C/C++ :: Program That Uses The Radius To Get Area?
Apr 28, 2012How can i come up with a program that uses entered radius of a circle to find its area
View 1 RepliesHow can i come up with a program that uses entered radius of a circle to find its area
View 1 Repliesi have written a program to find area of triangle, but i meet some errors,
//******area of triangle******//
#include<iostream>
using namespace std;
[Code].....
I trying to write a program that calculates the area and circumference of a circle.
This is what I wrote so far.
Code:
#include <stdio.h>
void main()
{
int r;
int pi=3.14159265;
float cir,area;
printf("
enter the radius of the circle ");
[Code]...
the Problem is when I input the radius the answer I get is zero regardless of the the radius. Am I missing something?
B. Circle in a Square Write a C++ program that will ask the user to enter the area of a square. Then the program will display the biggest area of a circle that will fit in a given square. Using math.h library is not allowed.
View 1 Replies View Relatedwrite a C++ program to find the area of a square, input the length of the side, and output your answer to the screen.
View 3 Replies View RelatedI got an assignment at school asking for a program that can implement functions that store, get and deletes text/binary data to a given memory area. We are supposed to make kind of like a tiny-mini OS..any links to some tutorials or explanations hon ow to understand this and be able to make a program like this on my own?
View 9 Replies View RelatedAny class or library that can to calculate the center and radius of a sphere from 4 known points on its surface?
View 9 Replies View RelatedI'm getting a error on my Circle::Circle(double radiusValue) constructor. My instructions is 'Add a constructor that accepts one argument and uses it to set the radius.'
#include <iostream>
#include <cmath>
using namespace std;
class Circle {
private:
double x;
double y;
double radius;
[Code] .....
Exerted by the rider's foot yet not exceed the stress placed on the crank arm's sprocket attachment, is provided by this formua:
r^3 = d*p/s*π
r is the radius of the cylindrical rod in inches. d is the length of the crank arm in inches. P is the weight placed on the pedal in lbs. S is the stress in lbs/in2
Using this information, design, write, compile, and execute a C++ program that computes the value of r for a crank arm that is 7 inches long, accommodates a maximum weight of 300 lbs, and is able to sustain a stress of 10,000 lbs/in2.
I am drawing a circle using ellipse because there is no explicit command for this.
Code:
pDC->Ellipse(CRect(70, 170, 300, 400));
What is the centre of circle and what is radius in the above command?
My problem is the following : We have a circle paper of radius R. We will cut off a sector of this circle (with length rem_sec), and the remaining (bigger part) will create a cone. Radius of cone base is r.
I need to create a code that prompts the user to enter circle's radius R and the program will calculate the length of removed sector (rem_sec) so that the created cone has the Max Volume.
I wrote the following code, but it doesn't work. It displays both rem_sec and MaxV = 0.
#include <iostream>
#include <cmath>
#include <iomanip>
#include <conio.h>
using namespace std;
const double PI = 3.1415;
int main() {
double rem_sec;
[Code] ...
Let (x,y) be the center of the circle. (x,y) will not be (0,0). I have radius of the circle. Now i want to find the angle and radius of the given point inside the circle.
View 2 Replies View RelatedI am facing a programming logic problem. I want to draw radius sized lines from centre of circle to the circle boundary.
My code is:
int x1, y1, x2, y2, i, r, old_xc,old_yc, x,y;
int xc, yc;
x1=170;
y1=300;
x2=70;
y2=400;
pDC->Ellipse(x1,y1,x2,y2);
[Code] .....
The lines are touching the circle boudary at only start while the rest of lines are smaller and the shape is a triangle instead of a pie slice.
I was given an assignment for class to calculate the area of a circle using only the radius as a user input and not using Pi in the code. I need to do this by calculating the areas of a series of rectangles under the curve and adding them together. Using nested loops to continuously reduce the size of these rectangles until the approximated area value is within a margin of error less than 0.1%.
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main ()
[Code] .....
I am having trouble with my C++ program. My program asks the user to enter any number greater than 0 and less than 20, and if the user enters any number(s) outside the acceptable range, the output should display:
input outside of exceptable range > 0 and < 20
length: 1 width: 1 area: 1 perimeter: 1
But in my program, this output displays no matter what the user types (even if the numbers are in the acceptable range, when it should be displaying the length and width the user enters and also displaying the calculated perimeter and area whenever the user enters number(s) in the acceptable range. Here is my code:
#include <iostream>
using namespace std;
float class_rectangle_area();
float class_rectangle_perimeter();
float class_rectangle_length();
float class_rectangle_width();
[Code] .....
