I am trying to do a simple for loop that computes sum of a certain number of integers and then outputs the sum.
.text
.globlmain
main:
li $9, 0
li $10, 0
li $11, 10
li $12, 0
li $13, 0
[Code] ....
There error I keep getting is on the line with the branch
Instruction references undefined symbol at 0x0040003c [0x0040003c] 0x10200000 beq $1, $0, 0 [exit-0x00400038]
The program requires the user to enter 10 integers then print the total no. of even integer,highest even integer, lowest even integer then total no. of odd integer,highest odd integer, lowest odd integer
I already got the total no. of even integer and total no. of odd integer. But I don't know how will i get the highest even integer, lowest even integer and highest odd integer, lowest odd integer.
I just want to practice in the language so i wrote this simple function that computes the factorial result of a certain number. The problem is that for all numbers > 20, the results are wrong ( < 20 all good).
I already learned that normal "long" type in c is more like 32 bit int and not 64 bit like a long type in java. so I used here a "long long" type.
why am I getting strange results above the number 20? isn't 64 bit enough to hold those numbers?
Code:
long long factorial(int n);
int main() {
long long result = factorial(20);
printf("%lld",result);
[code] ...
for 21 i get: -4249290049419214848
where the right result shoud be: 51,090,942,171,709,440,000
write a program that computes the factorial of a number and displays it. A factorial of a number (written N!) is defined as N * (N-1) * (N-2) * (N-3) ... *1 In other words, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 3! = 3 * 2 * 1 + 6.
Example of output 15 is 1.30767e+012
Can't get it to display error when user enters a number lower than 2 or higher 60.
// Program to calculate factorial of a number
#include <iostream>
#include <iomanip>
[Code].....
"Write a program that prompts the user for an integer number from the keyboard, and store it in a variable num. After each number is typed in, add num to a total.
Do this six times, each time adding num to a total. (Be sure to reuse the same variable named num for each of the six numbers entered.) When all six numbers have been entered from the keyboard, calculate an average. Display the total and average calculated. "
Here is what I have so far:
Code:
#include<stdio.h>
int main() {
int num, total1, total2, total3, total4, total5, total6, avg;
printf("Enter first number:");
scanf("%2d",&num);
[Code] .....
I was asked to create a loop that outputs until Quit is entered for customer name. This is what my output is suppose to look like: I will also attach the code I made. Im sure there is something wrong with my while command. But I believe there is something else I have to add to print out the last customer name: quit output.
Lab 28 - Your Name
Input Customer Name: xxxxxxxxxx
Input Customer State: xx
Input Product Price: xxx.xx
Customer Name: xxxxxxxxxxx
Customer State: xx
Product Price: xxx.xx
Product Discount: xxx.xx
Discounted Price: xxx.xx
Sales Tax: xx.xx
Total Cost: xxx.xx
Input Customer Name: Quit
End of Lab 28 for Your Name
Code :
#include<iostream>
#include<iomanip>
#include<string>
using namespace std;
double pPrice , pDiscount , dPrice , sTax , tCost ;
int cName , cState ;
[Code] .....
I need to write a program that outputs the number of characters, words, and lines in the files that are supplied as command-line arguments.
#include <iostream>
#include <string>
#include <iomanip>
[Code]....
How to total the values that are put in during the loop. For this program I need to add up the values the user inputs and then display them after the loop. Here is what I have:
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main() {
const int firstQuiz = 1, lastQuiz = 4;
int quiz, quizGrade;
for (quiz = firstQuiz; quiz <= lastQuiz; quiz++)
[code]...
I am trying to fill an array with blank spaces and instead i get the number 32 over and over, i think this is the ANSI code for that character. how do i get the character itself?
char values[max];
for(o=0;o<=max;o++)
{
values[o]=' ';
printf("%2d ", values[o]);
}
printf("
");
decTotalAmountOwed = decAmountOwed + decAmountOwed;
This is what i've tried so far. The numbers are supposed to be added together once placed in listbox.
How can i count total number of each topic separately? For example total number of topic 1 between all nodes. To begin enter 10 and 7 to initial node number and number of topic.
#include <iostream>
#include <vector>
#include <list>
#include <stdlib.h>
#include<time.h>
#include<iomanip>
#include <iostream>
#include <string>
[Code] ....
How can i count the total no of unique elements in an array? Like I have an array.
Code:
int array[]= { 2,1,4,0,3,3,0,0,1,2,1,1}
// As it has 0,1,2,3,4 as unique values so total no of unique values are=5
int unique =5;
My project is to make a options menu for the user to select a shape and than draw out the shape. That whole process is already done and ready to go. What i am having trouble on is totaling the number of selected shapes. For example, at the end of the program i need to prompt a message saying ("You have selected "shape" this many times "number").
View 1 Replies View RelatedSummary: 6 companies have a product in 5 different warehouses. Each company is identified by a positive ID number and each warehouse is identified by a number (1 for the first, 2 for the second,…)
Object: the object of this assignment is to write a C++ program which asks the user to enter a company ID number, and the number of products in each of the warehouses. It then computes and prints the total number of products for that company
If the total number of product is less than 100, it prints the message “place a new order”
Input: for each company, its ID, and the number of products in each warehouse with appropriate prompt messages.
