember. I am aware that it is gibberish right now, this is just me brainstorming.
int number;
cout<<("Please enter the four digit number(Ex: 0001):
");
cin>> setw(2) >> number;
cout<<)"Please enter four digit date. Two digits for month and two digits for year:
");
cin>> date;
if (number< || number > 30)
cout << "Invalid choice. Try again." << endl;
cin.clear();
Code:
#include<stdio.h>
#include<stdlib.h>
struct node{
int data;
struct node *next;
[Code] .....
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
You enter decimal number into the program and what base you want. The integer part of the decimal is being handled fine, but the decimal is not.
For example, I enter 15.6847 and base 10, which means I'm going from base 10 to base 10. It spits out 68469999999999 for the decimal part. (Do not worry about the first block of numbers. The second block seperated from the first by a space is where the decimal will appear in order.)
#include <iostream>
#include <string>
#include <math.h>
using namespace std;
int baseConverter(int, int, int *, int *);
[Code] ....
I'm stuck because I can make the calculator just find but the user will have to press enter after every number, what is s solution to this?
#include <iostream>
#include <string>
using namespace std;
int a = 1, b, c;
string symbol;
int multiplyFunction();
[Code] .....
Write a program that prompts the user to enter an item#, the program should determine if the item is in the file and print the price of the corresponding item. If the item is not in the file an error message should be printed.
All I have so far is
string item_no=0;
cout<<"Enter a item#";
getline(cin,item_no);
if stream openData;
I need to finish the rest in pseudo code
Assignment:
1. Choose what to enter NUMBER or LETTER.
2. Choose type of sorting ASCENDING or DESCENDING.
#include<iostream.h>
#include<conio.h>
main() {
int x,y,z;
cout<<"choose Number or letter
1.number
2.Letter";
[Code] ....
I don't know how to ask the user to enter the date in this format (DD/MM/YY) and ISBN number with hyphens.
After user enter date and ISBN number, it should look like this:
Date: 5/24/12
ISBN: 0-000-12345-0
#include <iostream>
#include <string>
using namespace std;
int main() {
string date;//MM/DD/YY Format
[Code] ....
The code on lines 44-53 is suppose to display a message when the user enter a negative number, however, when a correct positive number is entered the message is display again.
#include<iostream>
#include<cctype>
using namespace std;
int main() {
char carType;
int A, B, C;
[Code] ....
I could not find the mistake in this program....
Code:
//cpp program to check whether a number is palindrome or not
#include<iostream.h>
#include<conio.h>
//the class
class palindrome
[Code] ....
I can have at most 3 structs in array, but it could be 0,1,2 or 3 structs in array. I am trying to avoid dynamic memory allocation. I initialize sensors to 3 to reserve space for them in memory, since there may be at most 3 elements in the array. But I am testing a condition where there will only be 2 elements:
Code:
#include <stdio.h>#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float current;
unsigned char pressure_units;
} sensor;
[Code]...
The problem is even though there are only 2 sensors out of 3 in the array, sizeof(sensors)/sizeof(sensors[0]) returns 3. I assume because when it allocates memory for 3, it includes that allocated memory even though it really doesn't contain the struct. How can I figure out how many elements were really inserted into array, not just allocated to array?
I am making a number base conversion program in c++, suppose that user enters an base 2 number and want to convert that number in base 4. when he enter the number (which he wants to be converted), how can i detect that number is belongs to base 2 number system or not.
For example: if user enter 1001011001 , program should continue and convert that number to base 4. and if user enter 1200101 or 1001012 , program should not convert that number and output that this number is not belongs to base 2 number system.
My objective is to check to see if a number is odd or even and print it to the screen just to make sure its working correctly.
The data file contains:
138
402 2 485
9
43
98 805
58
421
948 7 97
48
67
35
42
948
579 39 12
700 20 500 210
98
I can get the numbers to print fine using:
fstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
while(infile1.get(listNum))
cout << listNum;
}
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list):
1 is odd 3 is odd 8 is even
9 is odd
But it should print:
138 is even
9 is odd
I tried using getline, but it keeps giving me the errors:
invalid conversion from 'void*' to 'char**'
invalid conversion from 'char' to 'size_t*'
too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
getline(infile1, listNum);
cout << listNum;
}
#include "stdafx.h"
#include "iostream"
using namespace std;
int main (){
int x;
int i;
int e;
[Code] ....
is the logic good ? and why the program is looping
I'm trying to make a program to check if a number has decimal place, for instance: 1.34(yes), 1.0(no), 3.45(yes), 5.0(no).
Code:
#include <stdio.h>
#define LENGTH 4
int main( void ) {
int i;
float a[LENGTH];
for(i=0; i < LENGTH; i++) {
scanf("%f", &a[i]);
[Code] ...
I'm getting this output, why?
Quote
error: invalid operands of types "float" and "int" to binary "operator%"
What is the minimum range of numbers which we need to go necessarily to check either a number is prime or not?(for all integers) ....
View 6 Replies View RelatedI'm trying to create a program that allows the user to enter an unknown number of income and expense amounts. The program has to us see a while loop and display the income total, expense total, and total profit or loss. I've got it really close, but I'm doing the loop wrong. It counts the sentinel value (-1) towards the total, instead of just ending like it is supposed to.
#include <iostream>
using namespace std;
int main() {
//declare variables
double incomeInput;
double expenseInput;
double incomeTotal=0;
double expenseTotal=0;
[code]....
I have to obtain a check number from a datafile and then also get company information also from a datafile.
So my first question is about the:
Code:
char outputFilename[]= "out.list"
Is this the name of the output file I'm going to write to? And also the file has to be created before being used...is that line of code creating the file or do i have to create it in notepad?
Code:
FILE *ifp, *ofp;
char *mode = "r";
char outputFilename[] = "out.list";
ifp = fopen("in.list", mode);
if (ifp == NULL) {
fprintf(stderr, "Can't open input file in.list!
[Code] .....
Whenever I run the program I get no errors yet it doesn't return a value for total it just exits the program. The program is supposed to output the number of the day based on the month day and year and check whether it is a leap year.
#include <iostream>
using namespace std;
int totaldays();
int days();
int month, day, year;
bool leap();
int main() {
char dash;
cout << "Enter the date in mm-dd-yyyy format to find out what day this is in the year." << endl;
[Code] ....
This is a simple dictionary program, richtextbox is used for a results
but i wants to use textbox as a richtext box
(ex:money = dollar,penny,rupees)
as a list : dollarpennyrupees
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Project 2 Dic.txt = Project 2 Dic.rar
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