I am supposed to have a loop that terminates when the difference between two successive values of 'e' differ by less than 0.0000001 (6 zeroes). So far I have written this much of the code:
#include <stdio.h>
double eCalc(int terms, double e);
int main() {
int dummy;
int terms;
double e;
[Code] ...
It will not even run. Compiler code errors are as such:
error C4700: uninitialized local variable 'e' used
I am working on Euler Project exercise number 17. Here is the problem from the website.
"If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?"
Code:
#include <stdio.h>
#include <string.h>
#define LENGTHOFHUNDRED 7
#define LENGTHOFONETHOUSAND 11
#define NUMSTART 1
#define NUMEND 1000
[Code] .....
I started to learn programming through this site two weeks or so ago. I've got a book with exercices and so on, and one of them involves calculating e within a tolerance given by the user.
The formula for calculating e is the summation of 1+(1/i!), where i -> n.
So, here's the code and I'll explain the problem below:
Code:
#include <stdio.h>
int main()
{
float error;
float terme;
float sumatori = 0;
int cicle_euler = 1;
int factorial;
[Code]...
For some reason, when I set factorial to cicle_factorial, factorial remains 0, which I find puzzling; the program always halts when 1 + sumatori is 2.0 no matter what error is.
This must be a common problem and I suspect it has to do with some distinction between variables inside a loop and variables outside it, but as I lack technical vocabulary I can't seem to find anything on Google.
Write a program that approximates the value of π using the Leibniz series and compares the Leibniz series approximation against the known value of π and two other common approximations of π (22/7 and 355/113). The program must prompt the user for the desired number of terms (n) to use in the approximation (as an integer) and calculate the approximate value of π to the given number of terms. The program must display each approximation of π and display the difference between each approximation.
I understand how to prompt for the number, what I don't even get how to start is to use it to approximate the value of pie in that given number. Also how to tell the difference between each approximation...
I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
string username;
string password;
cout << "Enter username: ";
getline(cin, username, '
[Code] ....
I'm doing some exercises in c and i have to do one which shows me this output:
Quote
I=0 J=1
I=0 J=2
I=0 J=3
I=0.2 J=1.2
I=0.2 J=2.2
I=0.2 J=3.2
.....
I=2 J=?
I=2 J=?
I=2 J=?
how i can find the 5 without loop?
vector<int>i;
vector<int>j;
i.push_back(1);
i.push_back(2);
j.push_back(3);
j.push_back(4);
j.push_back(5);
[Code]...
I've researched this quite a bit and the overwhelming answer I've been seeing for a loop generating the same pseudo-random number is that you're seeing the random number generator inside the loop, but that is not the case with me . . . At least not that I can see.
Basically, as I mentioned, I have a loop "birthing" new bunnies in a loop. And all the new bunnies are being created with the same name and other details.
Here is the code:
void BunnyGraduation::breed() {
for (unsigned int male = 0; male < colony.size(); male++) {
if (colony.at(male).getSex() == Bunny::Sex::MALE && colony.at(male).getRadioactiveMutantVampireBunny() != true && colony.at(male).getAge() >= AGEOFCONSENT) {
for (unsigned int female = 0; female < colony.size(); female++) {
[Code] ....
srand(time(0)); is seeded ONCE in the constructor of the bunny object itself. . . Now, come to think of it, the constructor is called every time an object is created . . . And the constructor contains the srand() . . . and the constructor is being called in a loop. . . So therefore, yes, the srand() is being called inside the loop.
I need to calculate the expected time it takes to do an activity using a formula provided and after the loop is broken it needs to show the number of projects processed and the project with the longest expected time. I've got everything working except for finding the the project with the longest expected time. What I have here just keeps displaying the number of the last project processed regardless of if it was the largest or not, specifically lines 54-61 is what i can't seem to figure out.
#include <stdio.h>
int main( void ) {
unsigned int counter;
int projectnumber;
int optimistictime;
int realistictime;
[Code] .....
I've been working on a program on and off for around a week now and I've been struggling towards the end of the program.First of all, the program is a maths quiz which generates two random numbers per question.I'll give you one part of my code:
Code:
srand ( time(NULL) ); //seeds the random number generator
int score = 0;
int a = rand()%12 +1; //generates a random num between 1-12
int b = rand()%12 +1;
int c = a+b;
int d;
}
[code]....
I've basically copied the above code 10 times and changed the variables by going through the alphabet e.g.
Code:
int a = rand()%12 +1; //generates a random num between 1-12
int b = rand()%12 +1;
int c = a+b;
int d; all the way to
Code:
int an = rand()%12 +1;
int ao = rand()%12 +1;
int ap = rand()%12 +1;
int aq = an+ao-ap;
int ar;
Now what I'm going to do is remove all the declared variables and create a loop. But my problem is; If I wanted to declare four variables for e.g.
Code:
int a = rand()%12 +1;
int b = rand()%12 +1;
int c = rand()%12 +1;
int d = a+b-c;
Would I place the srand( time(NULL)); inside the loop? it's confusing because I know an example of a basic loop with an array would be:
Code:
#include <stdio.h>
#include <conio.h>
int main(void)
{
int test[5]={21,18,47,21,4};
int I;
int total=0;
for (I=0;i<5;i++)
total += test[I];
}
[code]....
how or where to include the random number generator in the loop and to make it ask 10 questions at random.