Example: Enter company ID number: 101
Enter number of products in warehouse #1:30
Enter number of products in warehouse #2:60
Enter number of products in warehouse #3:0
Enter number of products in warehouse #4:5
Enter number of products in warehouse #5:27
The total for company 101 is:122
Output: for each company, the total number of product, and the message “place a new order” if the total number of product is less than 100.
Method:
1. Define global variable, int total_prod to hold the total number of products for a company
2. define the function void compute_total() that uses a loop to read the number of the products in all warehouses for one company, computer the total number of products and store it into the global variable total_prod.
3. Define the function void new_order() that determines if a new order need to be placed as follows: if the total number of products (in the global variable total_prod) is less than 100, it prints the message “place a new order”
4. Your function main does the following in a loop:
- read a company ID number
- call function compute_total() to read the number of the product in all warehouses for that company, and to compute their sum
- print the total number of the product for that company with an appropriate message
- call the function new_order() to determine if a new order need to be placed.
Write a C++ program to calculate the fewest number of each denomination needed to pay a bill of amount TOTAL. For example, if the end user enters $97 for TOTAL, program will output that the bills would consist of one $50 bill, two $20 bills, one $5 bill, and two $1 bills. (Assume that the amount is in whole dollars, no cents, and only $100, $50, $20, $10, $5, and $1 denominations are available.) Aid: You may want to use the modulus operator %.
View 1 Replies View RelatedI am currently working on an assignment.
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
char letter;
int count = 0;
double ppl = 0;
double finalCost = ppl * (count - 1);
[Code] ....
I am trying to create a word counter program that asks for the price per letter and then asks for the sentence they are writing. The app should then calculate the number of letters and give the total cost similar to:
You have 40 letters at $3.45 per letter, and your total is $138.00.
Everything compiles fine but when I run it the inputs don't work and it outputs:
You have -1 per letter, and your total cost is $-0.
I have to write a loop to access the integers. Then fill it with few sample data.
list<map<set<string>,int> l;
creating a program using while that terminates the loop when two intergers any two between 1 to 100 are equal with each other
View 2 Replies View RelatedCode: i am trying to display the information in the array as a table and add the total rows and the total colums separately
#include<stdio.h>
int main(void)
{
int row, col;
[Code].....
I got an assignment which asked me to create a program that asks user to input 10 numbers (positive and negative) integer. The program would be using loop to compute sum and average of all positive integers, the sum and average of negative numbers and the sum and average of all the number entered. But, the new problem is after I've entered all the number, the answer that the program gave me wasn't the answer that the program supposed to give. I don't know how to describe it, I would attach a picture and the code below:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
//Declaration
int x, value, sum, average, SumPositive, SumNegative, Positive, Negative;
float AveragePositive, AverageNegative;
[Code] .....
The question is "Write a program that uses a while loop to read a set of integers from an input file called "data.txt" and prints the total number of even numbers read from the file."
Code below is the program I have created so far. I keep getting the window to pop up but not stay up so I am assuming I am doing something wrong.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
std::fstream input("data.txt");
if (!input.is_open()) {
std::cout << "There was an error opening data.txt";
[Code]...
i dont usually write console programs, and i cant seem to find out how one parses an unknown number of arguments with cin.
the program receives an unknown amount of integers in stdin, and i need to parse them withouth hanging.
Unfortunately, stdin is a async. stream and blocks, if it doesnt find any integers left.
I cant use peek() or seek() either, as both are async, too, (which makes me wonder what their exact use is?).
Write a function that computes and returns the score for a permutation, i.e. the number of reversals required to make arr[0] == 1.
HAVE TO USE FOLLOWING FORMAT:
Code:
// POST: Returns the number of reversals needed to make arr[0] == 1
// if the reversal game were played on arr
// Note: If arr[0] == 1 initially, then score(arr, n) returns 0 AND this is what i could muster;
[code]....
I'm currently writing a program and a portion of it needs to have a function that computes the result of a formula for two sets of inputs. It then has to calculate and display the difference between the two results.
I have code that takes the input from the user and converts it to the type that I need. In this case we are talking about latitudes and longitudes that will be converted to degrees, then to xyz coordinates.
Write a program that reads four integers from a file ‘input.txt’.
The program will then create a single integer number from the four integers. The output of the program will be the single number and single number + 600.
#include <iostream>
using namespace std;
int main () {
int number , a;
cout<<"enter en integer number";
cin>>number;
cout<<"add 600 to the number"
cin>>a=number+600;
return 0;
}
I have a file with such a format:
string string 8 7 2
string string 7 12 19 -4
string string 1
As you can see I don't know how many numbers there are at the end. I have this code now:
while(!in.eof()) {
kr = 0;
getline(in, pavard, ','); getline(in, vard, ','); getline(in, gr, ',');
while(in.peek()) {
in >> k;
kr += k;
}
in.ignore();
}
in.close();
I tried various combinations with peek() function, but nothing worked.