C :: Program That Displays Each Digit Of Integer In English - Zeros Won't Display
Apr 24, 2014
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code:
#include <stdio.h>
int main (void)
{
int x, y = 0;
printf ("This program displays each digit of an integer in English.
[Code] ....
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Jan 23, 2015
I'm trying to create a program that takes an integer input and displays each digit on a new line from right to left.
An example of this would be:
Enter an integer: 657
Digit (1): 7
Digit (2): 5
Digit (3): 6
So far I have this:
#include <stdio.h>
#include <math.h>
int main() {
int i, input, output;
printf("Enter an integer: ");
scanf("%d", &input);
if(input == 0)
printf("Digit (1): 0");
[Code] ....
It works perfectly fine, but I just learned that I am not allowed to use the #include <math.h> so I have to take out floor, log, and pow.
I'm pretty sure I have to do some sort of while or for loop to get the results, but how to do it.
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Jul 13, 2014
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
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Mar 15, 2013
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/
#include<stdio.h>
int main(void)
{
//DECLARE VARIABLES
int num;
}
[code]....
I don't know how the program works if the integer is more than one digit.
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Mar 20, 2014
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream>
using namespace std;
int digcount (int x) {;
[Code]....
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Oct 6, 2014
Write a program that will generate, but not display, a three-digit "target" number that has three distinct digits. (Hint: use random number generator.) Then, input a maximum of ten user guesses and for each guess, output the number of hits and matches in the guess. Stop when the user guesses the number or runs out of guesses. For example, if the target is 427, the guess 207 has one hit (7) and one match (2).
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Mar 7, 2013
Create a program that display all the fibonacci numbers and display the 21st digit using array.
Here's my code:
#include <iostream>
using namespace std;
int main () {
cout<<" This program shows a series of fibonacci numbers
"<<endl;
[Code] ....
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Mar 14, 2013
How would I make the program still display zeros in front of a number?
Like say for example:
cout << "Enter any number";
cin >> number;
cout << number;
Let's say I entered 0003 as my input. How would I make it to where it will display the three zeros in front of the 3 instead of just displaying 3?
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Jan 20, 2014
With the loop below, is there a way to display the actual number without the leading zeros (scientific notation) or will it just display 0 since there are so many leading zeros?
num = 1;
while (num > 0){
num /= 2;
}
cout << num;
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Mar 8, 2013
Is it possible to create a function that can both return and display a value. I was trying to make a program that computes and prints terms of the Fibonacci series using a recursive function.
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Dec 28, 2013
Constructing this right aligned half pyramid? The code I had so far is right aligned and they're not in numbers
Write a program that receives one positive integer and display
_________ _ 1
________ 4 2
_______9 6 3
___16 12 8 4
25 20 15 10 5
when the user key in 5.PS: ignore the line
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Nov 8, 2013
I need to have a program display an error message if the variable entered isn't an integer but then I want it to cin again. I have this but it doesn't work:
cout << "Enter an Integer: " ;
for (;;) {
cin >> var;
if (!cin) {
[Code] ....
I am not sure how to do what I want and this doesn't work, it just repeats That wasn't an int.. over and over again.
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Oct 28, 2013
so in declaring a display function prototype only that displays a student test scores in the format (student name tab number of scores tab test scores )
is this right?
#ifndef STUDENTTESTSCORES_H
#define STUDENTTESTSCORES_H
#include <string>
using namespace std;
class StudentTestScores{
private:
[Code]...
and also how do we call the display function if it is in a class from the header file onto the main cpp file.
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Jan 13, 2014
i need a program which can convert numbers you enter into their respective words till 1 million.
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Oct 19, 2013
this code :
#include <cstdlib>
#include <iostream>
#define TRUE 1
#define FALSE 0
using namespace std;
typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
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Nov 3, 2013
I have been working on some C++ code that doesn't seem to be going right. I'm wanting it to read a (three-digit) integer representing the value to be encrypted, a (one-digit) integer representing the encryption key, encrypt the value and print the encrypted value. The encrypting method used is that each digit in the given number is replaced by ((the sum of that digit plus key) modulo 10) then the first and last “encrypted” digits are swapped.
