I am writing a program that asks the user for their gender. I know that atoi converts arrays into integers, but I need the input from the user in the form of F or M into a char, and return it to the main function to be displayed at the end of the program.
string Employee::getgender(char gen)
{
cout << "Please enter your Gender: " << endl;
//atoi function would go here, what for char?
getline(cin,gen)
return gen;
}
In this program, I have to ask the user for an employee, then the program will check to see if the file for that employee exist, if it doesnt then it will automatically create the file.
ReadNew function reads the file....check to see if it exist
CreateNew function creates a new file.
In my code I have no problem with the first part of reading file.. and my createnew function works in other programs where I am asking for input of file name to create the file name. However in this code I cannot figure how to automatically pass the input filename from the ReadNew function to the CreateNew function. I can't ask the user to enter the name a second time, so I have to pass the input filename into both functions. Here is my code.
Code:
//Create a file, append to it, and read it.
#include <iostream>
#include <fstream>
#include <string.h>
#include <stdio.h>
using namespace std;
char filename[256];
string n;
string filelist;
void CreateNew(ofstream & FileNew);
[Code]...
Here's the code I'm working on:
string* arrayPush(string *array, char **toks){
if(array[sizeofHistory -1].empty()){
//find the next available element
for(int i=0; i < sizeofHistory; i++ ){
[Code] ....
toks is an array of pointers to strings. I need to assign a toks to array[i].
So I have to convert ("a499.9") into a char and a float while ignoring the a.
I have the string stored in a buffer and found how to get the char, 4. But I don't know how to get 99.9 as a float.
Here is my code so far.
#include <string>
using namespace std;
main() {
buffer = "a499.9";
[Code] ....
My output:
4
0
How to get that double out?
I am writing a code in a class that will change the user input which is integer to a string. For example if the user enter 13347..the output should change to "one three three four seven" on the user screen.I'm not getting the right output.
Code below:
#include <iostream>
#include <string>
using namespace std;
string arr[]={"one","two","three","four","five","six","seven","eight","nine"};
class convertTo{
public:
int signed num;
int convet(){
cout<<"Enter a number to convert to string "; cin>>num;
[code]....
I am writing a code in a class that will change the user input which is integer to a string. For example if the user enter 13347..the output should change to "one three three four seven" on the user screen.I'm not getting the right output.
Code below.
#include <iostream>
#include <string>
using namespace std;
string arr[]={"one","two","three","four","five","six","seven","eight","nine"};
class convertTo{
public:
int signed num;
[Code] ....
I'm extremely rusty at C but is this the best way to store an input string into a char*?
Code:
int length = 100; //initial size Code: char * name = malloc(length * sizeof(char)); //allocate mem for 100 chars
int count = 0; //to keep track of how many chars have been used
char c; // to store the current char
while((c = getchar()) != '
'){ //keep reading until a newline
if(count >= length)
name = realloc(name, (length += 10) * sizeof(char)); //add room for 10 more chars
name[count++] = c
}
Is this a good way and what could be better?
I want to take string input into a char array.
What is the functionality for the above problem.
Why is this
Code: fFile << (char) (i)p.x, (char) (i)p.y,(char) (i)p.z); not the same as this
Code: printf("%c%c%c", (i)p.x, (i)p.y, (i)p.z);
Having trouble converting char to hex.
according to here [URL] ....
ô in decimal is 147 and print ô using alt 147
and here [URL] ....
ô in dec is 244 but prints ⌠ using alt 244
put on console
char c = ô;
cout << (int)c << endl;
prints -109 and print m using alt -109
I am using alt to test char output. Why I'm getting a negative value? Which of the tables are correct? I have string of char that I want to print in hex. I get a hex string but the hex value don't correspond to any of the two tables on the websites because the console converts special char to negative values.
I am tying to convert an int to a char. Below is an example of the code that I have but I am getting an error('=':left operand must be l-value). I am not seeing a problem with the code.
int num = 5;
char temp[2];
char final[2];
itoa(num, temp, 10);
m_pRes->final = temp;
I am looking for the correct syntax to typecast a character array as an int. So I would be able to do something like this:
char ch[4];
//...Read characters from file into ch or something, etc...
int i = ( int ) &ch;
or
char ch[4];
//...Read characters from file into ch or something, etc...
int i;
strncpy ( ( char* ) &i, ch, 4 )
I want all the 4 characters ( or bytes ) of ch to be classed as an int. So we are taking the 4 bytes of the character array and placing them in 4 bytes of the integer? How would i go about this?
I am trying to convert a char buffer[1024] with raw data to int 16 buffer2[1024] which is supposed to have hex data (0x01, 0x02 kind of format).
