I have tried to search all about strings,I have the occurrences and have worked out what letter corresponds with which. I have searched that much i can remove the vowels and reverse my string but I dont know how to swap them. This is what i have this far. When it compiles it just prints the decipher is:
If i even find out am i on the right track ive used caps when swapping to try and stop the doubles over writing,...
#include<stdio.h>
#include<string.h>
int main(void){
int i,count=0;
char secretText[] = "lopsy, hssepokd wl okrhsowk:
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() { int i; char ch[5]; for(i = 0; i < 5; i++) { scanf("%c",&ch[i]);
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";
I am trying to make a program which manages the data of 5 different patients (its an uni assignment), and i want to use a switch case as a menu to switch between the patients. All other functions (as for example putting the infromation on a file) work, but i cant figure out to bring the switch to work. First it asks for the number of the patient which should be worked with, this works perfectly, but afterwards changiung between the persons doesnt work as thought. It should ask everytime after it switches to one patient (i removed some functions to make it easier to read) and then asks to which it should jump next. If i put the number of one case (lets say 3) it just stops the program.
********Example: user@pc ~/wherever $ ./program current variables: jo = 2 a = 0 1 //the entered number The variable a = 1 patient 1 Enter the number of the next patient2 // and then it closes **************
The same thing happens if i compile an example code from a book, it writes the first case and then stops.
I looked already through the forum but didnt find a person with a similar problem, maybe i didnt dig deep enough.
I am running Linux Mint 17 and use gcc as compiler.
Code:
include <stdio.h> #include <stdlib.h> int a=0; int jo=2; int main(void){ printf("current variables: jo = %d a = %d
so I am trying to have an switch statement array. but every time i complete a case statement the whole process is returned. the thing is i want the menu to stay up even if i complete the case.
How do I convert dna from an array to complementary dna.
void print_reverse_complement(const char dna[]) {
the above function will convert DNA to Complementary DNA.. i.e A=T, C =G, G=C and T=A.
The prompt should look like: (asks user for dna sequence and stores into array) (prints back entered sequence)DNA sequence: ATCGGCATA DNA complement: TAGCCGTAT DNA reverse complement: TATGCCGAT
Then how would I do the same thing, but this time the reverse complement?
I have a seat allocation algorithm for an airplane 30 x 6 seats. The plane is 'split' front (1 - 15) and back (16 -30), right (A,B,C) and left (D,E,F). I am placing passengers in window seats front right centre (15A) first then back left centre (16F) followed by (15F) followed by (16A). This will continue for single passengers middle seats then aisle.
Another part of the algorithm is to ensure parties >2 or <=6 to sit together in an empty row, if not possible the party will be split as to not have a person in the party sitting alone firstly. i.e. 6 is 3 + 3 or 2 + 2 + 2 or 4 + 2 or 3 + 2 + 1 or 4 + 1 + 1 or 3 + 1 + 1 + 1 and so.
I have got it working for one person but seating two people is a bit more difficult. I am trying to get 15A,15B then 16E,16F then 16A,16B then 15E,15F then 16C 16D and 15C 15D.
This code only allocates passengers 15 A 15B then 15C 15D then 15E 15F
//seat allocation for two people public bool[,] seatTwoPerson(bool[,] seatArray, int startCol, int endCol, int directionX, int startRow, int endRow, int directionY) { //loop through seatArray section determined by parameters //for (int col = startCol; directionX < 0 ? col >= endCol : col < endCol; col += directionX)
Just making typical console game where hero moves with w a s d.
However, in my code, while a and w work (minusing), s and d dont work (adding). I have used a switch statement to change the char position of the hero based on kbhit.When you hit s or d, the buttons that add 1 to the 2nd dimension of the array, the screen goes crazy!
#include <iostream> #include <string> #include <conio.h> #include <ctime> #include <cstdlib> using namespace std; const char PLAYER = 'H';
Assume you want to use a loop to process an array of characters starting from the beginning of the array. You want the loop to stop when you read the null terminator character from the array. Fill in the loop test condition that will make this work correctly.
index = 0; ch = array[index]; while ( _____________________________) { // process the character index++; ch = array[index]; }
I have an array titled: char TypeOfSong[arraySize] where the array size is 15. I am reading data from a file into this array and the characters can be either 'C', 'D', 'E', or 'R'. Each of these characters stands for a word (sting) and when I output the array, I need the strings to show up, not the characters. I have been reading online and in my book but I can only find information on turning one array with the same characters into a string. How would I go about changing this character array with different characters into a sting?