For example, if the number entered was 216 and the key given was 7, after applying the encryption procedure described the first digit (2) would become 9, the middle digit (1) would become 8 and the last digit (6) would become 3. The first and last encrypted digits are then swapped. The program displays the encrypted number: that is 389 in this case.
#include <iostream>
using namespace std;
int main() {
int isolateDigits();
int replaceDigits();
int swapDigit1withDigit3();
[Code] ....
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Oct 10, 2014
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream>
#include <istream>
#include <cstdlib>
#include <cassert>
#include <string>
using namespace std;
int getIndex(int, int);
[Code] .....
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Oct 22, 2014
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
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Feb 18, 2015
Code:
int exploder(int number,int array[]) {
int functi = 0;
int digit = number % 10;
while (number > 0) {
[Code] ....
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Feb 18, 2013
I am building a linked list and i need to display function i have. The display function displays all the letters of the word entered instead of the word itself. below is my struct, one of my functions and the display function.
Code:
//-----------struct ------------//
struct Node
{
char data;
struct Node *next;
}*Head;
[code]....
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Oct 7, 2012
I'm attempting to write a program that displays an array of labels; however, I can't seen to make the labels appear in the form. I've set some of the properties, but still not luck.
Code:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
[Code]...
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Sep 25, 2014
I was trying to code a program that accepts your first name and then last name and then displays it through another function. I have checked that the assignments are between similar type of variables and pointers, but I don't seem to get it right.
When first input is taken and then second one, the first one's value changes to same as the second. E.G if first name is L and second name is S and after second input both variables, first and sec, become equal to S. Why?
Code:
#include <stdio.h>
#include <stdlib.h>
//FUNCTION PROTOTYPES
char *input(void);
void show(char *f,char *s);
[code]....
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Oct 1, 2014
This is just the portion of my program. This program displays Not Found even if the id number is found.
void search(void) {
char ID[10];
int i, found;
cout<<"Enter ID to search: ";
gets(ID);
found=0;
for(i=0;i<top;i++)
[Code] .....
Here's the incorrect output
Enter ID to search: 111
Not found
Name: jude
ID: 111
Semester: 1
Major: IT
I just want to remove the "Not found".
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Nov 18, 2014
I'm not sure why Im getting a wrong Sum. of the Columns.
Write a method that returns the sum of all the elements in a specific column in a matrix using the following header:
double sumColumn(const double m[] [SIZE], int rowSize, int columnIndex)
Write a test program that reads a 3-by-4 matrix and displays the sum of each column. here is a sample run:
Enter a 3-by-4 matrix row by row:
1.5 2 3 4
5.5 6 7 8
9.5 1 3 1
Sum of the elements at column 0 is 16.5
Sum of the elements at column 1 is 9.0
Sum of the elements at column 2 is 13.0
Sum of the elements at column 3 is 13.0
#include <iostream>
using namespace std;
const int SIZE = 4;
int rowSize=3;
[Code].....
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Aug 1, 2013
I've read that we can write a program that displays a menu of commands for the user to choose from.We can write some functions that implement these commands, then store pointers to the functions in the array :
Code:
void ( *file_cmd[])(void) = { new_cmd , open_cmd }; // 2 cmd's for simplicity
We can get a similar effect with a switch statement but using an array of function pointers gives us more flexibility since the elements of the array can be changed as the programm is running.
I decided to write an example about this in order to understand better the context, I am facing some problems though :
Code:
#include<stdio.h>
#include<stdlib.h>
typedef void (*p_foo) (int);
void foo(int x);
void foo2(int y);
[Code] .....
The problems are :
Code:
TEST2.c:9: warning: initialization from incompatible pointer type
TEST2.c:9: warning: initialization from incompatible pointer type
TEST2.c:25: error: too few arguments to function "*(arr + (long unsigned int)((long unsigned int)i * 8ul))"
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Feb 27, 2013
The assignment is to create a program that displays the median of an array using pointers. Assume the array is already in ascending or descending order.I'm getting errors currently on the bottom two "return median;" statements.The code that I have so far is as follows...
#include <iostream>
using namespace std;
char again;
int getMedian(int*, int);
const int constant = 100;
[code]....
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