I'm trying some codes about string arrays and taking array length. But i have some problems. I can't get length of string and can't send to a function.
------------------------
#include<iostream>
#include<cstring>
#include<string>
using namespace std;
void GetLength(string);
std::string Words[]={"table","gun","programming"};
int main()
{std::string InputWord;
[Code]...
And how can send Matrix to other function?
I would like to understand a function on strings. Below is a code that I took from my teacher where the user inputs a string and prints out the length of the string.
Code:
#include <stdio.h>
#include <string.h>
int main() {
char str[100];
int i = 0;
[Code] ....
Now I understand that it returns the count in "int" so my question is:
Let's say i declared
Code: int count = 0;
at the beginning of the code and then made
Code: count = strlen(str);
why wouldn't i have the same result? Is there a way to do it also?
In this code, i declared a string constant and trying to print the length of string. I know that if i write char a1[7] or char a1[] than it runs and give aggregate output, but in this case it is giving double length of string.
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
}
[code]....
int t;
string a;
cin>>t;
getline(cin,a);
int len=a.length();
cout<<a<<" "<<len;
[code].....
why is the length 0?what can I do to get the correct length of the input string?
I can't find any method of retrieving the length of an array except for doing this:
string first[] = {"a","be","see"};
int length = sizeof(first)/sizeof(first[0])
This is a very unconventional way of getting the length of an array.
first->length() would return 1 because it returns the number of letters in the first element of the array (which actually makes no logical sense).
first.size() would return 1 aswell as it's practically the same thing.
Since getting the length of an array is such a fundamental feat, how come I can't find a decent method of doing it?
Is there no buildt in method for this? If there is not, why has it not been implemented in the std?
The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 255 characters.
it said 1 to 255 characters
i have to use getline(cin,str);
i tried str[255] but some error happen
I am stuck here.
printf(" Enter a line of Morse Code for decrypting");
scanf("%s",phr);
len=strlen(phr);
for(a=0;a<36;a++) {
if(strcmp(phr, morse[a])==0)
printf("%c", alpha[a]);
};printf(" ");
The output :
[output] Enter line to encrypt:
..... -.... --...
converting...
5 [/output]
It should read all code, including null. between coded letter one space, between coded word three spaces.
The output should be:
[output]
56 7 [/output]
consider the following code:
string input;
getline( std::cin, input )
In the code above, what is the maximum number of characters that can be read into variable input?
Any way to get the length of a string? I have tried:
str.length
str.size
strlen()
Bob
Code:
// Exercise in string manipulation
#include <iostream>
#include <string>
void prtname(std::string str);
using namespace std;
int main() {
[Code]...
Well what the title says, but I can't get it done. This is what I got
Code:
#include <stdio.h>#include <string.h>
int main(void)
{
char word;
int count;
printf("Enter a word.
[Code] ....
I manage to split this str = "abc,def,123"
to s1 = "abc", s2 = "def", s3 = "123" with this piece of code using find and substr.
string str, s1, s2, s3;
getline(cin, str);
unsigned pos1 = str.find(",");
[Code] ....
But what should I do if the len of the string is unknown ?
For example, str = "abc,def,123,ghi,jkl,456,mno" and so on...
how to define a string of undefined length in c programming?
View 1 Replies View RelatedPHP Code:
int processString(xxx)
{
//do something
return non-null terminated string length
}
To make the function work better we change its internals
PHP Code:
int processString(xxx)
{
//do something
return null terminated string length
}
This phenomenon can be observed by use of mutibyte to wide char conversions, string copy , concatenation functions of MS etc ....
Should I minus one in the return value of the second function to match both versions ?
What I'm trying to do is to assign the length of a string to an integer variable. This is what i tried, it did not work.
Code:
printf("Enter a string
");
fgets(test_pass, 30, stdin);
strcpy(x,(strlen(test_pass)));
printf("%d", x);
This was just a test, and it did not compile. How to do this?
I want to read a string of unknown length from stdin. I tried to follow the approach from this link. URL....My code is like this:
#include <iostream>
#include <string>
using namespace std;
int n;
cin >> n;
cout << "The value of n is " << n << endl;
}
[code]......
What I have noticed is that if I take integer input from cin (cin >> n;) in the above code before getline, the control does not stop on getline to take str as input from the console. If I don't do (cin >> n) before getline then the control stops on getline and takes the string as input.What is the best way to read from console multiple strings of unknown length in combination with the integers?
