I made this program to convert bits to bytes, because I'm so sick of seeing ISP's advertise speeds in megabits, which I consider an intentional attempt to decieve :P And I think I've finally understood how the return value of scanf works since the last time I posted here, so my program can check to see if an integer was entered before processing the input, but I'm stuck on how to make the whole program start over if an integer is not entered. I have a hunch it would involve a loop, but I can't figure out how to make the program start over at "How many mb do you need converted?" if an integer is not entered into scanf..Here is the code I have so far:
Code:
#include <stdio.h>
int main () {
int b, mb, kb, Byte, kB, mB, gB;
char term;
}
[code]....
and my program makes the assumption for now at least, that mb will be inputted because that's the unit of measurement that i usually see advertised, and i didn't bother making an if statement to print a conversion in terms of gigabytes because i've never heard of a connection that fast :P
I receive a byte stream. The first 8 bytes contain an Identification number. I receive at first the lowest byte and at the end the highest byte of the number. How can I transform this into a double value and later back into the bytestream? In the past I hard only 2 Byte values and there I could use things like MAKEWORD and HIBYTE and LOWBYTE to convert the values
I am working on a project where I need to retrive a double number and store 8 bits of the number in one field and the other 16 bits in another field. the code below gives me an error.
lata= lat>>8; latb = (lat & 0xff);
The error states that & and >> are illegal for double. With this in mind, can I use these on a double. If not what can I do to achieve what I am trying to do?
(Program) a. Write a C++ program to convert meters to feet. The program should request the starting meter value, the number of conversions to be made, and the increment between metric values. The display should have appropriate headings and list the meters and corresponding feet value. If the number of iterations is greater than 10, have your program substitute a default increment of 10. Use the relationship that 1 meter = 3.281 feet.
b. Run the program written in Exercise 6a on a computer. Verify that your program begins at the correct starting meter value and contains the exact number of conversions specified in your input data.
here is what have so far
#include<iostream> #include <iomanip> using namespace std; // a programs to convert meter to feet int main() { const int MAXMETER = 10;
[Code] ....
I don't know how to have a setup where you input the values, and then will be provided the output.
I wanted to write a program to convert a number into a more readable format. It's like, if the input enters the number as 2361263 the output should be like 2,361,263. I went about this problem like extraction the number first and then if the count was equal to multiple of three i'd print ',' instead of the number.
But initially when i wrote the code for extracting a single digit from the number
Code:
#include<stdio.h> void main() { unsigned long long num=pow(2,50); int count=0; while(num!=0) { int last_digit;
[Code]....
I know that I'd lose the number when i finish printing it, but still I only end up printing the entire number in reverse order.
As in if the input is 1234 the output is 4,321 which is not what i want.
One way of overcoming this problem is to store the values in an array and then reading then back from the end. But i wanted to know if there is a better solution than this? To extract the digits from the number in the same order as it is in the number
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
I'm writting program and need to convert int ot char array without simbol. I have tryed snprintf , but his returns array full of simbols if it is initilized elsware return full of garbidge. Is there any elegent way to aceave this? What I'm trying to aceave is liek this:
char buffer[10]; int temp = 1231423; // Do conversation... // After conversation char array should look like this // 1 2 3 1 4 2 3 _ _ _ // without simbol
I need to create a conversion program to convert kilograms to pounds. The user will enter a number for weight and a char for unit of measurement K= kilo or P=pound and the program should display the other corresponding weight.
Set found to false. Set position to -1. Set index to 0. While found is false and index < number of elements If list[index] is equal to search value found = true. position = index. End If Add 1 to index. End While. Return position
//Program to convert from Fahrenheit to Celcius #include <iostream>
double fahrenToCelsius (double t); //precondition: //t is a valid tempreture in Fahrenheit //postcondition: //returns equivalent temp. in Celcius
[Code] .....
And here is the problem: [Linker error] C:UsersOwnerAppDataLocalTempcckex8SZ.o:fahrenToCelsius.cpp: (.text+0x3d): undefined reference to `fahrenToCelsius(double)' collect2: ld returned 1 exit status
I'm suspecting the program maybe that I saved it wrong? I saved it as fahrentoCelsius.cpp inside the folder "Work" ( I created this folder) which is inside the folder "Dev-cpp".
I am having a problem assigning bits a value of 0. The data is a 16 bit integer the bits greater than the 12th bit have garbage either a 0 or a 1. I would like to assign all bits greater than 12th bit the value 0 no matter what their values are. Whats the best approach.
Using the old fashioned (unsigned) multiplication instruction in x64 assembly multiplies RAX (64 bit register) by a 64 bit register. The answer is stored in RDX:RAX (i.e. the answer is 128 bits). Is there any way, using native c++ to get the value in RDX (higher 64 bits)? One I can think of is: right/(limit/left) e.g. if we are limited to a byte then 97*123 would overflow:
97/(255/123) = 46 times, which is RDX's (if it was one byte) value. But this is too inefficient. Is there a fast way?
If we use bitwise-shift to shift all bits to the right by 2, x is 0:
00000000000000000000000000000000
If we then do a bitwise leftshift on x by 30, do we end up with:
11000000000000000000000000000000 or 00000000000000000000000000000000
In other words, when we perform right shift which clips away the least most significant bits, and then do a left shift, is it possible for those bits to reappear?
I am trying to retrieve the first three bits of a number. The code that I am using should work but it isn't giving me the correct result when trying certain numbers. Below is the code I am using:
unsigned short num1, num2 = 0; unsigned short num = 65535// binary 111111111111111 num1 = num && 0x07;// gives me 1 but should give 7(111) num2 = num >>3;//gives me 8191, which is correct
Why I am not getting the first three correct bits(111)?
I have a double variable and depending on certain conditions I need to set certain bits of an unsigned short Variable. For example, if double var is odd I need to set the 15th bit of the unsigned short variable.
