I am trying to learn how to declare a pointer to an array of characters. And here is the code i have written. But iam getting a warning saying assignment from incompatible pointer type p = s.
Code:
#include <stdio.h>
int main(int argc, char *argv[]) {
char (*p)[10]; // pointer to an array of 10chars
char s[10] = "Hello"
p = s;
printf("%s",p);
return 0;
}
This is a sample program that declares a Matrix as a structure with an array as a pointer to a pointer. The following program is supposed to store a matrix in the structure "_Matrix" and later print the matrix just entered but it fails giving me a "segmentation fault". The sample code is given below
Code:
#include <stdio.h>
#include <stdlib.h>
struct _Matrix {
int row_size;
int col_size;
int **mat;
[Code] ......
I write these code in 2 different ways and I get the same result. I just want to make sure that they both are for declare a pointer using "auto"
The first one:
int varName = 10;
auto var1 = &varName;
cout << var1 << endl; //prints, varName address
cout << *var1 << endl; //prints, varName value
The second one:
int varName = 10;
auto *var2 = &varName;
cout << var2 << endl; //prints, varName address
cout << *var2 << endl; //prints, varName value
It doesn't matter if I put dereference operator or not, I still get the same result. I just want to make sure that var1 and var2 are both a pointer.
this question would their be a different process if they asked "declare and initialize a pointer to the variable int cost[N][N]" Here's what I have so far
[#include<stdio.h>
int main() {
int a; // Step 1
int *ptr; // Step 2
a = cost; // Step 3
ptr = &a; // Step 4
return(0);
[Code] .....
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
1. The debugger shows that the characters are entered into the word pointer, and when a punctuation or space character is encountered, I terminate the string with a ''. But when I use puts to print the string, garbage is printed. Why is this?
2. Also, if I don't allocate memory for word the compiler gives a warning about it being used uninitialised. But I didn't allocate memory for the array of pointers(words), and the compiler didn't give any warnings. Whats the difference between a pointer and an array of pointers?
Code:
// wordcount.c - count words.
#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>
[Code]....
I have an array of characters. I am trying to find "houston". The only way I can think of to do this is to use a for loop and check each individual character. Is there an easier way to do this?
char string[] = "Fishing tourism miami atlanta dallas houston";
I want to declare a global array and then use it in a few functions. When I want to assign any number to that array I face with this error:
Code:
a.c:11:6: error: expected expression before ']' token
n[]={1,2,3,4,5};
^
The code is:
#include <stdio.h>
int n[5]; // I need to define the array here to be global
int main () {
n[]={1,2,3,4,5};
[Code] .....
I need to make a program that will let the user input values and it will only stop accepting once the user has inputted a negative number then it will display its mode and frequency.
The problem is I can't find a way to let the user input values freely without asking first for the no. of values he will enter.
#include<stdio.h>
int main() {
int i,j,k=1,p,a[20],b[20],n,cnt=1,big;
clrscr();
printf("Enter the number of elements:
[Code] .....
I need a multidimensional array and it should be declared without giving size to it.will it be possible?
View 3 Replies View RelatedI wanted to add that the template argument is needed because its a "special case" but if that doesn't work what would be the next best way to solve this problem. I want to be able to declare the const size of the array outside the class far removed from it actually. I'm actually going off this page
[URL] .....
Heres the code
#include <iostream>
template <int F>
class C
{
[Code]....
Question simple like that: Let user enter some words from keyboard, one word per line until a '.' (period) entered then print out result, for example:
Code:
Enter a word: word1
Enter a word: word2
Enter a word: .
You have entered 2 word(s):
word1
word2
Problem is I don't know how to declare the array of character at the beginning since I don't know neither how many word user may enter nor how many letter of each word. So I go ahead and declared like this: char word[20][50] but I know it is not best way.
Code:
int main () {
char word[20][50]; //array has maximum 20 words, each word maximum 50 character
int i=0, number_of_word;
do {
printf ("Enter a word: ");
[Code] ....
how declaring this: { {1, 2}, {1, 2, 3} } Both outer and inner array had known size.
View 19 Replies View RelatedAssume you want to use a loop to process an array of characters starting from the beginning of the array. You want the loop to stop when you read the null terminator character from the array. Fill in the loop test condition that will make this work correctly.
index = 0;
ch = array[index];
while ( _____________________________)
{
// process the character
index++;
ch = array[index];
}
i have been fiddling with pointers but I don't understand how the proper syntax is written when I want to acces an element of an array through a pointer to a pointer...The code is all mostly just random bs for learning purposes. I marked the problem "// THIS LINE"
Code:
#include <stdio.h>
#include <stdarg.h>
#include <stdlib.h>
#include <string.h>
#define MAX_DATA 100
int find_average(char *iden, ...) {
[Code]...