I am currently having an issue with validating user input for a state abbreviation. I have an array where a list of abbreviations is stored to use as a comparison for whatever the user inputs. I have been able to get the list loaded properly but whenever i go to compare, it always comes back as true even if it isn't. Here is some relevant code:
static char stateTable[STATE_TABLE_SIZE][STATE_SIZE]; int main() { char buffer[40], *testCustName[40], testState[5], testCode; buffer[0] = ' '; int quit = 0; int p = 0;
I am trying to initialize an array of pointers to an array of characters, I can do it in 3 lines but I really want to do it in one line at the same time keeping the #define.
I am trying to write a function compress() that takes in an input of a 2-dimensional array (5x10) of character data, compresses each row of the array by replacing each run of character with a single character and the number of times it occurs, and prints on each line the result of compression in the function. For example, the row with data aabbcdddee may be compressed into a2b2c1d3e2.
Input (5x10 of characters): aaacccdeee sssseeeedd aaaaaaaccc eeedddasee ddeeeeeggg
Output: a3c3d1e3 s4e4d2 a7c3 e3d3a1s1e2 d2e5g3
I could achieve the compression part, but behind the compressed array, it printed out 5 extra lines of alien ASCI code, followed by printing out 5 times of everything .
Code:
void compress(char data[SIZE1][SIZE2]) { int i,j, k,l ,count; char data123; printf("Enter your data (5x10 of characters): "); for (i=0; i < SIZE1; i++) { for (j=0; j < SIZE2; j++) data[i][j] = getchar(); fflush(stdin); }
I have written this program to copy all the characters input from the keyboard into the array till a "?" mark is entered. what is the error i am doing. I am getting a run time error in this case.
Code:
void word_reversal(void) { char array[100]; int index=0; printf("Enter the number of characters less than 100 "); do { scanf("%c",&array[index++]); }while(array[index] != '?'); }
Here's the question: Create a program that accepts an array of characters. And displays the converted array of characters into Upper case if it is given in Lowercase and vice versa. Don't use string, but char.
Example: mychar ="I am A conQUeror." Code: //My Codes: #include <iostream> #include <conio.h> using namespace std; int main()
my question is located as a comment beside the last printf ! ? check the comment near the last printf the comment is ==>here i get a sequence of numbers the question is how can i copy this sequence to an array and the print the array out ?
Code: #include <stdio.h> #define N 30 #define n 100
[Code]....
here i get a sequence of numbers the question is how can i copy this sequence to an array and the print the array out ?
I am trying to learn how to declare a pointer to an array of characters. And here is the code i have written. But iam getting a warning saying assignment from incompatible pointer type p = s.
Code: #include <stdio.h> int main(int argc, char *argv[]) { char (*p)[10]; // pointer to an array of 10chars char s[10] = "Hello" p = s; printf("%s",p); return 0; }
I have initialized a multidimensional array eg char fruit[5][10]...Then I would need to read in 3 words with spaces in between from user and store in fruit[5][10] e.g "pear apple orange"
The thing is that after typing orange, when I press Enter it still prompts me to enter more characters. How can I end the scanning of characters after orange ?
I have been looking everywhere, but the only place I have seen it done is Objective C. The Question: how do I split a string, input by the user, into an array of characters? No code shown because I know no commands that do this.
My question is how create a function to remove all vowels defined as characters('a' 'e', 'i', 'o', and 'u') from the array provided to it.
An example of how the function should work:
input: Hello world, how are you? output: Hll wrld, hw r y?
Code: int removeVowels(char arr[]) { int i; //move through each element of the array for(i = j; arr[i] != '/0'; i++) { //if the last character was a vowel replace with the current //character
Below is an extracted portion of an example exercise from the C Programming Language book:
Code: void escape(char * s, char * t) { int i, j; i = j = 0;
while ( t[i] ) { switch( t[i] ) {
[Code] ....
Here's my problem with this. s is a pointer to a char array. That means each index stores 1 byte. A backslash character '' is one byte. In above example, we escape it with a second backslash character: ''. That means we have two bytes there. So why does it allow inserting two bytes into a one byte index?
