I am trying to send 0x20 from arduino and get the hex in c program on the pc iam using RS-232 for Linux and Windows lirary for rs232 communication and when i send 0x20 i get 28ef30 i dont know why.. but i want to get 20 integer type value in c program the code that i use in c is
Code:
n = PollComport(cport_nr, buf, 4095);
if(n > 0)
{
buf[n] = 0; /* always put a "null" at the end of a string! */
}
[code]....
Working on a Project Euler problem and the question asks for the largest prime number that is a factor of 600851475143. As you can see, this is significantly larger than the maximum of a long data type, which maxes out at 2147483647.
I'm running on Windows 32, so int64 is not a valid option for me. It seems like I'll likely have to use a different language to solve this problem.
Looking for extended unsigned integer class, that has custom lenght?
The reason i am asking is because i need an extremely large integer number, in fact one that has no theoretical limit(or at least an extremely large one).
Ok so I have this simple program that gets input from a user. I just want to put in a line of code to make sure that hte user can't type in something like "pizza" , I want to make it say that if the user puts in something that is NOT a number they will get a error back saying "Wrong! try again!" Here is my code :
#include <iostream>
using namespace std;
//Summation Program
//Function Prototypes
int get_num();
void compute_sum(int num, int &sum);
[Code] ....
i need to create a new integer data type called BigInt to store a big big integer, which includes Dint(8 bytes) and Qint(16 bytes)
here is the hint/
typedef struct BigInt {
Int data[2];
}
How can i "scanf" and "printf" them????
void ScanBigInt(const char *format, BigInt &x)
if format is “%dd” -> input Dint, if format is “%qd”--> input Qint
void PrintBigInt(const char *format, BigInt x)
I am using a structure , and when i am assing values i get the warning message , how do I avoid that ?
Code:
// header file
typedef struct {
unsigned _T_ipset:1;
unsigned RTCSetNewTime:1;
unsigned PassWord:1;
unsigned UserReset:1;
unsigned PCDEBUG:1;
unsigned PWRUP:1;
unsigned HostTaskShift:1;
unsigned TimeToConnMstr:1;
unsigned En_Display_Lcd:1;
}
[code]....
large integer implicitly truncated to unsigned type
My intent was to convert the string variable for the year to an integer data type. The code compiles but now cannot run on my system. I'm not sure what's going as to what the program is displaying.
Objective: Prompt the user for two years. Print all Comedy movies that were released between those two years.
#include <iostream>
#include <cstdlib>
#include <string>
#include <fstream>
#include <cctype>
using namespace std;
struct Movie {
string name;
[Code] .....
How can i write a function that will read an "unsigned integer" into a variable of type "unsigned short int"? i can not use cin >> inside the function.. so i am looking for atleast a hint!
View 16 Replies View RelatedJust wanted to share a program I made. It was the answer to one of the end chapter exercises in the C programming book I'm using, asking the reader to create a program that adds all the digits of an integer.
Code:
/* Program to calculate the sum of the digits in an integer */
#include <stdio.h>
int main () {
int number, right_digit, sum = 0;
[code]....
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/
#include<stdio.h>
int main(void)
{
//DECLARE VARIABLES
int num;
}
[code]....
I don't know how the program works if the integer is more than one digit.
Iam new to c++ and i want to write a program to generate an integer array. I keep getting the error at line 25: invalid types 'int[int]' for array .
int main() {
int rows;
int cols;
cin>>rows>>cols;
int test[rows][cols];
[Code] .....
Write a C program that sorts an unsorted array of 5 integer numbers in ascending order by swapping numbers repeatedly. Specifically, first prompt the user to input 5 numbers and store the numbers in an array. Then, if the numbers in the array are not in ascending order, ask the user to provide the indices of two numbers in the array that the user wants to swap. If the user does not enter valid indices (i.e., outside 0 to4), then re-prompt the user to enter new indices. Continue prompting the user to provide indices of numbers to swap until the array becomes sorted in ascending order. Finally, when the array becomes sorted, the program should print "The array is now sorted in ascending order".
Implementation Requirements
Use the #define directive to define the size of the array.
