C++ :: Find Every Permutation With Length From 1 To N?
Jan 29, 2015
I need to be able to find every possible permutation using all possible values of a char. But I have to make it be able to form permutations from a length of 1 to variable N. For example, if N=3, I need it to be able to come up with
0x00
0x01
.......
0x00 0x00
0x01 0x01
.......
0xff 0xff 0xfe
0xff 0xff 0xff
How could I do this. (I would like to avoid recursion, since N might be as large as 50 or 60 and using recursion would most likely cause a stack overflow)
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Jul 6, 2014
int t;
string a;
cin>>t;
getline(cin,a);
int len=a.length();
cout<<a<<" "<<len;
[code].....
why is the length 0?what can I do to get the correct length of the input string?
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Dec 15, 2014
I am stuck here.
printf(" Enter a line of Morse Code for decrypting");
scanf("%s",phr);
len=strlen(phr);
for(a=0;a<36;a++) {
if(strcmp(phr, morse[a])==0)
printf("%c", alpha[a]);
};printf(" ");
The output :
[output] Enter line to encrypt:
..... -.... --...
converting...
5 [/output]
It should read all code, including null. between coded letter one space, between coded word three spaces.
The output should be:
[output]
56 7 [/output]
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Sep 25, 2014
I am working on a c-programm. In this program I have to convert the amount of money I read on two variables into the corret format. I got Euros and cents on 2 ints. But now I want to add both of those variables in a String (char array). Also i want to find out the length of the new char array.
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Jul 21, 2013
Ok my assignment has me doing vector math with some canned code provided for me by the instructor This is the header file to the class I'm working with and the .cpp file as far as I've gotten it.
#pragma once
#include "Scalar.h"
class Vector2D {
public:
Vector2D();
Vector2D( const Vector2D& ) ;// copy constructor
Vector2D( Scalar element[2] ) ; // initialize with an array
[Code] ....
I'm having trouble seeing which data members I'm multiplying together and what the initial state, continuing state, and after loop action I'm supposed to be using in the for loop.
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Jul 24, 2014
I'm trying to find vertical paths of length n through a 2D grid of numbers. Paths may connect orthogonally or diagonally. An example grid and an example possible path looks like this:
//Grid
0 1 2 3 4 5 6 7
0 2 4 6 4 1 3 4 5
1 5 3 5 8 6 6 6 6
2 3 4 2 1 1 2 5 3
3 3 2 3 3 1 3 4 5
4 3 6 1 1 5 2 5 4
5 2 5 4 2 4 5 6 2
6 6 6 1 1 5 1 4 5
7 1 5 6 4 2 4 2 3
A example possible path of length n = 3 is running from (3,2) to (3,4) - All 1s ...An example of n = 4 is the run of 3s (1,1) (0,2) (0,3), (0,4)
What is an efficient algorithm for solving this kind of problem? I would like to solve (ideally) millions of grids, giving a list for each grid of all possible paths of length for n = 3-6.
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Feb 13, 2015
I have a question about finding the length of first sentence in an input string.
For example, let the input string be: dream in code. community learning
The length of first sentence is 13 (blanks are included). My question is how to create conditions for multiple punctuation signs (!,?)? If while loop goes like:
while((str[i]!='.')||(str[i]!='!')||(str[i]!='?'))
it gives me an error for infinite loop.
Code:
#include<stdio.h>
int main() {
char str[100];int i=0,br=0;
printf("enter a string:");
gets(str);
[Code] ....
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Nov 7, 2013
I got a permutation question, I got two different std::list:
list<string> slist;
slist.push_back("str111");
slist.push_back("str222");
slist.push_back("str333");
list<int> ilist;
ilist.push_back(100);
ilist.push_back(200);
I need the permutation for both two lists, the result should be like this:
#include <iostream>
#include <string>
#include <list>
#include <algorithm>
using namespace std;
template <typename value_t>
void dump_list(const list<value_t>& lst) {
[Code] ....
See, there are two do while loop, if I need a permutation with more than two lists, there'll be more and more do-while loops, that's make code looks ugly, I wonder if stl has some tricky way that can do this with just one next_permutation.
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May 11, 2013
I wrote this code to solve a problem in which the user inputs a permutation of size 'N' and the next permutation of the same elements has to be generated.
