I know how to find find ASCII value of given character, but I am not getting how to find ASCII value of given string. For example I want to find ASCII value of string "HELLO",so how to do that.
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My program is find non printable ASCII value(1 to 32) and calculate count from a text like "hi<tab>this<space>my text.i'm using library file here.(visual studio 2012)
removeascii.h(program name)
#pragma once
#include<stdint.h>
#include <string>
using std::string;
namespace ascii
[Code] ....
My ERROR is:
1>c:program files (x86)microsoft visual studio 11.0vcunittestincludecppunittestassert.h(65): error C2338: Test writer must define specialization of ToString<const Q& q> for your class class std::basic_string<wchar_t,struct std::char_traits<wchar_t>,class std::allocator<wchar_t> >
[Code] ....
how can I find ASCII value (0..255) of a character char in a string?
I have an array of char:
Code: char myarray[50]; and I need to have ASCII value of character eg myarray[10]. How can I do that?
I need to make program which converts text (letters and digits only) into 7-digit ascii code. The start and end code is "1100011", so it must not appear inside the output code, thus a zero should be added in it (11000011).
Not that it matters much what my task is - I have a problem. Here's the code:
Code:
#include <iostream>
#include <stdlib.h>
using namespace std;
int main() {
string in,out="",pk="1100011";
getline(cin,in);
[Code] ....
The 'pk' string loses its value here when I enter a character in the input and I cant figure out why... I got that the problem is somewhere in the first if loop, since the code prints pk nicely when cout is before the loop (comment 1)..however, after the loop (comment 2) it prints nothing..... When compiled, it works nice when I input numbers, but 1 character - and 'pk' disappears...
bool isQstr(string const& str)
{
size_t found = str.find(""");
return found != string::npos;
}
/*
I am trying to check whether a string contains a quoted string, I used the escape character but it does not even recognize it*/
So the program reads contents from a text file into a vector and then the user enters in a string that they want to search for. The program iterates through the vector to find the string and then saves that line to another vector to display later(incase there is more then 1 instance of the string found).
Here is what I have atm:
void doSearch(vector<string> &phonelist, string searcher, vector<string> &holdNumbers)
{
int i = 0;
string value;
[Code].....
I just get an R6010 error -abort() has been called.
int t;
string a;
cin>>t;
getline(cin,a);
int len=a.length();
cout<<a<<" "<<len;
[code].....
why is the length 0?what can I do to get the correct length of the input string?
I am stuck here.
printf(" Enter a line of Morse Code for decrypting");
scanf("%s",phr);
len=strlen(phr);
for(a=0;a<36;a++) {
if(strcmp(phr, morse[a])==0)
printf("%c", alpha[a]);
};printf(" ");
The output :
[output] Enter line to encrypt:
..... -.... --...
converting...
5 [/output]
It should read all code, including null. between coded letter one space, between coded word three spaces.
The output should be:
[output]
56 7 [/output]
I am stuck in some logic and want to write a program to do following tasks : I have three string variables to be compared to each other,a string having sub string & hierarchy string!!
1.) name1=john name2=tom_john_tom name3=alextom_john
thus we need to search john from name2 and name3 and if name1 exists in both name2 and name3 then ok else check for step2
2.) name1=a.b.c.d ,name2=a.b.c.d and name3=a.b.c.d
we need to compare each string seperated by a dot in all three variables and we need to match each string seperated by a delimeter "."
if name1.a==name2.a==name3.a and name1.b==name2.b==name3.b ,name1.c==name2.c==name3.c and name1.d==name2.d==name3.d then its a match
else its a mismatch
Also,the catch is we can have name1 ,name2 and name3 in format name1=*.*.*.* and name2=*.*.*.* and name3=*.*.*.*
where * defines it can be any value to be matched
name1=government.india.public.property
name2=rural.roads.maximum.x
name3=government.india.public.sales
name4=rural.roads.minumum.x
If operator wants to match only the second field , then the logic should be like:
If the Value is to be matched = (*.#.*.*)
then "matched"
Else
its a mismacth
# => for this field of name2 and name3 shall be same
* => for this field name2 and name3 shall be ignored for comparison
to obtain option1 we can have find function and substr however pls suggest how to approach for second option !!!!
I got a homework that require to count number of words in a text file and also display the first and last 10 words of the text file to the console. I have finished the counter problem and now I struggle showing the first and last 10 words.
#include <iostream>
#include <sstream>
#include <string>
#include <fstream>
using namespace std;
int tokenize(string sentence, string tokenizedWords[]);
[code]....
I need to find position of certain character in string, so i made a function but it doesn't do what i thought it would.
Consider this string:
std::string line = "<foo> <foo> <foo> <foo> <foo>"
I need to find position of a third '>' character so i can get:
std::string other = "<foo> <foo> <foo>";
This is my function that fails:
std::size_t find_third(const std::string& line) {
std::size_t pos = 0u;
for(std::size_t i = 0; i < 3u; ++i) {
std::string tmp = line.substr(pos);
pos = tmp.find_first_of('>');
} return pos;
}
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
void findPalind(char *arr) {
int i,j,n,odd,flag=0,count[26]={0};
[Code] ....
This question was asked in Hackerrank. [URL] ....
I am able to get correct output upto a input of 50000 character string, but not for 100000 character string.
I can't find the highest digit within c-string. Ithe user was to enter 1234. the highest shall be 4 but can't get that number.
int Hnum(char* str) {
//int size = 0;
int H = 0, remainder, div =0;
int intstr = atoi(str);
[Code] ....
