So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h>
int * toarray(int *num);
int main(void)
{
int testCases;
}
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases
23456 //input number
6
2293452
4
2293700
1974439125
Process returned 0 (0x0) execution time : 4.152 s
Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream>
#include<iomanip>
using namespace std;
int main(){
int n,i=1,sum=0;
cout<<"Enter a number: ";
[Code] ....
Design an algorithm using flowchart or pseudo-code to prompt the user for a series of positive integer values. Calculate the average of these values and display the average at the end of the program. Assume that the user types the sentinel value -1 to indicate end of data entry.
Sample input-output:
Enter a positive integer (-1 to end) : 5
Enter a positive integer (-1 to end) : 7
Enter a positive integer (-1 to end) : 6
Enter a positive integer (-1 to end) : -1
The average value is: 6
I searched online and found out this solution however it is only for three numbers.Is there any way of modifying this to include the sum of x numbers / number of x(integers) to find the average?
#include<iostream>
using namespace std;
int main() {
int a[9],x,f=1;
cout<<"Please enter an integer [0-10 only] : ";
[Code] ....
Constructing this right aligned half pyramid? The code I had so far is right aligned and they're not in numbers
Write a program that receives one positive integer and display
_________ _ 1
________ 4 2
_______9 6 3
___16 12 8 4
25 20 15 10 5
when the user key in 5.PS: ignore the line
You pros are once newbies like us. Hoped you might take a little time sharing your expertise. Got freaked out when our teacher gave us this activity, where she haven't taught this to us yet. So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
I need a program to run that will accept an input for user id. It will take the customer input and capitalize the letters, and return invalid id with the user inputted values. Then if it's valid it will add a counter counting the number of letters and numbers. It will keep track until the user puts in !. It seems when I try to pass values from the array to my toUpper function to capitalize it it doesn't seem to work right.
View 3 Replies View RelatedI need to promote user to enter y/n in switch statement to continue or not for an other conversion after showing results of each conversion.
#include <iostream>
using namespace std;
int main() {
char a;
double n, r1, r2;
cout<<"Please Chose the Temperature Unit to Convert: "<<endl<<endl;
[Code]....
Write a C++ application program to accept a signed decimal integer as input and output the equivalent 2s complement version in 16-bit binary. Include a space between every four bits in the output string. The input will only be processed by the application if it falls in the valid range that can be represented in 2s complement format with 16 bits. The range of a decimal number from - to + is -32768 to 32767.
View 3 Replies View RelatedI have an embedded microcontroller system communicating with a similar system by radio. The api for the radio requires data to be transmitted as an unsigned char array. It will always transmit a positive integer in the range 0 to 255.When I receive the data I am having difficult in extracting this positive integer.
Code:
unsigned char rxData[4]={'1','2','3',''};
int inVal=0;
//want to assign inVal whatever number was transmitted
E.g. 123
I've been at this for a week and have tried at least 10 different approaches including the use of the atoi(), copying the absolute value of each element of rxData into another char array, reinterpret_cast, and others.
My question is are there various ways that I can approach this program. I.e. do I have to use switch statements?
/*
NumToTxt
Creates the appropriate word form of any positive integer up to 999999
*/
#include <iostream>
using namespace std;
//represents the largest array size for the user entered number
const int MAXNUMARRAY = 6;
/*represents the largest number that can be entered + 1. Used to calculate the first number used to truncate the user
entered number and to display an error message to the user that tells the user the largest number that the program will
accept. */
const int BIGGESTNUMBER = 1000000;
[Code] .....
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
Write a program that asks the user to prompt an Integer number and then test whether it is Palindrome Numbers or not.
The following are Palindrome numbers:
1.22
2.333
3.67876
4.44444
5.123454321
Write a program that prompts the user to enter an integer and then displays that integer as a product of its primes and if it is a prime then it should say so? Above is the question I have been given
#include <iostream>
#include <vector>
using namespace std;
int main () {
int num, result;
cout << "Enter A Number " << endl;
system ("pause");
return 0;
}
This is what I have so far, do I have to use a for loop, a while loop or a do loop,
I have to write a program where the user will input integer numbers. How many numbers they enter is unknown, therefor you should use a repetition structure for the input. When the user is done, they will enter -1 to exit.
Create a dynamic array if the size=2( the initial size must be 2) Repeat until user enters -1.
I have to do this without using vectors.
This is what i have, I cannot figure out what to put in main. I was thinking of a do-while?
Code:
#include <iostream>
using namespace std;
void resize(int *[], int);
int main() {
int *listDyn;
int size=2;
[code].....
I want to accept numbers from the user into an array and convert into corresponding alphabets. E.g 1 into A, 2 into B, and so on.
This is simple, but the problem is the user is supposed to enter the character # also which I want to display as it is in the output. How can I do this ? What type of array should be used - int or char?
C programming: I want to creat a program that asks the user to input the integer lengths of three sides of a triangle, and if so whether the triangle is a right-angled, acute or obtuse one. i am having some doubts about the if, else if statements. I never seem to know how and in what order to use them.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(int argc, char *argv[]){
int SideA;
int SideB;
int SideC;
}
[code]....
Is there a way to tell the program to continue reading the next line of code within a nested IF statement?
The reason I want to do this is because the two "else" statements in the following sample (the main and the nested else) will contain the same exact code and I don't want to repeat it twice. I know I can do this by creating a function and calling it from each else statement but I was just wondering if what I'm asking is even possible without using a function.
if(1 < 2) {
// yes 1 is less than 2
if(5 > 10) {
// do something
} else {
// no, 5 in not greater than 10
// here is where I want to tell the program to continue reading the next else statement
[Code] ....
How do I write a ROM BIOS routine which accepts a row number from the user and place the cursor to the beginning of the row number which the user gave?
View 2 Replies View RelatedIt seems to be going null. I can't get a null value, I want it to accept input till the user hits enter with no text typed. I've tried checking to see if the input is NULL, "", and " " all to no avail.
Code:
#include <stdio.h>
#include <sys/shm.h>
#include <sys/stat.h>
#include <iostream>
#include <fstream>
#include <string.h>
#include <cstring>
using namespace std;
int main() {
string info = "";
[Code] ....
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
View 4 Replies View Relatedhow can I create a program that will accept 2 two integers. the user will also choose among the different operations:
1 for addition
2 for subtraction
3 for multiplication
4 for division
I am creating a WinForm registration application and my program accepts user input information and stores it but I am struggling to use my login function. I believe there is an error in the area of cmd.Parameters.AddWithValue section, I dont think addwithvalue is correct ? I get a fatal crash has occurred when I click Login
string constring = "datasource=127.0.0.1;port=3306;username=root;password=welcome";
string Query = "SELECT * FROM 'userinfo'.'users' where 'username' = @userid and 'password' = @password)";
MySqlConnection conDatabase = new MySqlConnection(constring);
MySqlCommand cmd = new MySqlCommand(Query, conDatabase);
cmd.Parameters.AddWithValue("@userid", this.userid_txt.Text);
cmd.Parameters.AddWithValue("@passone", this.passone_txt.Text);
[code]....
Fixed the crash error, simple typo but now I am getting SQL Syntax errors which I originally believed I fixed.