I want to create a specific number of for loops each in another loop, as in example:
for(i=0;i<9;i++)
{
for(j=0;j<9;j++)
{
for(k=0;k<9;k++)
{
//some stuff
}
}
}
In this example there are 3 loops, but what if i want to create e.g. 10 such loops, and program reads a number of loops from a txt? It is needed for checking numbers.
Something that does something like this
at this point run a loop for all players, in this loop use random to determine the face and depending on the face run a loop (for roll again etc) or give next user the chance.
And this loop is 2-12 people, all rolling die.
They draw 3 die out of a cup of 12.
Then they roll the 3 die, getting fish, hook, or boot on each die.
My program asks me to write a C++ program that generates a random number between 1-100, and lets the user guess the number until he/she guesses correctly.
I have every thing done but my loop will not end. I know I have to "update" the loop to end it but I don't know what that means.
#include <iostream>
#include <iomanip>
#include <ctime>
using namespace std;
int main() {
srand(time(NULL)); //the function that generates random numbers
[Code] .....
I know for while loops you type
while(argument){
do whatever
}
you have to use the brackets to enclose just like I used in my code right here.It is a simple while loop that is a countdown.
#include <iostream>
using namespace std;
int main() {
int n =10;
while(n>0){
cout << n << ", ";
[code].....
when I take the brackets away from my while loop, my code will still execute but it just prints out the number "10" repeatedly. I was just wondering why it does this and why the compiler does not throw out an error when I leave off the brackets after the "while()".
I have to write a C++ program that picks a random number between 0 and 49. If the number is even lets say 30, then the computer will display 30, 32, 34, 36... all the way till 100, if its odd lets say 17, then the computer will display 17, 19.. till 99. I got the computer picking a random number, I just can't figure out how to display every other number using a for loop statement. Here's my code for random number generator:
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
[Code] ....
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
How can i repeat a loop based on the number inputted by the user?
View 4 Replies View RelatedWrite a program to make a table for any input number and then continuesly ask to press y to print more table and if you press any key other than y then program must be terminate using while loop and do while loop. How to start or end with it.
View 2 Replies View RelatedOK, so the program is working minus the play again loop. I even tried a goto statement for it but no luck. Basically what its doing is after the game runs its course it asks if you would like to play again? If you hit Y it starts over but if you it N it starts over. I want it to out put thank you for playing and close after user hits a button.
// C// Guess My Number
// The classic number guessing game
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
[Code] ....
The function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application
//
#include "stdafx.h"
#include <iostream>
using namespace std;
void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
So I have been given and as part of the solution I need to count the number of digits in a long long variable. To do this I use a while loop, but it is behaving strangely. Here is the code.
#include <stdio.h>
#include <cs50.h>
#include <math.h>
int main (void) {
printf("What is the card number?");
long long card = GetLongLong();
if(card <= 0)
[Code] .....
When I execute the program it asked for the number, but then nothing happens. Of course, my first instinct was that the program was caught in an infinite loop somehow, but could not figure out how. I commented out the while loop and the program completed (albeit returning the incorrect value), so I was further convinced that there was an infinite loop that I was not seeing. I ran the program throug gdb. Strangely, the program did not loop infinitely, instead it got to line 16 [while(card1 > 0] and then just stopped, it was not executing the next line of code at all.
I am stuck looking at whats the problem ....
#include <iostream>
using namespace std;
int main() {
float average, largest = 0, smallest = 0;
int count = 1;
int num;
[Code] .....
I am trying to do a simple for loop that computes sum of a certain number of integers and then outputs the sum.
.text
.globlmain
main:
li $9, 0
li $10, 0
li $11, 10
li $12, 0
li $13, 0
[Code] ....
There error I keep getting is on the line with the branch
Instruction references undefined symbol at 0x0040003c [0x0040003c] 0x10200000 beq $1, $0, 0 [exit-0x00400038]
My while loop is the problem. I want to use a non-recursive function to make the triangle number the sum of all whole numbers from 1 to N.
#include "stdafx.h"
#include <iostream>
using namespace std;
int triangle(int t);
[Code] ....
I'm trying to write a C++ program that will allow a user to input a number from the keyboard. Then using a loop, that will perform 10 times, multiply the entered number by the loop counter. Print out the loop counter, the entered number and the product of the loop counter and the entered number. A one-time heading should be displayed before information is printed.
This kinda of what I have so far:
#include <iosteam>
using namespace std;
int main () {
Start
Declare: numScores, sum, score, avg, SENTINEL = 200
numScores = 0
[Code] ....
All the programs I have tried to make are not working?
I am writing for loop with a switch so that scores can be inputted in by a judge. The issue that I am running into is that I will put out an the text then the test happens and the code puts out the switch statement 5 times with random number. Here is what I have written.
Code:
int main() {
int diver;
int option;
int Judge;
cout << "Enter Divers Name:";
[Code] ....