How to find the last longest word in a string when there are more of them (with the longest size)?
Here is the program for the longest without checking if last:
#include<stdio.h>
#include<string.h>
int main() {
char a[50],b[20],c[20];
int i,j=0,l=0;
printf("Enter a string:
");
gets(a);
[Code] ....
The code shows all characters frequency, however i want to find which one has highest frequency
For example cprogrammmmming cboard
highest frequency: m
Code:
char string[100], ch;int c =0, count[26]={0};
printf("Enter a string
");
gets(string);
[Code] ....
i have a text file... with example following content:
Pizza 23232
Car 44,495
Drink 3493,90494
....
..
.
and so on..
no i want to find the 44,495 in this textfile.. calculate a new value like 44,495 x 2 + 5
and write the same file as
Pizza 23232
Car 93,99
Drink 3493,90494
....
..
.
back..
I'm trying to figure out the word frequency of a user inserted string. I've tried doing it via getline of the struct array and via the getline of the string word but neither either the former crashes or the latter just prints out the whole string.
Here is the latter.
#include "stdafx.h"
#include <iostream>
#include <string>
#define MAX_WORDS 200
using namespace std;
[Code] ....
How to handle the array of structs.
Whats wrong with my program ? It always says that coundn't find match operator ? What can i do ? I want to multiply string pay to int HOURS.
#include<iostream>
#include<fstream>
#include<string>
using namespace std;
int main () {
system("color 8e");
string ID,name, address,No, pos ,pay, hanap;
string hours;
[Code] .....
This program is to solve a word maze and find the number of words in the maze from a dictionary file.
The program runs, but stops by finding 1,2 and 3 letter words.
#include<iostream>
#include<vector>
#include<fstream>
#include<algorithm>
#include<string>
using namespace std;
int main() {
vector <string> dict,forward,reverse;
[Code] .....
I also tried to find words using the entire vector as a container, the synopsis code that also did not work is below
while(j<dict.size()) {
if(dict[j].size()>2) {
if (std::find(forward.begin(), forward.end(), dict[j]) != forward.end()) {
cout<<"found word "<<dict[j]<<endl;
[Code] ....
Attached File(s)
dumpling2.txt (2.54K)
Dictionary.txt (718.34K)
I have a question about finding the length of first sentence in an input string.
For example, let the input string be: dream in code. community learning
The length of first sentence is 13 (blanks are included). My question is how to create conditions for multiple punctuation signs (!,?)? If while loop goes like:
while((str[i]!='.')||(str[i]!='!')||(str[i]!='?'))
it gives me an error for infinite loop.
Code:
#include<stdio.h>
int main() {
char str[100];int i=0,br=0;
printf("enter a string:");
gets(str);
[Code] ....
I need a code that will search through string 1 and find the first place with a letter that also appears in string 2 and return the pointer of that place. This is what I wrote:
char strPbrk(const char *s1, const char *s2) {
char p = *s1;
for (int i = 0; i < strlen(s1); i++)
for (int j = 0; j < strlen(s2); j++)
if ((p+i) == *(s2+j))
return p;
return NULL;
}
but it continues to return wrong values idk what I'm doing wrong.
I'm trying to use the find string to erase a ' ' from the end of a word. I tried something along the lines of:
if (SecondSide.find('
')!= string::npos)
SecondSide.erase(SecondSide.find('
'));
but it had no effect.
I need to find 2 similar words in one sentence and i need to find how much symbols are between these two words. I can't figure out the algorithm.
For example sentence would be-
This is nice table and nice chair.
Similar words are- nice
Symbols between them are 11 or 8(dont know if space is count as symbol)
int main()
char text[200],*dist;
printf("Enter one sentence
");
gets(text);
Maybe first of all would be
dist=strtok(text, " ,.!?");
while(dist!=0)
{
printf("%s
", dist);
dist=strtok(NULL, " ,.!?");
}
and it wil output each word and maybe then can search for similar words if there would be 2 strings then i would use strstr but i dont know how to do with one string.
<IMG border=0 alt="UserDeviceId = 70813215">
Above is the sample string object from this i need to find the integer value of UserDeviceId.
write a C program which repeatedly reads in sentences from the user and reports on how many capital letters are in the sentence and how many punctuation characters. Your program will stop asking for input once the user has entered in a blank line. Consider the following example usage with the program. User input is marked in underline:
Enter a sentence: John and Mary went to Fred's house.
You used 3 capital letters and 2 punctuation characters.
Enter a sentence: I like A&W more than McDonald's.
You used 5 capital letters and 3 punctuation characters.
Enter a sentence:
Good bye!
Hint: make use of the standard C functions ispunct and isupper. Other requirements. You must make two functions.
Make a function called find_characters, which has a return type of void, and which has three parameters: one of type char * (a string to find characters in), one of type int * (a reference to int variable indicating how many capital letters are in the string) and the last one also of type int * (a reference to an int variable indicating how many punctuation characters are in the string). Your find_characters function should scan the string and update the two variables it has references to.Make a main function.
This function should repeatedly read in a string from the user, call your find_characters function, and output the information returned to it by the find_characters function indicating how many capital letters and how many punctuation characters were in the string. Your main function should stop reading in input when the user enters in a blank string (i.e., the user just hits enter without entering anything else in). You may assume that the user will not enter in a sentence longer than 100 characters
Code:
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<string.h>
int main(void) {
[Code] .....
I need a simple adjacent_find() to find the adjacent same letter in a randomly generated string?
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