Is my understanding correct?
Ascii 'a' = 61 (Hex)
Ascii '0' = 30 (Hex)
So this is how we convert characters to hex.
Integer 0 = 0 (Hex), because it's not a character but an integer.
I have been skimming and searching but dont know how to word the search just right to find what I need to know. I have written simple stuff with the support of tutorials like weight conversion or loops counting up to a set number. Nothing amazing. The other day I found out how to input and print a string rather than a single text character which i though was bad ass. I even got it to read multiple strings on a single line and found a way to read multiple lines. I can even format it to read both integers and characters on the same line as long as I know the predefined format.
On to my question... How do I read multiple lines with both carecters and integers. for instance:
nissan 1996
toyota 1998
or more comples like
nissan gtr 1996
toyota markii 1998
I want to use
int year;
char make[10]; maybe need to use char make[10][10]; for an array i would guess.
char model[10]; optional for the extra data
but reproduce what i read in a different order. say...
1996 nissan
1998 toyota
vice the original format.
this is what I have tried.
Code: scanf("%s %s", &make,&year);
//The way I seen to read multiple lines was on here
scanf("%[^/t]", %make);
But this wont let me separate the two into two differnet definded data types. Let alone use printf to display them in reverse order.
a few pointers in building an assembler in C for a 68hc11 micro controller I'm struggling on a way to convert the assembly language in a txt file to s19 format.
View 1 Replies View RelatedI wanted to write a program to convert a number into a more readable format. It's like, if the input enters the number as 2361263 the output should be like 2,361,263. I went about this problem like extraction the number first and then if the count was equal to multiple of three i'd print ',' instead of the number.
But initially when i wrote the code for extracting a single digit from the number
Code:
#include<stdio.h>
void main() {
unsigned long long num=pow(2,50);
int count=0;
while(num!=0) {
int last_digit;
[Code]....
I know that I'd lose the number when i finish printing it, but still I only end up printing the entire number in reverse order.
As in if the input is 1234 the output is 4,321 which is not what i want.
One way of overcoming this problem is to store the values in an array and then reading then back from the end. But i wanted to know if there is a better solution than this? To extract the digits from the number in the same order as it is in the number
I have total time in seconds (say 2500 seconds). I want to store this time in CTime or CTimeSpan format.?
How to do this.?
How do I convert date in integer format to DateTime without using DateTime?
I have tried:
Regex regex = new Regex(@"^(0[1-9]|1[012])(0[0-9]|1[0-9]|2[0-9]|3[01])(1[789]|[2-9][0-9])dd+$");
if (regex.IsMatch(txt_fromdate.Text) == true)
{
DateTime dt = DateTime.ParseExact(txt_fromdate.Text, "MMddyyyy", null);
}
I have almost a hundred names in a text file that I want to convert to email addresses and save to another file. I seem to have it working, but it doesn't print the full names in the email prefix. The output I'm looking for is Doe_John@livebrandm, but I'm only getting D_J@livebrandm. I'm not sure what I should specifically be reading up on that applies to this directly.
Code:
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
FILE *fpin=fopen("namesIN.txt", "r");
FILE *fpout=fopen("emailOUT.txt", "a");
char first[20],last[20],inbuff[1500];
[Code]...
The code is supposed to convert characters from an array into their respective ascii integers, and append a 0 if the number is less than 3 digits long. It then supposed to put it all together into one string.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
char file[] = "This is a test";
char *ptr = file;
int length = strlen(file);
int i, numbers[length];
[Code] .....
heres the function:
string ToString ( const char * format, ... )
{
char buffer[256];
[Code]....
these function do the same of the sprintf() function. but instead we use a variable for add the result, i want to return the result. when i use it:
string f;
f=ToString("hello world");
gives me several errors:
"error: crosses initialization of 'std::string f'"
"error: jump to case label [-fpermissive]"
How would you convert say "238273615237287352536266362524382737272" base 10 to a base x number contained within a string of characters?
View 2 Replies View Relatedso my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char str1[20], str2[20],remp = ' ';
int size1,i,j,temp;
printf ("Input the first string");
[Code]...
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";
Code:
template<class T>
class Convert {
T data;
public:
Convert(const T& tData = T()) : data(tData)
[Code] ....
Why do we use operator? Is float and double function names below?
Code:
Convert<int>::operator<float> float();
Convert<int>::operator<double> double();
I am in a c++ class and my group is having a hard time making this work... It keeps saying that 'fileOne.open' isn't working.
#include <iostream>
#include <string>
#include <fstream>
[Code]....
I'm trying to edit an image by multiplying the red component of each pixel by 10 and leaving the other components (green and blue) untouched. I'm not really sure how I'm supposed to edit the pixels one by one. I have this so far. I think there is something wrong with my ppm header as well. Is there a way to make a ppm header without specifying the bounds so that it conforms to the image you are putting in?
Code:
#include <stdlib.h>
#include <stdio.h>
#define PICTURE_FILE 1
#define MIN_ARGS 2
#define h 768
#define w 1024
void solve(FILE *in_picture, FILE *out_picture)
[Code] .....
I have installed VS 2010 and VS 2012. VS 2012 uses SqlServer CE 3.5 and VS 2012 uses SqlServer CE 4.0.The problem is that when a project uses a 3.5 file it tries to open it with 4.0 even if the app.config says to use the 3.5 provider. The version of the assembly is pulled right out of the GAC. I uninstalled 4.0 and the reference auto updated its version to 3.5.1. However after installing 4.0 again it changes to 4.0. The error I am getting is that 4.0 cannot open a 3.5 file....they changed the file format from 3.5 to 4.0 and they are not compatible.
