The output of this short program is really weird. When I type 123 from the keyboard,I get the following answer in console window"123 length=4".Why the output of length is always 1 more than the actual length of the string that I type in.
I am trying to read all the 9 letter words in a words list text file and print them to the screen. Here is the code I have so far, but I am currently printing nothing.
Code:
#include <stdlib.h> #include <stdio.h> #include <string.h> int main() {
Currently I am doing the first exercises from Illustrating C. The exercise that I am trying first is the one where someone can input degrees and the program will be able to put those in to sin or cos. Im trying to use fgets to take input from the user. the answer can only be sin or cos. Im having trouble with how to get it to work.
My goal is to have the output of the choice sin or cos. Store that choice. proceed to ask what the degrees are from the user. then i would have the degree input multiplied by pi/180 converting it to radians and having the program compute it that way
Code:
#include <stdio.h> #include <math.h> #include <string.h> int a; int main() }
With my input.txt file being Code: abcd efgh And in particular, there is no new line after the letter h, but when I print out the text string, I get a new line after h. Why is this?
I am trying to write a terminal-like chat application in Linux. I would like to use a FIFO queue to print out the messages in terminal. The queue would be populated from 2 sources- stdin and messages sent from the other user over TCP. I have meet an obstacle that I cannot handle...
Lets say I would like to take user input using fgets and put it into a buffer. Then queue it if the buffer is not empty or print if it is. The problem is that when I use fgets or scanf, my input is instantly printed to the terminal..If i do:
Code:
fgets(message, 100, stdin); printf
("%s", message The string under message is printed twice :|. Is there a way to prevent this?
i am trying to read a string using fgets and storing in an array i want to prevent fgets from storing the new line character on the array using the shortest means possible..
I'm new to C/C++. I am attemping to use fgets and sscanf to read a line of input, and confirm it is a positive number.My code works great, except for the case of a negative number. When I enter a negative number, my while loop seems to run infinitely, with stdin providng the same input over and over again.
How can I make fgets stop reading when it reaches a new line? Right now it will read the new line and continue until the buffer is full. I was thinking something like this.
In the assignment we are forbidden to use fscanf(). I have been trying to get this to work, but I've started to realize that I do not have a complete understanding of what strtok() actually does. I'm getting this warning when debugging: "assignment makes integer from pointer without cast."
This warning happens when assigning str to goal and assist, and I think it is because they are, when dereferenced, integers. The code below correctly assigns the name into the correct spot, but leaves nonsense data in the goal and assist arrays.
ex:-7880, -7888 file example: NAME GOALS ASSISTS JOHN 1 2
Code: void readLinesFromFile( FILE* Ptr, int* goal, int* assist, char** name, int lines ){/* * Reads lines from files and populates the arrays with the corresponding info. */ int index; char hold[ MAX_LINE ] = { 0 }; char* str = NULL;
[Code] .....
From what I understand about strtok(), it returns a string, and takes in a character array and a key value that tells it when to stop. In the online examples I've seen, they use NULL in the first field. I'm not sure why.
int check_up(char string[]); int check_low(char string[]); void to_up(char string[]); void to_low(char string[]);
[Code] .....
When I compile this I have the following problems: warning: data definition has no type or storage class [enabled by default] in 'to_up(word)'conflicting types in 'to_up' function and to_low function warning: data definition has no type or storage class [enabled by default] into_up function error: unknown type name "word" in line 'printf("All uppercase %s. ", word):;'warning: parameter names (without types) in function declaration [enabled by default] in 'to_up(word)'and 'to_low(word)' 'note: previous declaration of "to_up" was here in function declaration of to_up function
I'm using fgets which will read a single line at a time, but unlike fgets I don't want it to return the new line char ( ) ?I want to be able to use printf to display the lines next to each other.
I'm trying some codes about string arrays and taking array length. But i have some problems. I can't get length of string and can't send to a function.
------------------------ #include<iostream> #include<cstring> #include<string> using namespace std; void GetLength(string); std::string Words[]={"table","gun","programming"}; int main() {std::string InputWord;
binary [] is the char array and count is... you know how many times the for loop will turn. So my question is, how do i know the length of the number ? Any function that shows the integer length ? because its impossible to know what count is equal to. like 100 is 3.
I need to be able to find every possible permutation using all possible values of a char. But I have to make it be able to form permutations from a length of 1 to variable N. For example, if N=3, I need it to be able to come up with
How could I do this. (I would like to avoid recursion, since N might be as large as 50 or 60 and using recursion would most likely cause a stack overflow)
I'm working with arrays that might have NULL bytes in them and I'm wondering how to determine the length of the array or store it somewhere with the array (strlen() won't work because of the NULL, right?).
I've found advice like store the length of the array in the first byte of the array, but since sizeof(size_t) is 8 should I leave the first 8 bytes for the length?
Would it be better do define my own structure which would store the array and its length? What's the usual way these things are handled in practice?
I was reading in a book I had about C that an array has at the very end a "null character" signifying the end of the string inside it, "/o". So that made me think, "I guess one needs to declare arrays as having 1 extra space than one expects the array to need. I wonder what will happen if I exceed the array length?" So I made a program to test it out. Here is the program/results:
Code:
#include <stdio.h> int main(void){ char name[3]; printf(" What's your name? "); scanf("%s", name); }
[code]....
As you can see my name was able to fit in the array somehow even though I only allocated 3 bytes to the array. I tried again using my legal first name, Benjamin, and it was still able to fit. How is the array able to hold my name when I declared it as only having 3 bytes?