So I have to convert ("a499.9") into a char and a float while ignoring the a.
I have the string stored in a buffer and found how to get the char, 4. But I don't know how to get 99.9 as a float.
Here is my code so far.
#include <string>
using namespace std;
main() {
buffer = "a499.9";
[Code] ....
My output:
4
0
How to get that double out?
In my project i have to take the string valve and convert it into float
For example
100 will be 100.00
100.0012 will be invalid
100.00 will stay as it is
99 will be 99.00
I am thinking of using stof but i m stuck on how to set the precision of 2 ....
I would like to convert a string variable to float.When acquiring data from text file, I use:
while( getline( ifs, temp )) {
numberOfFeatures++;
vecteur.clear();
string::size_type stTemp = temp.find(separateur);
number_descriptorEntries=0;
[code].....
the matrix that I obtain is of type vector<Vec> where Vec is a vector of strings.I want to convert each element of matrixe to a float.
I have a vector<string> of times that I want to convert to vector<double>. The time string is in the form 00:00.000. Is there a STL or something like it algorithm or function to do this, otherwise what would be the best way to do this with a function.
View 3 Replies View RelatedI have an assignment that is due on monday I am stuck on this function. I have to convert my netpay which is a float to a string So if i have 356.26 it should output the sum of three hundred fifty-six and 26/100 dollars my program function works for the sum of three hundred but after that it spits out garbage.
Code:
void convertNetPay(float netPay, char *netPayString) {
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
[code].....
I'm reading lines from a text file in C++ which contains integer + string + float number(like 3,67 with comma) + string in this order. I need the float number to sort the lines but I couldn't manage to separate the data into the types I can use so far. I tried different kind of functions and the best I could do was such a code;
void main (){
ifstream records;
records.open("records.txt");
int id;
string line;
char name[100];
float gpa;
[Code] ....
This fails at reading the floating number which has comma in it and then last string is read as string starting with the comma and rest of the number. An output example is:
698 John 3 ,67
It doesn't read last string on the line as well. I understand that part but simply I need another read but what I want exactly is to separate one line using "tab" as a seperator into proper data types and then using the numbers as integers, and the grades as floating numbers. How Can I do this?
In this program, I have to ask the user for an employee, then the program will check to see if the file for that employee exist, if it doesnt then it will automatically create the file.
ReadNew function reads the file....check to see if it exist
CreateNew function creates a new file.
In my code I have no problem with the first part of reading file.. and my createnew function works in other programs where I am asking for input of file name to create the file name. However in this code I cannot figure how to automatically pass the input filename from the ReadNew function to the CreateNew function. I can't ask the user to enter the name a second time, so I have to pass the input filename into both functions. Here is my code.
Code:
//Create a file, append to it, and read it.
#include <iostream>
#include <fstream>
#include <string.h>
#include <stdio.h>
using namespace std;
char filename[256];
string n;
string filelist;
void CreateNew(ofstream & FileNew);
[Code]...
Here's the code I'm working on:
string* arrayPush(string *array, char **toks){
if(array[sizeofHistory -1].empty()){
//find the next available element
for(int i=0; i < sizeofHistory; i++ ){
[Code] ....
toks is an array of pointers to strings. I need to assign a toks to array[i].
I am writing a program that asks the user for their gender. I know that atoi converts arrays into integers, but I need the input from the user in the form of F or M into a char, and return it to the main function to be displayed at the end of the program.
string Employee::getgender(char gen)
{
cout << "Please enter your Gender: " << endl;
//atoi function would go here, what for char?
getline(cin,gen)
return gen;
}
Question: A computer uses 10 bits to store integers with 1 bit for a sign. It stores an approximation of real numbers in 10 bits. The first bit of the first five is the sign of the mantissa and the other four bits are the mantissa. The first bit of the second five is the sign of the exponent and the other four the exponent.
1)What is the range of integers?
2)what is the range of real numbers(Float Type)
The first question was simple. I just found the smallest 10 digit binary number 1000000000 = -512 and then found the largest 10 digit binary number which would have to be 0111111111 = 511, therefore the range of integers is from -512 to 511.
For the second question - I am either making this harder than it is, or it really is a challenging question. So I followed the steps and first I was thinking I would take the number 1000000000 and convert this to a decimal (assuming its a 10 bit float)...But, can you even do this with a 10 bit float??
I ended up getting 1000000000 (after denormalizing) = .000100000 = 0.625.. would that be the minimum range? If so, then I know what I need to do to find the maximum , but if not - then I am really lost.
My Process was:
1.00000 X 2^(-4) = my final result of 0.625 after converting.
Here is my code:
int main (int argc, char* argv[]) {
int x = atoi (argv[1]);
int y = atoi (argv[2]);
int z = atoi (argv[3]);
if (strcmp(argv[4], "Simple") == 0){
[Code ....
I need to convert the output of simple interest to float which is $5184.90 instead of $5180. how to go about it?
Why is this
Code: fFile << (char) (i)p.x, (char) (i)p.y,(char) (i)p.z); not the same as this
Code: printf("%c%c%c", (i)p.x, (i)p.y, (i)p.z);
Having trouble converting char to hex.
according to here [URL] ....
ô in decimal is 147 and print ô using alt 147
and here [URL] ....
ô in dec is 244 but prints ⌠ using alt 244
put on console
char c = ô;
cout << (int)c << endl;
prints -109 and print m using alt -109
I am using alt to test char output. Why I'm getting a negative value? Which of the tables are correct? I have string of char that I want to print in hex. I get a hex string but the hex value don't correspond to any of the two tables on the websites because the console converts special char to negative values.