View 2 Replies View RelatedThe requirement is to capture statistics of uuid occurrences for ALIVE/SEARCH/BYEBYE (it can be all 3, combinations of 2 each, or one alone) in a dynamically populated file in run time.
I am able to print all 3 combinations, but not in combination of 1 or 2 e.g.
If my input.txt is like this :
uuid:22314754-a597-490b-8a93-02cfae01036b ALIVE 16
uuid:22314754-a597-490b-8a93-02cfae01036b BYEBYE 8
uuid:22314754-a597-490b-8a93-02cfae01036b SEARCH 8
uuid:50e65653-7525-485d-83bf-d293558c4264 ALIVE 32
uuid:50e65653-7525-485d-83bf-d293558c4264 BYEBYE 8
uuid:50e65653-7525-485d-83bf-d293558c4264 SEARCH 132
[Code]...
Code:
#include<stdio.h>
#include<string.h>
struct uid
{
char uid_val[100];
char state[100];
int temp_count;
int alive_count;
int search_count;
[Code]...
Gives the following output ->output.txt)
Device ID ALIVE BYEBYE SEARCH
uuid:22314754-a597-490b-8a93-02cfae01036b 16 8 8
uuid:50e65653-7525-485d-83bf-d293558c4264 32 8 132
uuid:55076f6e-6b79-4d65-6497-180373763bc1 113 112 111
uuid:T0100203354 1 2 3
I want to generalize the code such that uuid occurrence does not have to be all 3 (ALIVE/SEARCH/BYEBYE), the occurrences can be any combination and code should work. e.g my code gives wrong results when input.txt contains the following:
uuid:22314754-a597-490b-8a93-02cfae01036b BYEBYE 8
uuid:22314754-a597-490b-8a93-02cfae01036b SEARCH 8
uuid:50e65653-7525-485d-83bf-d293558c4264 ALIVE 32
uuid:50e65653-7525-485d-83bf-d293558c4264 BYEBYE 8
uuid:55076f6e-6b79-4d65-6497-180373763bc1 ALIVE 113
uuid:55076f6e-6b79-4d65-6497-180373763bc1 BYEBYE 112
uuid:55076f6e-6b79-4d65-6497-180373763bc1 SEARCH 111
uuid:T0100203354 BYEBYE 2
I am using ubuntu for gcc/g+ compiler.
I am trying to format a Gregorian Calendar that accepts only the year as a user input, but I want the display to show 3 months on one row. I can get January to display correctly, but the February and March months do not.
I think my loop inside of my calendar1 function specifically is the issue:
//Is day before Sat? Else start next line Sun.
if ( ( day + daycode ) % 7 > 0 )
cout << right << setw(3);
[Code]......
My output right now is:
Enter first prime numbers that will be used or -1 to end: 20
Twin Prime Number : (3,5)
Twin Prime Number : (5,7)
Twin Prime Number : (11,13)
Twin Prime Number : (17,19)
But what I want is:
1. {3;5} 2.{5,7} 3.{11,13}
4. {17,19}
else if (i - prime_number == 2)
{
cout << "{" << prime_number << ";" << i << "}" << endl << endl;
prime_number = i;
}
I have a Dialog with a Browser Control and load a Site with a Video, as the Title says, is there any Way to keep a Dialog in the Format of 16:9 Format, in eg. if someone change the Width or Height of a Dialog, the Height/Width should be changed to? To keep this Format permanent?
My first try was in a OnSizing(UINT fwSide, LPRECT pRect) Function but this is not the best way, because any Time i want to resize my Dialog it flickers terribly and i know i make it in a wrong way.
So I have a programming assignment which is for getting a user input in the format of m/d/yyyy. This is stored as d/m/yyyy. I have been able to code all the rest of the requirements of the program but the thing that is giving me trouble is this. The year is allowed to go from 1-3000. The format of the displayed date is:
a zero-filled, two-digit day number, a dash, full name of month, a dash, zero-filled, four-digit year.
I am able to use a switch statement in order to get my name of the month. What I am struggling to figure out is the whole zero filled two digit day and zero filled four digit year. From the way the input is store it appears to me that it will be stored as yyyy which means if you were to enter 0001 for year 1 then it should output it as that (this is an assumption based on format). What I don't get is that the day is entered and stored as d which means if you put in 12 how would it be stored. However if you put in 6 to print the output I would need to add a zero and I dont know how to do that either.
Here is the code for getting the input. The function must stay formated this way as per the instructor. The / is stored but ignored hence the char for second and fourth since / is a char
Code:
void getDate (int& day, int& month, int& year){
char second;
char fourth;
cout << "Please enter a date in the format of m/d/yyyy" << endl;
cin >> month >> second >> day >>fourth >> year;
}
I need a C code for generating a Histogram with intensities at X-axis and number of pixels at Y-axis from a PGM format image.
View 5 Replies View RelatedHow to make tabular format in STRUCT?
View 5 Replies View RelatedI want to take screen shot and save it in any image format like jpg, bmp, ppm or any other .
View 3 Replies View RelatedI am new to C++ and programming in general. I was wondering if it is possible to use C++ to search for company email formats and domain addresses?
For example, finding the correct format like:
jsmith@carnival.com
or
johnsmith@carnival.com
or
j.smith@carnival.com
Also, if it is possible to find the actual email domain, such as:
@carnival.com
or
@carnivalcruises.com
or
@carnivalcorp.com