Any really simple way of converting the following float to a string so I can take strlen()?
float a = 53213421;
strlen(a)?
I have looked up solutions but they are either too long or they confuse me.
I have to convert my netpay which is a float to a string So if i have 356.26 it should output the sum of three hundred fifty-six and 26/100 dollars my program function works for the sum of three hundred but after that it spits out garbage.
void convertNetPay(float netPay, char *netPayString)
{
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
[Code].....
I am working with a XML serializer. I wonder if I am creating a text element (xerces). But the value I am after is a float, how do I convert it into a std::string ....
View 4 Replies View RelatedI want to program an advanced calculator. I'd like to enter some more complex expressions like -17+3*4*(4-sqrt(4) and i want, that mathematical operations are done the correct order, so at first 4-sqrt(4) is calculated, then 3*4*2 and then -17 is subtracted.
Problem 1: Convert a string into a mathematical calculation
Problem 2: Calculate in the correct order
How would I do that (I dont expect perfecly precoded calculators from you, just the way how to do it)
Google search just delivers primitive calculations with entry methods like
Enter first number 1
Enter operator +
Enter second number 2
3
But thats not what i want
#include <iostream>
#include <string.h>
#include <sstream>
[Code]....
I have this:
void reverse(char *in, int isize) {
char t = 0;
for( int a = 0; a < isize / 2; a++ ) {
t = in[a];
in[a] = in[(isize - 1) - a];
in[(isize - 1) - a] = t;
[Code] .....
s:
float:123456
s:123456
The function i made is working fine, exacly how cout << float is working. The problem is i think my function is not really effective. By that i mean my function is doing alot of useless stuff to do what i want and there have to be a better way.
The rule is that you can not use other functions, only playing with loops and operators.
I have two vectors of float that I need to sort in reverse order. reverse() seems to work for one of them, but not the other. I have toggled between sort() and reverse(). for one vector, the expected behavior is seen and the order reverses. For the other, there is no change in order.
This is very simple code, so it's hard to imagine what is going wrong.
Code:
vector<float> vec1, vec2;
vec1[0] = 14.1102; vec1[1] = 14.1145;
vec2[0] = 15.8508; vec2[1] = 26.0842;
sort( vec1.begin(), vec1.end() );
sort( vec2.begin(), vec2.end() );
[Code] ......
Printout is,
Code:
vector 1 sort
14.1102
14.1145
vector 2 sort
15.8508
26.0842
vector 1 reverse
14.1102
14.1145
vector 2 reverse
26.0842
15.8508
You can see that the order of the first vector did not change. Am I right in suspecting that the numbers are too similar for what ever method reverse() uses to determine the difference between values?
So I been working on this c++ project and I need to be able to take three seperate strings and send them to function to put them in alphabetical order through a-z and use the swap function to return them in order. I been searching for problems like this but I haven't fame across any. I can copy my code onto here as well as a more detailed description of what I'm needing to do onto here if needed.
View 4 Replies View RelatedWhat would be a reliable way to do this? I need to convert RGB components to float values between 0.0 and 1.0 so 0 is 0.0 and 255 is 1.0.
View 1 Replies View Relatedhow to covert float value to array get any sessegation to convert the value
View 1 Replies View Relatedwhen you convert 1.7 to unsigned int, it becomes 1 or 2?
View 9 Replies View RelatedHow do you convert a number float in a range of -10.0f to 17.0f to a eqivalent number in the range of 0.0f to 1.0f?The code does not work well. floaty is the float to change.
//change range to 0..1
diamond[x][y] = (floaty - minY) / (maxY - minY);
Converting ascii value entered by user.
How to convert it to float basic of c programming techniques only ....
I'm VERY new in programming and I'm having trouble converting an integer to string. I need to create a function for a programme I'm working on for my school. My problem is that i am only allowed to use the libraries stdio.h, time.h and stdlib.h as well as printf, scanf, system, srand, time and rand. If I was allowed to use itoa or pointers it would be easier but i am not.
View 4 Replies View RelatedThis was an exercise from a book (convert a character string into a floating point value). It seems to work with both negative and positive decimal numbers.
It basically get each digit from the string multiplies by 10 to hold the place, and then adds the next to the result, if that makes sense.
Then determines where the decimal and null character are to figure out what to multiply by (1/1000 or whatever) to determine where the decimal should go. The variable names dealing with this part of the program aren't accurate names right now.
My question is, the output, is always putting 6 zero's. So if the argument is .95, Ideally the output should say .95 and not .950000, even though the value is still correct.