I went about this in this way: given 3 2 5 4 1, starting from the right, the first no. has to be searched which has a no. greater to it on its right. Here it is 2. Now an array is generated containing all no.s on its right and greater than it. For 2, it is: 5,4. Out of these the smallest member is searched for and switched with 2. So, 4 is switched with 2 to get the Next Permutation: 3 4 5 2 1.
The code I wrote does not show any error but does not return the correct value when run and gives the same value instead. If I enter '3 2 5 4 1' it returns the same value as the answer.
#include<iostream.h>
#include<conio.h>
void main() {
clrscr();
int N,M,i,n,c,swap,flag,count,small,m;
int Array[100],Key[100];
[Code] .....
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Aug 10, 2013
#include <iostream> // std::cout
#include <algorithm> // std::next_permutation, std::sort
int main () {
int myints[] = {1,2,3};
std::sort (myints,myints+3);
std::cout << "The 3! possible permutations with 3 elements:
[Code] ....
this will result
123
132
213
231
312
321
The question is : If I want to get a permutation combination with range of N
What should i do?
if N = 2
result should be 12,13,21.....such and such
Eliminate the last digit is working for 3 combination but if its going to a bigger number it does not work ...
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Jan 17, 2015
I need to create such a function that the content of the first is put into the second, the content of the second into the third and the content of the third into the first.
For example, output should be like this
3
2
1
But the code below prints out:
1
2
2
Where am I making a mistake?
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <math.h>
#include <ctype.h>
[Code]....
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Feb 16, 2013
I'm currently working on assignment which requires to generate a random permutation of the first N integers. For example, if N = 4, one possible answer is {3,1,2,4} without duplicates. {3,3,2,4} is not correct
to fill a[4], generate random numbers until you get one that is not already in a[0], a[1], ..., a[n-1]. for a[0] whatever random number you generate can be put in it. So here is my code. It seem to works but sometime it give duplicates.
#include <iostream>
#include <stdlib.h>
#include <time.h>
[Code].....
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Mar 27, 2014
I have been given an assignment that has to do with permutations. I am suppose to read a text file that contains the permutation rules and the text to be "permutated", and then output the rules and the new text into an output file.
So far, I've gotten this:
Code:
# include <stdio.h>
void printArray(FILE* file, char* array, int maxSize)
{
int i;
for (i = 0; i<maxSize; i++)
fprintf(file, "%c", *(array + i));
[Code] ....
Here is what the input file looks like:
Code:
0 1 2 3 4 5 6 7 8 9
4 5 6 0 9 7 8 1 2 3
Moderation in temper, is always a virtue; but moderation in principle, is a species of vice.
Here is what the output file is suppose to look like:
Code:
0 1 2 3 4 5 6 7 8 9
4 5 6 0 9 7 8 1 2 3
ratMnioodetem rpein al,ywa isvirsetu a t m;eod
buon r inaticipp,lerina s cpeis of icvies - Temho.
-ainaPes
The first two lines are the permutation rules. Currently I have figured out how to read the file into an array and then print it back out into a text.
What I want to do is figure out how to read only the first two line of the input file and store that as a permutation rules, and then continue reading the rest of the input file and store that separately as the text to be "permutated". And then eventually figure out how to apply the permutation to the text.
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Feb 16, 2014
I need to create a function with the following prototype:
bool isPermutation( const unsigned a[], unsigned elements );
unsigned a[] = {3, 0, 2, 1};
bool P1 = isPermutation( a, 4 );
would set P1 to true because the set of subscripts is {0, 1, 2, 3}, and the values are just a reordering of those values. On the other hand,
unsigned a[] = {3, 0, 2, 3};
bool P2 = isPermutation( a, 4 );
would set P2 to false because the set of subscripts is {0, 1, 2, 3}, but there’s no value that’s equal to 1.
I'm not exactly sure how to do this. I thought about it a couple different ways. I first thought about taking the range (max/min) and then checking to see if the numbers in between are equal from each other, distance-wise.
I then thought that I should just make this basically a sort function (I used bubble-sort), and then to just check if the numbers are equi-distant from each other.
This is my basic bubble-sort. Perhaps it is wrong, but I'm not certain...Perhaps I am making this function harder than it has to be.
unsigned temp = 0;
for (unsigned i = 0; i < elements; i++){
for (unsigned k = 0; k < elements-1; k++){
if (a[k] > a[k+1]){
temp = a[k+1];
a[k+1] = a[k];
a[k] = temp;
}}}
Should I do a sort like this, and then do something where I subtract a[i+1] - a[i], and see if that equals '1'?. I would think that would mean they would have to be equidistant. Even if this is correct, I feel like it could be more efficient.
