C++ :: Terminate Loop When Two Integers Between 1 To 100 Are Equal
Mar 21, 2013creating a program using while that terminates the loop when two intergers any two between 1 to 100 are equal with each other
View 2 Repliescreating a program using while that terminates the loop when two intergers any two between 1 to 100 are equal with each other
View 2 Repliescreate a program that asks the user to input 10 integers of an array the program will add the numbers greater or equal to 10.
View 6 Replies View RelatedI am new to C++ and wrote some code here that is not working how I want it to:
Code:
int main() {
vector<string> distinct;
string parag;
typedef vector<string>::size_type vec_sz;
vec_sz size = distinct.size();
[Code] ....
Basically, if I run it, it takes a string, stores it in a vector string, and then outputs it to the screen as I hit enter. But then it waits for another string to be entered. How can I stop it waiting for new input after I hit enter? I tried comparing parag with and terminating there, but I am getting compiler error. I am using code::blocks.
Code:
#include<stdio.h>
#include<stdlib.h>
#include<ctype.h>
#include<string.h>
int main(void) {
int i;
char *str;
int len = 1;
[Code]...
I have to write a loop to access the integers. Then fill it with few sample data.
list<map<set<string>,int> l;
I got an assignment which asked me to create a program that asks user to input 10 numbers (positive and negative) integer. The program would be using loop to compute sum and average of all positive integers, the sum and average of negative numbers and the sum and average of all the number entered. But, the new problem is after I've entered all the number, the answer that the program gave me wasn't the answer that the program supposed to give. I don't know how to describe it, I would attach a picture and the code below:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
//Declaration
int x, value, sum, average, SumPositive, SumNegative, Positive, Negative;
float AveragePositive, AverageNegative;
[Code] .....
The question is "Write a program that uses a while loop to read a set of integers from an input file called "data.txt" and prints the total number of even numbers read from the file."
Code below is the program I have created so far. I keep getting the window to pop up but not stay up so I am assuming I am doing something wrong.
#include <iostream>
#include <fstream>
using namespace std;
int main() {
std::fstream input("data.txt");
if (!input.is_open()) {
std::cout << "There was an error opening data.txt";
[Code]...
I am trying to do a simple for loop that computes sum of a certain number of integers and then outputs the sum.
.text
.globlmain
main:
li $9, 0
li $10, 0
li $11, 10
li $12, 0
li $13, 0
[Code] ....
There error I keep getting is on the line with the branch
Instruction references undefined symbol at 0x0040003c [0x0040003c] 0x10200000 beq $1, $0, 0 [exit-0x00400038]
How can I terminate a function?
View 3 Replies View Related#include <iostream>
#include <string>
using namespace std;
[Code].....
This is my code, when my pintrials = 0, my system cannot terminate but go through the option menu below.
"Allow the user to enter an integer, between 1 to 9 only. You may use the value ‘0’ to terminate the program. Then display the output as follows:
Sample Run 1
Enter an integer (1-9):4
1
121
12321
1234321
Sample Run 2
Enter an integer (1-9): 20
You have entered an invalid entry, please try again.
Enter an integer (1-9): 0
(Try to use remark to explain function and process area)
how to use EOF to terminate inputting data
View 1 Replies View RelatedI've stored a binary pattern in what is interpreted as an unsigned short.
unsigned short byte_one = 128;
I've done some bitwise manipulation and want to store it back into an array, however, it needs to be null-terminated.
buf[1] = byte_one;
How do I null-terminate this?
this application has requested the runtime to terminate it in an unusual way. contact the application support team for more information!!!
#include <cstdlib>
#include <iostream>
#include <fstream>
#include <string>
#include <stdlib.h>
[code].....
I have a thread with a while(1) loop in it. When the user push the stop button I would like that thread to end.
I thought about creating a bool and checking its value periodically in the thread and when I push the stop button I change the value of the bool for that the thread breaks out of the loop and finishes.
i would like to know how to replace a value with the variable that ii is equal, i mean like a=5 i want to be able to replace the number 5 by the letter a when needed in printf. ofc i want to use this for an actual purpuse and meaning what i gave was a mere example and thxx. BTW DONT jUst DROP a few lines of code that would make it work
View 5 Replies View RelatedHow i can find two equal int in array with O(n) time complexityand O(1) place complexity?
View 8 Replies View RelatedI made my own function to search if two given strings in my function are equal but the problem is if i pass two variable like hello,hello ... result is string equal but if i pass hello , hello also give me string equal because last 4 characters same to last 4 characters of hello ...
Code:
int getSimilarityOfTwoStrings(const char str1[],const char str2[]){
int str1Len = getStringLength(str1);
int str2Len = getStringLength(str2);
int i = 0;
int j = 0;
bool truefalse;
[Code] .....
I'm making a simple calculator and have done it all right where you can input everything, all the functions are there, but when i run the program it will come to displaying the result and it will always equal zero, I just need it to say 8+8 = 16 rather than 8+8 = 0, i don't know whether its just displaying the results as 0, or not displaying it at all, the code will follow below:
Code:
#include<iostream>
using namespace std;
double num3;
double num2;
double result;
char operation;
[Code] ....
I calculate two numbers "R1",R2"
when i make
cout<<R1;
cout<<R2
i get
R1=51,9151
R2=51,915
when i make
Code: if (R1>R2) cout<<"i am here" he print the message
but they are equal. how i made limit the number of flottant to get equal numbers?
int main()
{
int a=0, c, d, N, K;
bool stopBool = 0;
[Code]....
This is supposed to find take a number N and K and find all numbers between 0 and N that equal K and cout the number of pairs that fit it but it doesn't work.
how to check if a specific index equal to null when i try to implement it, it gives an error for example:
vector < vector <double> > v;
v[0].push_back(0);
v[0].push_back(1);
v[0].push_back(2);
v[0].push_back(3);
v[1].push_back(10);
v[1].push_back(11);
v[1].push_back(12);
v[1].push_back(13);
if(v[0][4]==NULL) {
cout<<"empty"<< endl;
}
how to make a programm in native c++ which print out all prime numbers less than or equal to given number????????
View 5 Replies View RelatedIn my program I am supposed to call isEqualTo with a user defined class type, and print out if my two numbers being compared are equal or not. I had to write two versions of this, one with just a template which works fine, but when I implemented the class, all the sudden my program just spews out true no matter if actually equal or not. Here is what I have so far:
#include "stdafx.h"
#include <iostream>
#include "UserClass.h"
using namespace std;
template<typename T>
bool isEqualTo(T value1, T value2){
if (value1 == value2)
[Code] ....
how to split a file in equal size and when clicking on split button it split the files as well as encrypt split parts and the size information are automatically stored in groupbox and save all splitted files in folder.
View 1 Replies View RelatedI'm a beginner at c++ and I need to write a program that reads a set of integers and then finds and prints the sum of the even and odd integers. The program cannot tell the user how many integers to enter. I need to have separate totals for the even and odd numbers. what would I need to use so that I can read whatever number of values the user inputs and get the sum of even and odd?
View 2 Replies View Related