C/C++ :: How To Convert Entered ASCII Value To Float
Sep 29, 2012Converting ascii value entered by user.
How to convert it to float basic of c programming techniques only ....
Converting ascii value entered by user.
How to convert it to float basic of c programming techniques only ....
This is a small program that reads a line from the screen, takes the ASCII values from the entered text, and edits it. Next, the ASCII values are reinterpreted (am i misspelling?) as text, and displayed. However, my final output has (allways?) at least 7 characters, even if you enter only one. I'm also trying to accomplish, that the part of the string which isn't filled, will be printed empty. In spaces.
compiled with -std=c99.
Code:
#include <stdio.h>
int main(){
int maxsize;
printf("How long is your message?
[Code] .....
#include <iostream>
#include <string.h>
#include <sstream>
[Code]....
I want to convert Hex:390041 to ascii "90A",
39: 9
00: 0 -->Null
41: A
i am getting only "9" in the bytearray,i know 0 is terminating the array
unsigned int bytes[3];
int j=0,counter=0;
char c[2];
[Code]....
How can I convert bytes to ASCII?, I read wikipedia about UTF-8 and I understood a little bit about add or split bytes to change the value.
Now I have those bytes
0xC7 0xE6 0xC2 0x91 0x93 0x7B 0xCE 0x01
And I found a program (DCode) that convert to 64 bits little-endian, supposedly those bytes in ASCII is this.
lun, 08 julio 2013 04:28:17 UTC <---
I am making a text encrypter and I have to convert text into ASCII codes. I know how to convert a single character into ASCII -
#include <iostream>
using namespace std;
int main() {
cout<<"Text to ASCII converter"<<endl<<"Enter text to convert into ASCII - ";
char text; //defining input type, which is single character
[Code] ....
Try it here - URL.....Is there any way to run a similar program, which converts a string with spaces into ASCII code?
i am doing an embedded project on avr microcontroller ATmega8515.actually my project is smart card based electricity billing using UART interfacing..so in this module HEX to ASCII conversion is not possible for me...
how to convert from hex to ascii.
Using C . I have been tasked (for a University assignment) to create a program that will enable a user to upload an image and convert that image into ASCII text using SDL on a Linux system. I've managed to open a window, display an image (non-selected) and convert it into grayscale using
case SDLK_g:
for (int y = 0; y < image->h; y++) {
for (int x = 0; x < image->w; x++) {
Uint32 pixel = pixels[y * image->w + x];
Uint8 r = pixel >> 16 & 0xFF;
Uint8 g = pixel >> 8 & 0xFF;
Uint8 b = pixel & 0xFF;
Uint8 v = (0.212671*r)+(0.715160*g)+(0.072169*B)/>;
pixel = (0xFF << 24) | (v << 16) | (v << 8) | v;
pixels[y * image->w + x] = pixel;
I am absolutely clueless as to how I can get the user to upload an image to the program and then begin the image -> ASCII conversion. I've found seem to be written in C++ or C# to make the conversion I should be using the GetPixelColour command?
The code is supposed to convert characters from an array into their respective ascii integers, and append a 0 if the number is less than 3 digits long. It then supposed to put it all together into one string.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
char file[] = "This is a test";
char *ptr = file;
int length = strlen(file);
int i, numbers[length];
[Code] .....
What would be a reliable way to do this? I need to convert RGB components to float values between 0.0 and 1.0 so 0 is 0.0 and 255 is 1.0.
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void convertNetPay(float netPay, char *netPayString)
{
int numHuns, numTens, numOnes;
char OnesTable[9][8]={"One","Two","Three","Four","Five","Six","Seven","Eight","Nine"};
[Code].....
when you convert 1.7 to unsigned int, it becomes 1 or 2?
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//change range to 0..1
diamond[x][y] = (floaty - minY) / (maxY - minY);
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strlen(a)?
I have looked up solutions but they are either too long or they confuse me.
I can do the folowing:
float var1 ;
var1 = 9.12345 ;
printf("%.2f",var1) ;
the output will be 9.12. What if I wanted to save that as another separate float with displaying it on screen?
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream>
using namespace std;
int Max(int x);
int main() {
int x;
[Code] ....
How do I print this without generating errors?
Code:
printf(" ||====================================================================||
");
printf(" ||//$///////////////////////////////$||
");
printf(" ||(100)==================| RESERVE BANK OF INDIA|================(100)||
");
printf(" ||$// ~ '------========--------' $//||
[code].....
I have some ascii characters in a char variable.ex - char buf[100]="ab*(z&";
So each of the char in that char array will have some hex value.ex- *'s hex value is '2a'.
And I have a long long int variable in which there is a 64 bit hex value.
ex- long long int k=0x0000888888888888;
Now i want to subtract the char buff's hex value in k. How to accomplish it.
That is 0x0000888888888888
- 0x000061622a287a26
= 0x000027265e600e62 (final result in a buffer or a long variable is okay)
Later i want to reverse the result as 26e006e56272.It should be stored in a variable such that i should be able to access each byte from it(ex- '72'(last 2 hex digits))
Code:
template<class T>
class Convert {
T data;
public:
Convert(const T& tData = T()) : data(tData)
[Code] ....
Why do we use operator? Is float and double function names below?
Code:
Convert<int>::operator<float> float();
Convert<int>::operator<double> double();
I know how to find find ASCII value of given character, but I am not getting how to find ASCII value of given string. For example I want to find ASCII value of string "HELLO",so how to do that.
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I have an array of char:
Code: char myarray[50]; and I need to have ASCII value of character eg myarray[10]. How can I do that?
I have to Write a program to produce that makes four triangles and a pyramid. I have to ask the user they height of the triangle and prevent the user from entering a height any larger than 25. It should look like this.
Enter the height of your triangle/pyramid: 3
***
**
*
*
**
***
*
**
***
***
**
*
*
***
*****
im having tourble with 3 and 4th and also pyramid.
HERES WHAT I HAVE SO FAR.
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main () {
int input = 0;
cout << "Please enter the height of your triangle/pyramid: ";
[Code] .....
I'm currently working on a project that utilitzes a Caesar Cipher. Basically, it reads input from a file and then, depending upon the input file, requires encrypting or decrypting. The cipher used to encrypt/decrypt simply adds/subtracts an integer from each character in the input file. All input is lowercase alphabetic characters (ASCII 97-122). My problem is trying to figure out how to wrap the ciphered characters, e.g., if the cipher require a shift of +5 and the character read was 'x', a shift of +5 to the right would produce 'c' (beginning with 'x' and counting up 5 letters: 'y', 'z', 'a', 'b', 'c').
I've written some crude and cumbersome loops that will work, but there has to be a better way. It is my understanding that it can be done using the modulus operation, %, but I cannot figure out how. I spent several hours trying to figure out the modulus approach, but no luck.
I have a C program where I rapprendentare a table using a 10x10 matrix and create the chart with the game piece and the matrix in a spiral. I do not know how to start or even how to create the table with the ascii codes. is a task for school and I need to do it soon.
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