I was asked to build a small program to calculate the are of a Triangle but my code must have some problem.. />
#include "stdafx.h"
void main()
{
int a,b;
[Code]....
I get this errors:
-warning C4996: 'scanf': This function or variable may be unsafe. Consider using scanf_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS.
-warning C4244: '=' : conversion from 'int' to 'float', possible loss of data
I would like to calculate area and volume of cylinder but radious and height should be integer, float and double.
View 14 Replies View RelatedI would like to calculate area and volume of cylinder but radious and height should be integer, float and double. How can i do?
View 9 Replies View RelatedI am currently learning "if statements" while doing a program that calculates the area of a triangle. My problem is that the result is always "0". I am pretty sure the problem lies within my math, but how I have set it up wrong.
I am using Heron's Formula. Here it is for reference:
area=sqrt(s(s-a)(s-b)(s-c)) where s=(a+b+c)/2
Code:
#include <stdio.h>
#include <math.h>
int main () {
float area, sideA, sideB, sideC, halfP;
[Code] ....
#include <iostream>
#include <cmath>
using namespace std;
//prototypes for all separate functions
int chooseFunc(int);
int chooseMethod(int);
int numRect(int);
[Code] .....
It seems that my program will ask the user for the number of rectangles and trapezoids but will fail to compute the area under the curve from the user input. Therefore, I believe I have a logical error somewhere or I'm forgetting to call something somewhere.
I'm building a pretty basic calculator program that calculates the area of generic shapes (triangles, rectangles, and squares); for some reason though, my program is having troubles as soon as it hits the if/else code in the int main section. When I enter triangle, rectangle, or square, it just spits back out the "That's not one of the options. Please re-enter and try again." error line I created. When I isolate and run just the stuff inside the if/else statements it works great, but why it won't just understand my if (shape == triangle).... .
Code:
#include <iostream>
using namespace std;
class figure {
protected:
double x, y;
[Code] ....
Below is what i have so far. My main issue is outputting the area and perimeter of the given coordinates as i need the final coordinate to connect up to the first coordinate. I've tried doing that using numberOfcorners but it says "the expression must have integral or enum type"
#define _USE_MATH_DEFINES
#include <iostream>
#include <cmath>
#include <math.h>
using namespace std;
int main() {
float ArrayX[10];
float ArrayY[10];
float numberOfcorners;
[Code] .....
I need to calculate the average brightness of a defined area in a bitmap. Is there a way to select the area which a watermark is going to be applied to, and then find it's average brightness?
I have the below code, but at the moment Color pixel is displaying 0, 0, 0 for RGB, I believe i'm doing it wrong, I have tried to use this as a reference but use part of the image instead of the entire image.
See Company Watermark region!
public void addWatermark() {
Image source = Image.FromFile("C:UsersMartyn BallDesktopImages 38.JPG");
Image watermark1 = Image.FromFile(Glb_venueWatermark);
Image watermark2 = Image.FromFile(Glb_companyWatermark);
//Get width and height of image
int sourceWidth = source.Width; int sourceHeight = source.Height;
[code]....
[URL] .... This is what I have so far, and it isn't incorrect, but how to improve this or make it more accurate?
// subtracting the area of two circles from a rectangle
#include <iostream>
using namespace std;
int main() {
cout << "This program is designed to calculate the area of a rectangle, to exclude the area of 2 circles that have been placed inside of the rectangle." << endl << endl;
[Code] .....
Write a program that prompts the user to input the length of a rectangle and the width of a rectangle and then displays the rectangle's area and perimeter. The program should be broken down in 3 parts:
1. Input the length and the width (two input statements)
2. Calculate the area & perimeter (results should be saved in variables
3. print results.
Format the output so the user can easily read the results. Use the tab escape so its easy to read.
---------------------------------------------------------------
So here's what I have so far. I have been stuck for two days
#include iostream
using namespace std;
int main () {
int double length;
int width;
int area;
int perimeter;
[Code] ....
I dont want to get a zero for not turning this in...
I am writing a program to calculate a rectangle's area.
Eg.
Enter top left point: 1 1 (User input)
Enter bottom right point: 2 -1 (User input)
Top Left x = 1.000000 y: 1.000000
Bottom Right x = 2.000000 y: -1.000000
Area = 2.000000 (Program output)
It keeps on prompting me my variable r is being used without being initialized, when I think I already did so.
Code:
typedef struct {
double x;
double y;
} Point;
[Code] ....