Implement a function called "checkArrayOrder" to check whether an array is in ascending order or not. The prototype of the function is
"intcheckArrayOrder(int arr[], int size);". The function should return
1 if the array passed to the function is in ascending order0 if the array passed to the function is not in ascending order
Define the function prototype in your program.
Implement a function called "swap", whose prototype is "int swap(int arr[], int size, int i, int j);" which swaps the numbers in positions "i" and "j" of the array passed to the function and returns
1 if the indices"i" and "j" are within bounds (i.e., between 0 and 4) and the swap operation is performed correctly.
0 if the indices"i" and "j" are outside bounds so that the swap operation cannot be performed.
Define the function prototype in your program.
Use the function "checkArrayOrder" whenever your program needs to check whether an array is in ascending order or not; and the function "swap" to swap the numbers the user specifies (Note that, you should check whether the user provided indices are valid inside the function "swap" and not inside "main").
here is my code so far
Code:
#define ARRAY_SIZE 5
void main()
{
int i, array[ARRAY_SIZE];
printf("Enter %d numbers
", ARRAY_SIZE);
for(i=0; i<ARRAY_SIZE; ++i)
scanf("%d", &array[i]);
[Code] .....
I'm just not sure how to proceed. I'm not really sure how to progress the checkArrayOrder function to the swap function (in the if statement).
I have a question about my program.. I would like to make a program that if you put "ABC" on INT, the program will restart again... below are my coding...but it not works..if i put ABC on INT, the "Invalid Mark.. please re-insert mark :" will repeat, repeat and repeat infinitely...
Code:
#include <stdio.h>
void calcul() {int mark;
char * grade;
if (!(scanf("%d",&mark))){printf("
}
[code]....
Constructing this right aligned half pyramid? The code I had so far is right aligned and they're not in numbers
Write a program that receives one positive integer and display
_________ _ 1
________ 4 2
_______9 6 3
___16 12 8 4
25 20 15 10 5
when the user key in 5.PS: ignore the line
I am trying to make my program read an integer until a space, namely ' ', is pressed, and then move on to the next command. However, all my attempts hitherto with both scanf() and getchar() have been to no avail. Every time it proceeds to the next command only upon pressing Enter, which is not quite what I want.
View 3 Replies View RelatedA program that asks 10 positive integers and classify them as odd or even positive integer inputs. The algorithm has to trap negative integer inputs. The output will be displayed in two columns. ODD and EVEN.
here's my program code...
#include<iostream>
using namespace std;
main() {
int countA;
for(countA=0;countA<=10;countA++) {
[Code] ....
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream>
using namespace std;
int digcount (int x) {;
[Code]....
I want to make a simple program that will print out the factors of an integer. My program right now only outputs "The prime factors of 221 are 221, 221, 221, 221"... Where it should be "The prime factors of 221 are 1, 13, 17, 221"
#include <cstdio>
int factorsOf(int x);
//function
int main() {
int x = 221;
printf("The factors of 221 are ");
[Code]...
How to write a program without using any type of container .
View 4 Replies View RelatedI want to be able to type a message into another program (such as notepad) using C++. How would I do that? Is there a function to do this, or an event, or something?
View 4 Replies View Relatedfor ex: say i'm declaring two variables under int type and some 3 under char,my output should be lyk this: 2 variables in int and 3 var of type char...(input to the main program is actually another program where these 2 int and 3 char are defined).
View 1 Replies View RelatedYou pros are once newbies like us. Hoped you might take a little time sharing your expertise. Got freaked out when our teacher gave us this activity, where she haven't taught this to us yet. So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
Write a program that asks the user to prompt an Integer number and then test whether it is Palindrome Numbers or not.
The following are Palindrome numbers:
1.22
2.333
3.67876
4.44444
5.123454321
Write a program that prompts the user to enter an integer and then displays that integer as a product of its primes and if it is a prime then it should say so? Above is the question I have been given
#include <iostream>
#include <vector>
using namespace std;
int main () {
int num, result;
cout << "Enter A Number " << endl;
system ("pause");
return 0;
}
This is what I have so far, do I have to use a for loop, a while loop or a do loop,
#include<iostream>
using namespace std;
int main() {
int a[9],x,f=1;
cout<<"Please enter an integer [0-10 only] : ";
[Code] ....
So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