I know there the %.2f to determine the amount of decimals, but the amount of decimals in these instances would be varying depending on the argument sent to the function.
So, if 600.158 was sent as an argument, only 3 decimals would be displayed, as opposed to two from the previous example. Is there a way to do this?
Code:
// Function to convert a string to an integer
#include <stdio.h>
double strToFloat (const char string[])
[Code].....
I have the following function I would like to convert to work with std:string. I don't understand QT strings at all.
Code:
void FromHexString(const QString &hexText, void* pData, int dataSize) {
for (int i = 0; i < hexText.length(); ++i) {
bool ok = false;
((uint8_t*)pData)[ i ] = hexText.mid( 2*i, 2 ).toInt( &ok, 16 );
}
}
I am trying to read all the 9 letter words in a words list text file and print them to the screen. Here is the code I have so far, but I am currently printing nothing.
Code:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
int main()
{
[Code]....
#include<stdlib.h>
#include<stdio.h>
#include <string.h>
int main() {
char input[256];
char buffer[256];
[Code] ....
The output of this short program is really weird. When I type 123 from the keyboard,I get the following answer in console window"123 length=4".Why the output of length is always 1 more than the actual length of the string that I type in.
What is the efficiency of the two assignments (line 1 and 2), i.e. (function calls, number of copies made, etc), also the Big O notation. I know there are function calls for retrieving the size of each string in order to produce a new buffer for the concatenated string...any difference between line 1 and 2 in terms of efficiency?
String s("Hello");
String t("There");
1. s = s + t;
2. s += t;
In my project i have to take the string valve and convert it into float
For example
100 will be 100.00
100.0012 will be invalid
100.00 will stay as it is
99 will be 99.00
I am thinking of using stof but i m stuck on how to set the precision of 2 ....
I want a code that can convert floating/double value into string/char array(char arr[]) and also it can be run on Boreland C++ 5.02
Here I've a code but it doesn't show all the numbers. Instead, it's showing in exponential form which I don't want!!
int main() {
char* str = new char[30];
float flt = 2.4567F;
sprintf(str, "%.4g", flt );
cout<<str<<endl; //Exponential form even after 6 digits without decimal
return 0;
}
I would like to convert a string variable to float.When acquiring data from text file, I use:
while( getline( ifs, temp )) {
numberOfFeatures++;
vecteur.clear();
string::size_type stTemp = temp.find(separateur);
number_descriptorEntries=0;
[code].....
the matrix that I obtain is of type vector<Vec> where Vec is a vector of strings.I want to convert each element of matrixe to a float.
So I have to convert ("a499.9") into a char and a float while ignoring the a.
I have the string stored in a buffer and found how to get the char, 4. But I don't know how to get 99.9 as a float.
Here is my code so far.
#include <string>
using namespace std;
main() {
buffer = "a499.9";
[Code] ....
My output:
4
0
How to get that double out?
I have a vector<string> of times that I want to convert to vector<double>. The time string is in the form 00:00.000. Is there a STL or something like it algorithm or function to do this, otherwise what would be the best way to do this with a function.
View 3 Replies View RelatedI have an assignment that is due on monday I am stuck on this function. I have to convert my netpay which is a float to a string So if i have 356.26 it should output the sum of three hundred fifty-six and 26/100 dollars my program function works for the sum of three hundred but after that it spits out garbage.
Code:
void convertNetPay(float netPay, char *netPayString) {
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
char ResultString[10+1];
[code].....
So, I'm supposed to do : Create a function with unlimited number of arguments, which forms a dynamic string based on the following form (%d, %s, %f, %lf, %c), with the following prototype:
char*create(char*form, ...);
The function is supposed to have the following output:
create("Peter is %d years old and is in %s-%c class.",7,"second",'A');
-> Peter is 7 years old and is in 7-A class.
create("His GPA is %lf.",4.96);
-> His GPA is 4.96.
create("His favourite subject is math!");
-> His favourite subject is math!
I've managed to do the following :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>
char *create(char *form, ...) {
char *res =(char*)calloc(1,1),*pos_int,*pos_float,*pos_str,pos_char,*pos_long;
[Code] ....
The part with %d and %s string was not that hard, but now I'm supposed to convert %f and %lf to string, I've tried using sprintf but I've had no luck so far, another problem is the fact that I've gotta use lists to complete the task. I've been trying to convert float to string for the past 2 hours, but I'm drawing a blank now.