I have an array titled: char TypeOfSong[arraySize] where the array size is 15. I am reading data from a file into this array and the characters can be either 'C', 'D', 'E', or 'R'. Each of these characters stands for a word (sting) and when I output the array, I need the strings to show up, not the characters. I have been reading online and in my book but I can only find information on turning one array with the same characters into a string. How would I go about changing this character array with different characters into a sting?
The characters stand for:
C = Country
D = Dance Party
E = Elevator
R = Rock
I am currently having an issue with validating user input for a state abbreviation. I have an array where a list of abbreviations is stored to use as a comparison for whatever the user inputs. I have been able to get the list loaded properly but whenever i go to compare, it always comes back as true even if it isn't. Here is some relevant code:
static char stateTable[STATE_TABLE_SIZE][STATE_SIZE];
int main() {
char buffer[40], *testCustName[40], testState[5], testCode;
buffer[0] = ' ';
int quit = 0;
int p = 0;
[code].....
I am trying to initialize an array of pointers to an array of characters, I can do it in 3 lines but I really want to do it in one line at the same time keeping the #define.
3 lines initialization (can compile)
======================
#define A 1
#define B 2
char row1[] = {A|B, B, A};
char row2[] = {B, A};
char *test[]= {row1, row2};
1 line initialization (failed)
===============================
char *test[] = { {A|B, B, A}, {B, A} }; // <- how do i do this??
I do not want this because it waste ROM space
=============================================
char test[][3] = { {A|B, B, A}, {B, A} };
I have the following code :
Code:
#ifndef TDYNAMICARRAY_H
#define TDYNAMICARRAY_H
namespace Massive {
template<class T>
T **AllocateDynamic2DArray(int nRows,int nCols)
[Code] .....
I wish to know how to traverse or loop through a dynamic 2D array using pointer to pointer as returned by the code above. Like I would in a static T[20][20] 2D array.
I am trying to write a function compress() that takes in an input of a 2-dimensional array (5x10) of character data, compresses each row of the array by replacing each run of character with a single character and the number of times it occurs, and prints on each line the result of compression in the function. For example, the row with data aabbcdddee may be compressed into a2b2c1d3e2.
Input (5x10 of characters):
aaacccdeee
sssseeeedd
aaaaaaaccc
eeedddasee
ddeeeeeggg
Output:
a3c3d1e3
s4e4d2
a7c3
e3d3a1s1e2
d2e5g3
I could achieve the compression part, but behind the compressed array, it printed out 5 extra lines of alien ASCI code, followed by printing out 5 times of everything .
Code:
void compress(char data[SIZE1][SIZE2])
{
int i,j, k,l ,count;
char data123;
printf("Enter your data (5x10 of characters): ");
for (i=0; i < SIZE1; i++) {
for (j=0; j < SIZE2; j++)
data[i][j] = getchar();
fflush(stdin);
}
[code]....
I have written this program to copy all the characters input from the keyboard into the array till a "?" mark is entered. what is the error i am doing. I am getting a run time error in this case.
Code:
void word_reversal(void) {
char array[100];
int index=0;
printf("Enter the number of characters less than 100
");
do {
scanf("%c",&array[index++]);
}while(array[index] != '?');
}
I have tried to search all about strings,I have the occurrences and have worked out what letter corresponds with which. I have searched that much i can remove the vowels and reverse my string but I dont know how to swap them. This is what i have this far. When it compiles it just prints the decipher is:
If i even find out am i on the right track ive used caps when swapping to try and stop the doubles over writing,...
#include<stdio.h>
#include<string.h>
int main(void){
int i,count=0;
char secretText[] = "lopsy, hssepokd wl okrhsowk:
[code]....
Here's the question: Create a program that accepts an array of characters. And displays the converted array of characters into Upper case if it is given in Lowercase and vice versa. Don't use string, but char.
Example: mychar ="I am A conQUeror."
Code: //My Codes:
#include <iostream>
#include <conio.h>
using namespace std;
int main()
[Code] ....
my question is located as a comment beside the last printf ! ? check the comment near the last printf the comment is ==>here i get a sequence of numbers the question is how can i copy this sequence to an array and the print the array out ?
Code:
#include <stdio.h>
#define N 30
#define n 100
[Code]....
here i get a sequence of numbers the question is how can i copy this sequence to an array and the print the array out ?
Code:
#include <stdio.h>
#include <string.h>
#include <conio.h>
#include <math.h>
void reverseAr(char ar[], int n);
int main() {
int choice;
char *abc= ar[];
[Code]...
My codes keep couldn't get the reverse array of characters.
I have initialized a multidimensional array eg char fruit[5][10]...Then I would need to read in 3 words with spaces in between from user and store in fruit[5][10] e.g "pear apple orange"
The thing is that after typing orange, when I press Enter it still prompts me to enter more characters. How can I end the scanning of characters after orange ?