I need to create a loop to return a minimum value using a boolean variable but don't quite understand how to format my algorithm.
#include <iostream>
using namespace std;
int main() {
bool first = true;
while (first) {
cout << "Enter a number (X to exit): ";
int num;
[Code]....
I know its jacked up any comments in the code would be great I need to finish the program but also understand it.
Requirement: the AddRegistration method in the RegistrationDB class should accept a Registration object and return a Boolean value that indicates if the operation was successful
a brief overview. Form with two combo boxes and a button, when you click the button the data from the combo boxes is entered into a table in the connected database...
I'm trying to test if a character is a vowel. I made a separate function for the test, I'm not really sure how to get my return value to output whenever I call the function from main?
Also, I'm not good with while loops and can't figure out how to get it to continue asking whether or not the user wants to keep entering values.
#include <cstdlib>
#include <iostream>
using namespace std;
bool isVowel(bool);
int main(int argc, char *argv[]) {
char var1, cont;
[Code] ....
My assignment : "Input the answer as the words true or false and put the user's answer in a boolean alphabetic variable."
My code:
bool T;
cout << "Type 'true' for lowercase or 'false' for uppercase";
cin >> T;
if (T == "true") {
cout << "Enter a whole number in decimal base: ";
cin >> dec;
cout.setf(ios::showbase);
cout << "Decimal " << dec << " to Hexadecimal with lowercase: " << setbase(16) << dec;
}
I'm not sure how to get 'true' as user-input as true for bool.
I want to finding maximum and minimum values of 10 numbers using for loop and the program work wrong !!
#include <iostream>
using namespace std;
int main() {
int x;
int max = -999999999;
int min= 999999999;
[Code] ....
I have a hit a snag in a number guessing game program. I was given a half-completed program and told to use functions to complete the missing pieces. It looks unwieldy, but this is how it is supposed to be. I have temporarily made the random guess value visible for troubleshooting purposes.
#include <iostream>
#include <time.h>
#include <stdlib.h>
using namespace std;
int welcome() {
cout << " Welcome to the hi-low game!" << endl;
[code]....
The issue lies within this piece of code:
checkGuess(guess, correct); done = false; //either true or false
} while (!done);
cout << "Congratulations, you got it!" << endl;
return 0;
}
I need to manipulate the Boolean variable done so that it registers as false when the user inputs a number higher or lower than the randomly selected value. However, if the user guesses correctly, done will become true and the program will end.
As it stands now, the program will not terminate, and if I set done equal to true like so:
checkGuess(guess, correct); done = true; //either true or false
} while (!done);
cout << "Congratulations, you got it!" << endl;
return 0;
}
Every number the user inputs will register as correct instead of the one right guess.
I am working on a small simple program my program fills up a air plane with customers there is 2 levels 1 and 2 and it will put that person in the spot depending on being picked.
So far i made a boolean airplane with 10 spots I can enter 1 person into the airplane with no problem but then after he sits down i get a infinite loop? I assume i maybe have to use the continue statement I feel like there is something simple that im missing i want to add more people. here is what i have
class Program
{
static void Main(string[] args)
{ bool[] planeSeats = {false, false, false, false, false, false, false, false, false, false };
[Code]......
I have to write a loop assigning a variable x to all positions of a string variable and I'm stuck. I don't have extensive experience with arrays and I'm also a bit confused about C-String. The problem is below.
"Given the following declaration and initialization of the string variable, write a loop to assign 'X' to all positions of this string variable, keeping the length the same.
char our_string[15] = "Hi there!";
(Please note this is a 'C-string', not C++ standard string.)"
How would I go about getting a loop to return to the start?
View 2 Replies View RelatedI want to get a random number from this function but idk if I did this function right....
int random(int x) {
srand(static_cast<unsigned int>(time(0)));
int randomN = rand();
x = (randomN % 10) + 1;
return x;
}
I need a few pointers on how to replace the multiple "return input" in my "choice" function with a statement that perform the same action in C Programming..
Code:
/*
*FILENAME:
*PROJECT:
*PROGRAMMER: Brian Hinds
*DATE: September 05, 2014
*DESCRIPTION: This program uses a function to calculate the result of raising one number to the power of another.
[Code] ....
Suppose I have the following function containing while loop:
#include <iostream>
using namespace std;
int Loop () {
[Code]....
here in above code I want to return value of 'a' by calling function 'Loop'. Is there any way to do this??
for above code output should be:
value of a: 10
value of a: 11
value of a: 12
value of a: 13
value of a: 14
value of a: 15
value of a: 16
value of a: 17
value of a: 18
value of a: 19
So I have been working my way through this assignment and I'm just stuck now. I cannot get this work properly It just tells me I'm trying to return a local variable when attempting to return postfix in the to_postfix function. It is line 97 that wont compile. Also I cannot change anything in runner.c.
Calculator.c
Code:
1 #include <stdio.h>
2 #include <stdlib.h>
3 #include <ctype.h>
4 #include <string.h>
5 #include "stack.h"
[Code] .....
