How can I convert bytes to ASCII?, I read wikipedia about UTF-8 and I understood a little bit about add or split bytes to change the value.
Now I have those bytes
0xC7 0xE6 0xC2 0x91 0x93 0x7B 0xCE 0x01
And I found a program (DCode) that convert to 64 bits little-endian, supposedly those bytes in ASCII is this.
lun, 08 julio 2013 04:28:17 UTC <---
I want to convert Hex:390041 to ascii "90A",
39: 9
00: 0 -->Null
41: A
i am getting only "9" in the bytearray,i know 0 is terminating the array
unsigned int bytes[3];
int j=0,counter=0;
char c[2];
[Code]....
I made this program to convert bits to bytes, because I'm so sick of seeing ISP's advertise speeds in megabits, which I consider an intentional attempt to decieve :P And I think I've finally understood how the return value of scanf works since the last time I posted here, so my program can check to see if an integer was entered before processing the input, but I'm stuck on how to make the whole program start over if an integer is not entered. I have a hunch it would involve a loop, but I can't figure out how to make the program start over at "How many mb do you need converted?" if an integer is not entered into scanf..Here is the code I have so far:
Code:
#include <stdio.h>
int main () {
int b, mb, kb, Byte, kB, mB, gB;
char term;
}
[code]....
and my program makes the assumption for now at least, that mb will be inputted because that's the unit of measurement that i usually see advertised, and i didn't bother making an if statement to print a conversion in terms of gigabytes because i've never heard of a connection that fast :P
How to convert bytes of data to string using c programming , I searched but i didnt get appropriate one .
Example : 112131(bytes) to string ("some sample")
I am making a text encrypter and I have to convert text into ASCII codes. I know how to convert a single character into ASCII -
#include <iostream>
using namespace std;
int main() {
cout<<"Text to ASCII converter"<<endl<<"Enter text to convert into ASCII - ";
char text; //defining input type, which is single character
[Code] ....
Try it here - URL.....Is there any way to run a similar program, which converts a string with spaces into ASCII code?
Converting ascii value entered by user.
How to convert it to float basic of c programming techniques only ....
I receive a byte stream. The first 8 bytes contain an Identification number. I receive at first the lowest byte and at the end the highest byte of the number. How can I transform this into a double value and later back into the bytestream? In the past I hard only 2 Byte values and there I could use things like MAKEWORD and HIBYTE and LOWBYTE to convert the values
View 4 Replies View Relatedi am doing an embedded project on avr microcontroller ATmega8515.actually my project is smart card based electricity billing using UART interfacing..so in this module HEX to ASCII conversion is not possible for me...
how to convert from hex to ascii.
Using C . I have been tasked (for a University assignment) to create a program that will enable a user to upload an image and convert that image into ASCII text using SDL on a Linux system. I've managed to open a window, display an image (non-selected) and convert it into grayscale using
case SDLK_g:
for (int y = 0; y < image->h; y++) {
for (int x = 0; x < image->w; x++) {
Uint32 pixel = pixels[y * image->w + x];
Uint8 r = pixel >> 16 & 0xFF;
Uint8 g = pixel >> 8 & 0xFF;
Uint8 b = pixel & 0xFF;
Uint8 v = (0.212671*r)+(0.715160*g)+(0.072169*B)/>;
pixel = (0xFF << 24) | (v << 16) | (v << 8) | v;
pixels[y * image->w + x] = pixel;
I am absolutely clueless as to how I can get the user to upload an image to the program and then begin the image -> ASCII conversion. I've found seem to be written in C++ or C# to make the conversion I should be using the GetPixelColour command?
The code is supposed to convert characters from an array into their respective ascii integers, and append a 0 if the number is less than 3 digits long. It then supposed to put it all together into one string.
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
char file[] = "This is a test";
char *ptr = file;
int length = strlen(file);
int i, numbers[length];
[Code] .....
how to accommodate double-size:8 bytes in 4 bytes pointer in 32bit system.
View 1 Replies View RelatedCode:
int i12 = 1001;
cout << i12 << " " << &i12 << endl;
gives the result: 0x7fff0d065098
It's 6 bytes, but I'd expect the address to be 8 bytes on my 64 bit machine. I am using Ubuntu 12.04, GNU compiler.
So, why the address is 6 bytes and not 8 bytes?
Im using some motors which run off PWM pins.Theres a High byte and Loq byte register (PWMH,PWML).I have an int which i need to put into these registers but i dont know how???so for example
int:84 -> PWMH=0x00 , PWML=0x54
int:310 -> PWMH=0x01 , PWML=0x36
int:11588 -> PWMH=0x2D , PWML=0x44
How many bytes in a string ....
How many bit in a string ...
How do I print this without generating errors?
Code:
printf(" ||====================================================================||
");
printf(" ||//$///////////////////////////////$||
");
printf(" ||(100)==================| RESERVE BANK OF INDIA|================(100)||
");
printf(" ||$// ~ '------========--------' $//||
[code].....
