C :: Program That Displays Each Digit Of Integer In English - Zeros Won't Display
Apr 24, 2014
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code:
#include <stdio.h>
int main (void)
{
int x, y = 0;
printf ("This program displays each digit of an integer in English.
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO) if the input is 23456 the output is : TWO THREE FOUR FIVE SIX if the input is 9349 the output is : NINE THREE FOUR NINE if the input is 245 the output is : INVALID CODE (3 DIGITS) if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code step 2 : count the number of digits in the code step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4 step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS) step 5 : call a function called digit_name to convert each digit into its equivalent english name. display the result step 6 : print the digits in reverse order eg; if input is 13453, reverse order is 35431
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/ #include<stdio.h> int main(void) { //DECLARE VARIABLES int num; }
[code]....
I don't know how the program works if the integer is more than one digit.
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream> using namespace std; int digcount (int x) {;
Write a program that will generate, but not display, a three-digit "target" number that has three distinct digits. (Hint: use random number generator.) Then, input a maximum of ten user guesses and for each guess, output the number of hits and matches in the guess. Stop when the user guesses the number or runs out of guesses. For example, if the target is 427, the guess 207 has one hit (7) and one match (2).
With the loop below, is there a way to display the actual number without the leading zeros (scientific notation) or will it just display 0 since there are so many leading zeros?
num = 1; while (num > 0){ num /= 2; } cout << num;
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cout << "Enter an Integer: " ; for (;;) { cin >> var; if (!cin) {
[Code] ....
I am not sure how to do what I want and this doesn't work, it just repeats That wasn't an int.. over and over again.
so in declaring a display function prototype only that displays a student test scores in the format (student name tab number of scores tab test scores )
is this right?
#ifndef STUDENTTESTSCORES_H #define STUDENTTESTSCORES_H #include <string> using namespace std; class StudentTestScores{ private:
[Code]...
and also how do we call the display function if it is in a class from the header file onto the main cpp file.
#include <cstdlib> #include <iostream> #define TRUE 1 #define FALSE 0 using namespace std; typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
I have been working on some C++ code that doesn't seem to be going right. I'm wanting it to read a (three-digit) integer representing the value to be encrypted, a (one-digit) integer representing the encryption key, encrypt the value and print the encrypted value. The encrypting method used is that each digit in the given number is replaced by ((the sum of that digit plus key) modulo 10) then the first and last “encrypted” digits are swapped.
For example, if the number entered was 216 and the key given was 7, after applying the encryption procedure described the first digit (2) would become 9, the middle digit (1) would become 8 and the last digit (6) would become 3. The first and last encrypted digits are then swapped. The program displays the encrypted number: that is 389 in this case.
#include <iostream> using namespace std; int main() { int isolateDigits(); int replaceDigits(); int swapDigit1withDigit3();
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream> #include <istream> #include <cstdlib> #include <cassert> #include <string> using namespace std; int getIndex(int, int);
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
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Code:
using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text;
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When first input is taken and then second one, the first one's value changes to same as the second. E.G if first name is L and second name is S and after second input both variables, first and sec, become equal to S. Why?
I'm not sure why Im getting a wrong Sum. of the Columns.
Write a method that returns the sum of all the elements in a specific column in a matrix using the following header:
double sumColumn(const double m[] [SIZE], int rowSize, int columnIndex)
Write a test program that reads a 3-by-4 matrix and displays the sum of each column. here is a sample run:
Enter a 3-by-4 matrix row by row: 1.5 2 3 4 5.5 6 7 8 9.5 1 3 1 Sum of the elements at column 0 is 16.5 Sum of the elements at column 1 is 9.0 Sum of the elements at column 2 is 13.0 Sum of the elements at column 3 is 13.0
#include <iostream> using namespace std; const int SIZE = 4; int rowSize=3;
I've read that we can write a program that displays a menu of commands for the user to choose from.We can write some functions that implement these commands, then store pointers to the functions in the array :
We can get a similar effect with a switch statement but using an array of function pointers gives us more flexibility since the elements of the array can be changed as the programm is running.
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Code: TEST2.c:9: warning: initialization from incompatible pointer type TEST2.c:9: warning: initialization from incompatible pointer type TEST2.c:25: error: too few arguments to function "*(arr + (long unsigned int)((long unsigned int)i * 8ul))"
The assignment is to create a program that displays the median of an array using pointers. Assume the array is already in ascending or descending order.I'm getting errors currently on the bottom two "return median;" statements.The code that I have so far is as follows...
#include <iostream> using namespace std; char again; int getMedian(int*, int); const int constant = 100;