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Mar 21, 2014
Write a function that computes and returns the score for a permutation, i.e. the number of reversals required to make arr[0] == 1.
HAVE TO USE FOLLOWING FORMAT:
Code:
// POST: Returns the number of reversals needed to make arr[0] == 1
// if the reversal game were played on arr
// Note: If arr[0] == 1 initially, then score(arr, n) returns 0 AND this is what i could muster;
[code]....
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Nov 12, 2014
Exception Details: System.ArgumentOutOfRangeException: Length cannot be less than zero. Parameter name: length
using System;
using System.Data;
using System.Configuration;
[Code]....
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Nov 20, 2013
I'm trying some codes about string arrays and taking array length. But i have some problems. I can't get length of string and can't send to a function.
------------------------
#include<iostream>
#include<cstring>
#include<string>
using namespace std;
void GetLength(string);
std::string Words[]={"table","gun","programming"};
int main()
{std::string InputWord;
[Code]...
And how can send Matrix to other function?
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Oct 3, 2013
The programming problem is supposed to take a decimal number from a user and turn it into a binary number. Here is my code:
for (int i=0; i< count; i++) {
binary[i] = decimal % 2;
decimal = decimal/2;
} cout << binary[2] << endl;
decimal is the number entered by the user.
binary [] is the char array and count is... you know how many times the for loop will turn. So my question is, how do i know the length of the number ? Any function that shows the integer length ? because its impossible to know what count is equal to. like 100 is 3.
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Apr 16, 2013
I'm working with arrays that might have NULL bytes in them and I'm wondering how to determine the length of the array or store it somewhere with the array (strlen() won't work because of the NULL, right?).
I've found advice like store the length of the array in the first byte of the array, but since sizeof(size_t) is 8 should I leave the first 8 bytes for the length?
Would it be better do define my own structure which would store the array and its length? What's the usual way these things are handled in practice?
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Apr 20, 2013
Code:
char line[BUFSIZ];
while ( fgets(line, sizeof line, file) != NULL ){
llen = strlen(line);
printf("%d - %s
",llen,line);
}
I get a full line printed but my llen is the size of my buffer. how do i get the total size om my line from the beginning to " "
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Feb 9, 2014
I was reading in a book I had about C that an array has at the very end a "null character" signifying the end of the string inside it, "/o". So that made me think, "I guess one needs to declare arrays as having 1 extra space than one expects the array to need. I wonder what will happen if I exceed the array length?" So I made a program to test it out. Here is the program/results:
Code:
#include <stdio.h>
int main(void){
char name[3];
printf("
What's your name?
");
scanf("%s", name);
}
[code]....
As you can see my name was able to fit in the array somehow even though I only allocated 3 bytes to the array. I tried again using my legal first name, Benjamin, and it was still able to fit. How is the array able to hold my name when I declared it as only having 3 bytes?
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Nov 23, 2013
Any good function that get the length of an integer in C++
I do know of str.length(), however i want something similar for integers
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May 24, 2013
i having a code to pass in array as argument, but the length returned is 1. This is not match with the array size.
int Getsize(int Array[])
{
int len = sizeof(Array)/sizeof(int);
cout << len << "
";
}
int main()
{
int X[] = {45, 12, 54, 83, 41, 36};
getsize(X);
}
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Oct 5, 2014
im new to c++ ,so my question is how do i change a length of a text. for example hi my name is blah blah blah. nice to meet you. (n i want every lines to have 8 chars how do i do that)
(hi__my__
name_is_
balh____
blah____
blah____
._nice__
to_meet_
you.) (_ equal space)
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Sep 7, 2013
I can't find any method of retrieving the length of an array except for doing this:
string first[] = {"a","be","see"};
int length = sizeof(first)/sizeof(first[0])
This is a very unconventional way of getting the length of an array.
first->length() would return 1 because it returns the number of letters in the first element of the array (which actually makes no logical sense).
first.size() would return 1 aswell as it's practically the same thing.
Since getting the length of an array is such a fundamental feat, how come I can't find a decent method of doing it?
Is there no buildt in method for this? If there is not, why has it not been implemented in the std?
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May 28, 2013
The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 255 characters.
it said 1 to 255 characters
i have to use getline(cin,str);
i tried str[255] but some error happen
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