I'm confused about the actual value of 8 bytes for unsigned integers.
The below code suggests the value is 13217906525252912201:
#include <stdio.h>
#include <inttypes.h>
typedef uint64_t byte_int_t;
int main(void){
byte_int_t t;
printf("%" PRIu64 "
", t);
}
./runprogram
13217906525252912201
However, when I use a calculator, I get a different value: 2^64= 1.8446744e+19
So I was wondering is this really 8 bytes? So I try below test and it produces 8, as expected:
#include <stdio.h>
#include <inttypes.h>
typedef uint64_t byte_int_t;
int main(void) {
byte_int_t t;
printf("%u
", sizeof(t));
return 0;
}
So why does C and my calculator provide two different results?
I need to read repeatedly data from a MPEG2 file to the buffer of 188 bytes and analyse data bit by bit.
I have the problem with correct bytes reading from file. In my code listed below I have two methods for that.
First one is lossing this bytes which in hex_base mode have 0 at the begining, eg: 03, 0F, etc.
The second method based on read function which need to have buffer as a char (lenght > 1 byte). Because of that I receive different values from that from file in some cases.
How can I properly read such file?
Code:
#include <iostream>
#include <fstream>
#include <stdlib.h>
#include <windows.h>
using namespace std;
int main() {
fstream plik_in;
[Code] .....
I am encoding some information in a binary file, and I want to check what I am doing by printing out all the bytes that represent the file.
This is being done by opening a pointer to the file with fopen, reading in each byte of data as a char, and then writing this char to the screen.
I have some image files (e.g. "image.jpg"), whose structure I know, so that I can test my program.
When I print out the chars, they are initially correct, and follow the structure of the file as expected.
However, after about 40 bytes, I find that every subsequent character is ' ' i.e. a blank character.
I then created a CharToBin function, which allows me to print out the actual bits in the char. When doing this, it shows that all the bits are 1 for the characters. i.e. most of the file is represented by 1's, which is clearly not correct.
This happens on all the image files I have tested, and furthermore, on several other non-image files. They all start printing out ' ' after a while. However, all these files are fine and not corrupted, e.g. the image files display correctly.
Code:
#include <fstream>
#include <iostream>
#include <sstring>
#include <string>
#include <stdio.h>
using namespace std;
string CharToBin(char ch) {
bool bits[8];
for (int i = 0; i < 8; i++)
[Code] ....
I have a FILE stream, and I want to create a function that streams a specified number of bytes (up to four bytes) and returns the value of this, as an integar.
For example, supposing that my FILE has the following data, in hex: 74 C8 02 33 F2 7B....... I then want to stream three bytes and store this as an integar. So, I want to stream "04 08 02". The data stored in the integar should then be "00 74 C8 02", because I have not streamed anything into the first byte. By converting the hex to dec, the integar should then be of the value 7653378 (if it is unsigned).
To try to achieve this, I have written the following function. I create an integar and initialise it to zero, then take each byte from the stream, and OR it with my integar. Then, I shift the integar left by 8, and read the next byte, and so on.
The problem is, when I convert "c" to "c_int", it adds on a load of 1's to the left of the "c" data. This then means that the OR comparison changes all those bits in my integar to 1.
How to solve this? I am also wondering whether there is a much more simple way of doing this, rather than having to write my own function....
Code:
int StreamFileToInt(FILE *fp, int num_bytes) {
char c;
int c_int;
int x = 0x0000;
for (int i = 0; i < num_bytes; i++) {
[Code] ....
I have some ascii characters in a char variable.ex - char buf[100]="ab*(z&";
So each of the char in that char array will have some hex value.ex- *'s hex value is '2a'.
And I have a long long int variable in which there is a 64 bit hex value.
ex- long long int k=0x0000888888888888;
Now i want to subtract the char buff's hex value in k. How to accomplish it.
That is 0x0000888888888888
- 0x000061622a287a26
= 0x000027265e600e62 (final result in a buffer or a long variable is okay)
Later i want to reverse the result as 26e006e56272.It should be stored in a variable such that i should be able to access each byte from it(ex- '72'(last 2 hex digits))
Code:
template<class T>
class Convert {
T data;
public:
Convert(const T& tData = T()) : data(tData)
[Code] ....
Why do we use operator? Is float and double function names below?
Code:
Convert<int>::operator<float> float();
Convert<int>::operator<double> double();
while bytesremaining >=8 do something;
if bytesremaing <8 then something else .
I am new and don't know how to code for this.
and see if the first three match a list then read in three more behind those that were left and perform a similar test on them and keep going?
View 8 Replies View RelatedI'd like to know how I could break a float into individual bytes for binary use.
Sounds simple, but it seems as though the compiler doesn't realize everything is just a series of bytes.
m_sName-- character array shall be 128 bytes
How do i create a character array that has 128 bytes?
How to delete certain bytes from middle of a binary file?
Those bytes are in fact of a struct.
One approach I found was to re-write the whole data except the struct I want to delete. But may be its not good one if file size is in gb and I will have to write complete data again.