Code:
char temp_buffer[1024];
block_size = sizeof(temp_buffer);
num_blocks = sizeof(char);
Status = mount(0, &myfsObject);
if(Status != DAVEApp_SUCCESS)
[Code] .....
I am verifying the data of resultant buffer by creating a new file and writing data to it. The result which i got is:
Code: H uy H uy H uy H uy H uy H uy H uy H uy
Originally I had to create a simple integer palindrome program that looped while the user entered 5 digit inputs (entering -1 stopped the loop). I did this using a conversion to string, reading the length to determine if the length was valid, and then reading the string forward and backwards inside of a while loop. (snippet below)
while( digitsEntered != -1)//Allow user to quit by entering -1 to end the loop
{
ostringstream convert;//conversion stream
convert << digitsEntered;//converted text from number goes in the stream
convertedString = convert.str();//store the resulting conversion to convertedString
[Code] ....
The next stage of this program was to do the same thing with strings instead of integers. However, the option to end the loop by entering -1 is still a requirement.
I think the way to do this is to first determining whether the input is a string or an integer, and if it is a string then read it and if it's an integer determine if it's -1. However, whenever I write code to do this, it converts strings to 0 so the string is not stored and cannot be read to determine if it is a palindrome. Is there a way to determine the type of input without converting it into a different type i.e. read string and then keep string or read number and keep number?
I'm trying to create a sort of text-adventure game, but rather than having to check for the input being uppercase or lowercase, I'd rather convert it before checking it in an if statement.
I've created a function, and I know it works because when I print the output, it shows up capitalized, however when I check it with an if statement, it doesn't pass.
Here is my code:
#include <iostream>
using namespace std;
void stringUppercase(string x) {
int i;
for (i = 0; i < x.length(); i++) {
[Code] ....
Code:
void convertNetPay(float netPay, char *netPayString){
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
char TensTable[9][8] = {"Ten","Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"};
char TeensTable[9][10] {"Eleven","Twelve","Thirteen","fourteen","fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
float cents;
[Code] ....
I have to convert my netpay which is a float to a string So if I input a value of say, 356.26 it should output "the sum of three hundred fifty-six and 26/100 dollars" . My program function works for the sum of three hundred but after that it spits out garbage.
How will I add the existing content of the text file to the newly inputed date(hoursworked & minsWorked) to compute the total number of hours works. I'm just a beginner in using Visual basic C++.
Code:
#include <iostream>
#include <fstream>
#include<string>
#include <cstdlib>
using namespace std;
bool parseTime(char* _timeStr, int& _hour, int& _min) {
[Code] ....
I'm trying to find a way to accuratley convert a double in the form of a bank account number stored in a file into a string representing the number returned by a file.
View 1 Replies View Relatedvoid convertNetPay(float netPay, char *netPayString) {
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
[Code] ....
BASICALLY, I have to convert netpay (float to string). Theoretically if I have 666.66, my program here should output the sum of "six hundred sixty-six and 66/100 dollars".
i think i need to convert a double to a string, we are working in visual studio doing a program. when i run the calculator i'm not getting the answer i need instead its giving me 0.0 when it should be reading 0.5, here is the code i'm using
{int width;
int height;
int area;
double gop;
String ^strWidth;
String ^strHeight;
String ^strArea;
String ^strGop;
strWidth=width1->Text;
[Code]....
I'm trying to convert a string into a integer and when I call stoi(line) it causes the program to crash.
int main() {
vector<int> numbers;
int i;
string line;
ifstream myfile ("example.dat");
[Code] ....
The file being read from looks like:
3
12
23
34
12 34
12 12
34 23
23 23
In my project i have to take the string valve and convert it into float
For example
100 will be 100.00
100.0012 will be invalid
100.00 will stay as it is
99 will be 99.00
I am thinking of using stof but i m stuck on how to set the precision of 2 ....
Quick code for converting strings to Dates in C++.
Example: What is the date:
User response: 12/05/14
Any way I can code this to recognize it as a date, and make it so that the date is sortable? Not referring to the system date, but a user input date.
I am trying to convert a 1d string array to a 2d but i couldnt do it. Heres my code so far,
for(i=0;str2d[i][j]='';i++)
{
for(j=0;str2d[i][j]=' ';j++)
{
str2d[i][j] = str1d[k];
k++;
}
}
str1d is a paragraph btw.I tried using NULL instead of '' but didnt work either.
how to convert from string to date in c++? Example: 17 mar 2012 to 17/03/2012
View 1 Replies View Relatedstruct time
{ int t;
int h,m,s;
};
int main() {
time t;
int totalsecond;
char A[10],B[10];
[Code] ....
It gives error at line no 12.