The error is unclear but suggests Its received a bad pointer from another heap. It references dbgheap.c line 1322 and assertion failure
I have two string vector functions the first is called from the main function, the second is called from the first.
Their purpose is to receive a string of text and numbers in a semi-specific format, which the main body of the code reads from a text file, and delaminates the data as to return the first variable in the string as the variable name and the second as the variable value. Along the way it filters out a lot of the unwanted whitespace and punctuation.
E.g "{ VariableNameA 123 }" would be returned as "VariableNameA" And "123"
The code works perfectly for most of the lines in the text file but fails on one particular line where the first variable is 25 characters long. Basically it works for anything 22 characters or less. There are never more than 4 elements in the vector and each element is never intended to be longer than 25 characters.
It fails trying to return from the second split function to the first split function.
Is there a limit to the size of each vector element? I'm struggling to find a way round this without having to rewrite the whole thing.
vector<string> split(const string &s, char delim) {
vector<string> elems;
split(s, delim, elems);
return elems;
[Code] ....
I need to know if it is possible to show the maximum length that is defined a string. I explained it with a example
void charLong(char *a){
cout <<"a defined max long = "<<a-><FUNCTION>;
} int main() {
char str[40];
charLong(&str);
return 0;
}
That the result was : a defined max long = 40.
I know that exist strlen() but this show only the length that is used, I need the definition length. is it possible?
I have a question about finding the length of first sentence in an input string.
For example, let the input string be: dream in code. community learning
The length of first sentence is 13 (blanks are included). My question is how to create conditions for multiple punctuation signs (!,?)? If while loop goes like:
while((str[i]!='.')||(str[i]!='!')||(str[i]!='?'))
it gives me an error for infinite loop.
Code:
#include<stdio.h>
int main() {
char str[100];int i=0,br=0;
printf("enter a string:");
gets(str);
[Code] ....
I want this program by using only iostream.h & conio.h
View 4 Replies View RelatedException Details: System.ArgumentOutOfRangeException: Length cannot be less than zero. Parameter name: length
using System;
using System.Data;
using System.Configuration;
[Code]....
The programming problem is supposed to take a decimal number from a user and turn it into a binary number. Here is my code:
for (int i=0; i< count; i++) {
binary[i] = decimal % 2;
decimal = decimal/2;
} cout << binary[2] << endl;
decimal is the number entered by the user.
binary [] is the char array and count is... you know how many times the for loop will turn. So my question is, how do i know the length of the number ? Any function that shows the integer length ? because its impossible to know what count is equal to. like 100 is 3.
I need to be able to find every possible permutation using all possible values of a char. But I have to make it be able to form permutations from a length of 1 to variable N. For example, if N=3, I need it to be able to come up with
0x00
0x01
.......
0x00 0x00
0x01 0x01
.......
0xff 0xff 0xfe
0xff 0xff 0xff
How could I do this. (I would like to avoid recursion, since N might be as large as 50 or 60 and using recursion would most likely cause a stack overflow)
I'm working with arrays that might have NULL bytes in them and I'm wondering how to determine the length of the array or store it somewhere with the array (strlen() won't work because of the NULL, right?).
I've found advice like store the length of the array in the first byte of the array, but since sizeof(size_t) is 8 should I leave the first 8 bytes for the length?
Would it be better do define my own structure which would store the array and its length? What's the usual way these things are handled in practice?
Code:
char line[BUFSIZ];
while ( fgets(line, sizeof line, file) != NULL ){
llen = strlen(line);
printf("%d - %s
",llen,line);
}
I get a full line printed but my llen is the size of my buffer. how do i get the total size om my line from the beginning to " "
I was reading in a book I had about C that an array has at the very end a "null character" signifying the end of the string inside it, "/o". So that made me think, "I guess one needs to declare arrays as having 1 extra space than one expects the array to need. I wonder what will happen if I exceed the array length?" So I made a program to test it out. Here is the program/results:
Code:
#include <stdio.h>
int main(void){
char name[3];
printf("
What's your name?
");
scanf("%s", name);
}
[code]....
As you can see my name was able to fit in the array somehow even though I only allocated 3 bytes to the array. I tried again using my legal first name, Benjamin, and it was still able to fit. How is the array able to hold my name when I declared it as only having 3 bytes?
Any good function that get the length of an integer in C++
I do know of str.length(), however i want something similar for integers