I need to calculate the expected time it takes to do an activity using a formula provided and after the loop is broken it needs to show the number of projects processed and the project with the longest expected time. I've got everything working except for finding the the project with the longest expected time. What I have here just keeps displaying the number of the last project processed regardless of if it was the largest or not, specifically lines 54-61 is what i can't seem to figure out.
#include <stdio.h>
int main( void ) {
unsigned int counter;
int projectnumber;
int optimistictime;
int realistictime;
I'm trying to write a program that will allow a user to enter infinite numbers (one at a time) with a way to stop entering values, and once it stops it immediately displays:
Lowest number: Highest number: Number of values entered: Average of numbers:
what I can't figure out is:
-how to end the loop with something other than a number, preferably a char, so that it doesn't affect the average/lowest/highest
-how to output the lowest and highest numbers in a loop (would be easier to figure out were it finite and I could just type a bunch of printf/scanf)
What I have so far:
Code:
#include <stdio.h>#include <stdlib.h> #define pause system("pause") main(){ //n = amount of numbers input //x = number given by user //s = smallest number //l = largest number }
And here is my output when I run the program. 75 Max: 90 Min: 0
Press any key to continue . . I am reading from a file in this program which contains a set of 30 numbers and it has the average correct and the max correct but the minimum number in the set is 56 however it keeps giving me a zero for the min.
I want to find third largest character in ascii as alphanumeritic. The problem is i cannot use arrays. How can I find third largest number ? Have to I compare all chars with each other ?
I am trying to find the largest prime factor of a number. But when I am trying to determine if a number is a prime number in the function:
int is_prime(int number), I am unable to exit the loop.
Here is the code:
#include<iostream> using namespace std; int is_prime(int number) //the problem is in this function { int num = number; int factor=0; do{ num++; for(int i=1;i<(num+1);i++){
[code].....
So when the program runs, it first divides 20 by 2, to get 10, then divides 10 by 2 to get 5. Since, // condition 1 is not met, it passes 2 to the function int is_prime(int number). The function is able to return 3, but cannot exit the loop when num is 4.
I think the problem lies in the function: int is_prime(int number).
I'm trying to make an array that takes a group of numbers and finds the largest number into a template class.
template<class TYPE> void Integers(TYPE data) { int integers[] = {4, 25, 32, 85, 150, 12, 98, 200}; int i = 0; int Max=integers[0]; for (i=1; i < 8; i++) {
[Code] ....
I'm sure I'm going about it all wrong, but I'm not sure as to get it so that it will accept the arrays input.
Write a program that uses two functions; one finds the largest number and second largest number; and second function finds the average. The data, comprising of 20 different temperature values, is available on a file.
My code compiles fine but it doesn't seem to want to calculate the max integer. It calculates min and average fine but I'm not seeing what is wrong with my code. The max integer keeps coming out wrong.
#include <iostream> using std::cin; using std::cout; using std::endl; #include <cstdlib> #include <algorithm> using std::swap;
I am attempting to write code that receives a number from the user and outputs the largest prime number underneath the user's number. There are no errors in my code, but no matter what number is imputed, the program says the largest prime number is 1. I cannot find where the issue is in the code. Here is the code I wrote:
I'm suppose to write a program using (for loop) that asks the user to enter any amount of numbers, so that it can display the smallest and largest. My program successfully finds the largest, but it is always displaying 0 for the smallest, I think Im doing something wrong with the internalization but I dont know what to change it to.
This is what I have ....
#include <iostream> using namespace std; int main() { int amount; int count; int number = 0; int smallest = 0; int largest = 0; cout << "Enter total numbers to process: ";
i want to print Largest number from any 5 rows.Th number printed should be any one of the largest in the five rows of 2d arrays.I have created code for largest number in each row but how to pick and print them randomly?.
Code:
#include<conio.h> main( ) { int a,b,c,d,e,x; int arr[] = {a,b,c,d,e}; int Matrix[5][5] ={ /*Initializing array*/ 2,4,3,5,9, 6,8,2,2,10,
In this exercise:The C Programming Language Exercise 3-4..It states the following: "In a two's complement number representation, our version of itoa does not handle the largest negative number, that is, the value of n equal to -(2 to the power (wordsize - 1)) ."
A char is one byte (255 bits). The range of an 8 bit variable using a two's complement representation is -128 to 127. Therefore -128 is the largest negative value. The statement in book suggests that the itoa function will not output -128 if we pass -128 as a parameter, because in itoa when we try to convert -128 to positive -128, the inverse of -128 is -128. However, I just ran this code in my computer and it successfully outputted -128.
Code:
#include <stdio.h> #include <string.h> #define SIZE 10 void reverse(char s[]) { int c, i, j; }
What is the largest prime factor of the number 600851475143 ?
This is what I have. If I replace 600851475143 by 1000 (for example), it works fine until 2 divides 1000 to 500, 250, 125...but when it has to find the next divisible prime (ie 5) it cannot do that and the program stops working.
Code:
#include<iostream> using namespace std; bool find_prime(int number) { int factor, num; factor = 2; num = number;
How to find the largest and smallest number entered by a user. So far I'm able to add, find the average and count how many numbers are entered.
I'm just having trouble with find the max and min. I tried if statements and it breaks the program will it wont let me exit the while loop or the program will do a force close after entering a value.
Code:
#include <stdio.h> #include <stdlib.h> int main(){
int maxNum=0, minNum=0, value, count=0, sum=0; double average;
I made the code that stores and prints 5 row by 5 column values but how to find the largest number from them.What should I do to find the largest number?If I use if-else then it would be very tedious but I think there is way out with for loop but still I can't frame the logic. Here is the code
Code: #include<stdio.h> main() { int lnum[5][5]; int i,j; for(i=0;i<=4;i++) {
Keep track of the sum of values entered (as well as the smallest and the largest) and the number of values entered. When the loop ends, print the smallest, the largest, the number of values,and the sum of values. Note that to keep the sum, you have to decide on a unit to use for that sum; use cm.
Try not to make too much fun of me for my logic, but I'm having trouble with this. I am trying to make it so the program takes a 1 dimensional array and a 2 dimensional array, and checks to see what row in the 2 dimensional array is the closest to the 1D array.
To compute the value of the 1D array you take the first row first element in the 2D array, and the first element in the 1D array, subtract and the absolute value.
The whole temp part is kind of confusing myself. What I'm thinking is that I can add all row values up using
Code: tempRow += abs( x[i][j] - y[j] ); , then I need to compare that value to see if it is close to the "firEle" which is value I need to get closest to.
Write a program to calculate the Loan Balance, where a person borrows an amount A and in return he/she agrees to make N payments per year, each of amount P. While the person is repaying the loan, interest will accumulate at an annual percentage rate of R, and this interest will be compounded N times a year (along with each payment). Therefore, the person must continue paying these installments of amount P until the original amount and any accumulated interest is repaid.
NOTE: The formula to calculate the amount that the person needs to repay after T years is-
Balance Amount after T years = A[(1+R/N)^NT]-P -----------------------------------------------------------
I have a few doubts :
1. I think that the "balance amount" formula can directly give the "loan balance" for the person. I'm not sure if it's correct but in that case the question would serve no purpose. Maybe I'm wrong.
2. If there should be a loop to calculate the loan balance, what condition should I give and which loop will be better to use?