I am tying to convert an int to a char. Below is an example of the code that I have but I am getting an error('=':left operand must be l-value). I am not seeing a problem with the code.
int num = 5;
char temp[2];
char final[2];
itoa(num, temp, 10);
m_pRes->final = temp;
I am looking for the correct syntax to typecast a character array as an int. So I would be able to do something like this:
char ch[4];
//...Read characters from file into ch or something, etc...
int i = ( int ) &ch;
or
char ch[4];
//...Read characters from file into ch or something, etc...
int i;
strncpy ( ( char* ) &i, ch, 4 )
I want all the 4 characters ( or bytes ) of ch to be classed as an int. So we are taking the 4 bytes of the character array and placing them in 4 bytes of the integer? How would i go about this?
I am trying to convert a char buffer[1024] with raw data to int 16 buffer2[1024] which is supposed to have hex data (0x01, 0x02 kind of format).
Code:
char temp_buffer[1024];
block_size = sizeof(temp_buffer);
num_blocks = sizeof(char);
Status = mount(0, &myfsObject);
if(Status != DAVEApp_SUCCESS)
[Code] .....
I am verifying the data of resultant buffer by creating a new file and writing data to it. The result which i got is:
Code: H uy H uy H uy H uy H uy H uy H uy H uy
I have to convert my netpay which is a float to a string So if i have 356.26 it should output the sum of three hundred fifty-six and 26/100 dollars my program function works for the sum of three hundred but after that it spits out garbage.
void convertNetPay(float netPay, char *netPayString)
{
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
[Code].....
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
I have this:
void reverse(char *in, int isize) {
char t = 0;
for( int a = 0; a < isize / 2; a++ ) {
t = in[a];
in[a] = in[(isize - 1) - a];
in[(isize - 1) - a] = t;
[Code] .....
s:
float:123456
s:123456
The function i made is working fine, exacly how cout << float is working. The problem is i think my function is not really effective. By that i mean my function is doing alot of useless stuff to do what i want and there have to be a better way.
The rule is that you can not use other functions, only playing with loops and operators.
I am working with a XML serializer. I wonder if I am creating a text element (xerces). But the value I am after is a float, how do I convert it into a std::string ....
View 4 Replies View RelatedI would like to convert a float or double variable into unsigned char variable and back.
float number_float = 23.453f;
unsigned char* number_char = (unsigned char*)malloc(sizeof(float));
number_char = reinterpret_cast<unsigned char*> (&number_float);
float* number_float_0 = reinterpret_cast<float*>(&number_char);
I am not getting the same value back.. why?
Any really simple way of converting the following float to a string so I can take strlen()?
float a = 53213421;
strlen(a)?
I have looked up solutions but they are either too long or they confuse me.
So, I'm supposed to do : Create a function with unlimited number of arguments, which forms a dynamic string based on the following form (%d, %s, %f, %lf, %c), with the following prototype:
char*create(char*form, ...);
The function is supposed to have the following output:
create("Peter is %d years old and is in %s-%c class.",7,"second",'A');
-> Peter is 7 years old and is in 7-A class.
create("His GPA is %lf.",4.96);
-> His GPA is 4.96.
create("His favourite subject is math!");
-> His favourite subject is math!
I've managed to do the following :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
char *create(char *form, ...) {
char *res =(char*)calloc(1,1),*pos_int,*pos_float,*pos_str,pos_char,*pos_long;
[Code] ....
The part with %d and %s string was not that hard, but now I'm supposed to convert %f and %lf to string, I've tried using sprintf but I've had no luck so far, another problem is the fact that I've gotta use lists to complete the task. I've been trying to convert float to string for the past 2 hours, but I'm drawing a blank now.
Debug Error
ProjectsFinal ProjectGrItemDebugGrItem.exe
R6010 - abort() has been called
I was going over this with a friend and it seems as though getline() is not reading anything in and thus throwing the abort error. I'm not sure why this is because I've included the textfile, with the correct name of course, in both the regular file location and the debug folder. I ask for user input and the user then inputs the name of the file they want, I do some required things behind the scenes and display the results for them in a cmd window. I've included pastebin files for both my header and cpp files because it is far to large for one post I shall, however, post the full code in the comments.
Quick Code
The problem occurs on line 159. I'm assuming once this line is fixed, line 163 will have the same problem.
// Read regular price
getline(nameFile, input, '$');
vectorList[count].regPrice = stof(input.c_str());// Casts string to a float
// Read sale price
getline(nameFile, input, '#');
vectorList[count].salePrice = stof(input.c_str());
Pastebin Links : [URL] ....
Code:
void convertNetPay(float netPay, char *netPayString){
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
char TensTable[9][8] = {"Ten","Twenty","Thirty","Forty","Fifty","Sixty","Seventy","Eighty","Ninety"};
char TeensTable[9][10] {"Eleven","Twelve","Thirteen","fourteen","fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
float cents;
[Code] ....
I have to convert my netpay which is a float to a string So if I input a value of say, 356.26 it should output "the sum of three hundred fifty-six and 26/100 dollars" . My program function works for the sum of three hundred but after that it spits out garbage.
How will I add the existing content of the text file to the newly inputed date(hoursworked & minsWorked) to compute the total number of hours works. I'm just a beginner in using Visual basic C++.
Code:
#include <iostream>
#include <fstream>
#include<string>
#include <cstdlib>
using namespace std;
bool parseTime(char* _timeStr, int& _hour, int& _min) {
[Code] ....