Suppose i have a function:
int & f1(int & p) {
return p;
}
void main() {
int a,b;
b = 10;
a = f1(b);
a = 11;
cout<<b<<endl;
}
why when i change a, b doesnt change? a is supposed to be an alias of b right?
I am making a function that will return a pointer to a long long variable. For example, I have the next variable prototype: Code: long long funcName(long long x, int s); I want to change the return value, and the first parameter to pointers to long long.
View 4 Replies View RelatedI am currently having problems creating a loop that will allow my user to choose to return to the beginning of the program or quit.
#include <iostream>
using namespace std;
int main() {
int j;
do {float a;
cout << "+----Welcome to Basic Operations----+
| Select Your Operation |
[Code] .....
I have not yet finished designing the interface for a couple of the operations, but right now i am hung up on trying to return to the beginning. I believe it is because the j was defined inside do and isn't carried out of the do statement for while.
what i think i need to create 2 int for the FOR loop to do the encryption but how am i to do it meaning the actual encryption itself what is that i check with?Also i think i need more than just the #include <stdio.h> library due to the file functions that i will need or is C having them built in? Also what is that about the program doing all this from DOS?
Create 2 programs with the names encrypt and decrypt that will encrypt and decrypt files respectively.The encryption and decryption will be done through a command line of DOS and the program should be as follows: encrypt file1 file2 key and decrypt file1 file2 key
Where:
file1 is the source file
file2 is the destination file
key is the word with which we encrypt/decrypt file1
So when the user executes the command encrypt f1 f2 sunnyday the program will create a file with the name f2 which will have the contents of f1 encrypted with the key sunnyday.When the user executes the command decrypt f1 f2 sunnyday the program will create a file with the name f2 which will have the contents of f1 decrypted with the key sunnyday.
If the user gives a wrong key the program will continue to decrypt file1 but since the key is wrong the results will be unexpected.Finally the program must print the corresponding error messages in case of errors for example (There is no file 1).The program is expected to work corectly with not only plain text files but executable (exe) files etc.Also The program must be fully commented.
Note: The way the encryption will work is yours to choose but it is recommended that you encrypt every letter of the file with every letter of the key with the (start to finish and begin) technique meaning that if the key has 8 letters then the first leeter of the file will be encrypted with the first letter of the key, the second letter of the file with the second of the key, ..., the ninth letter of the source file with the first letter of the key, the tenth letter of the source file with the second letter of the key etc.
In order to create 10 different zipcode where should i put the loop I tried put loop at every function it does not work and I tried put under the main method it create exactly 10 same zipcode here is my coding only create one zipcode
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <ctime>
#include <cmath>
using namespace std;
class Zipcode {
[Code] ...
I'm writing a program to sum up the even numbers in between 1 and 100, using a while loop. At the beginning of my program, I initialize a variable "sum" to 0, and a variable "temp" to 1. Afterwards I enter a loop where I determine if "temp" is even or not, and if so add it to sum. However, at the end of my program, when I print "sum", I get a result of 0. Below is my code.
Code:
#include <stdio.h>
int main(void)
{
int sum = 0, temp = 1;
}
[code]...
for (int raw1=0;raw1<4;raw1++){
for (int column2=0;column2<4;column2++){
unsigned char temp=0x00;
for (column1=0;column1<4;column1++){
int z1=7;
int p1[8]={00000000};
unsigned char temp2;
[Code] ....
When I print the variable output_mix_column inside the for loop as shown in the code, it prints the right output, but when I print it outside the for loop, it changes its value ....
is it possible to have a global variable pointing to a different address depending on the thread?
Imagine one would like to use threads with the loop:
for (i=0;i<n;i++){
globalPointerVariable=getAddress(i);
DoThingsUsingThe_globalPointerVariable();
}
Can I create 1 variable that accept any type? And can I give it the NULL value too?
View 14 Replies View RelatedSo, I'm relatively new to programming.
I want to create a loop (for, while, do while) which can run the Collatz Conjecture when I give it any number.
The Collatz Conjecture consists of two functions (3n+1 for odd numbers and n/2 for even numbers) and it states that when applied to any positive number, the outcome will ultimately be 1. think of a loop/pseudocode to apply to this.
I create a loop that would repeat itself many times a second? Trying to do extremely basic graphics with a grid and system("cls") every time I run a command, but it still looks very jumpy. I realize system calls are evil. Any way to get rid of this too.
View 1 Replies View RelatedCode:
#include <stdio.h>
int main(void){
int a=0;
for(;a<=10;)
int b;
return 0;
}
I have got a code like this. I don't expect to get an output but just assumed I would see the command screen until I terminated it. What I want to do is just declare a variable b in a endless loop. But what I got from the compiler is this error: error: expected expression before 'int'. I am using Code::Blocks and I think the compiler is GCC.
I have a problem with my code which I can't work out:
double Mi = 200*pow(10,30);
cout << "
Enter accreted mass increment in solar masses
";
cin >> dm;
cout << "
[Code] ....
Basically the loop works, but gives the wrong results.
I need, at the end of the loop, to sort of "redefine" Mi as "Mi + Macc". I then need it to repeat the loop, and at the end add another Macc so that Mi becomes "Mi + Macc + Macc", etc.