C/C++ :: Program Takes Integer Input And Displays Each Digit On New Line From Right To Left
Jan 23, 2015
I'm trying to create a program that takes an integer input and displays each digit on a new line from right to left.
An example of this would be:
Enter an integer: 657
Digit (1): 7
Digit (2): 5
Digit (3): 6
So far I have this:
#include <stdio.h>
#include <math.h>
int main() {
int i, input, output;
printf("Enter an integer: ");
scanf("%d", &input);
if(input == 0)
printf("Digit (1): 0
");
[Code] ....
It works perfectly fine, but I just learned that I am not allowed to use the #include <math.h> so I have to take out floor, log, and pow.
I'm pretty sure I have to do some sort of while or for loop to get the results, but how to do it.
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Apr 24, 2014
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code:
#include <stdio.h>
int main (void)
{
int x, y = 0;
printf ("This program displays each digit of an integer in English.
[Code] ....
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Oct 22, 2014
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
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Mar 15, 2013
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/
#include<stdio.h>
int main(void)
{
//DECLARE VARIABLES
int num;
}
[code]....
I don't know how the program works if the integer is more than one digit.
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Mar 20, 2014
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream>
using namespace std;
int digcount (int x) {;
[Code]....
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Jan 18, 2015
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#include <iostream>
#include <vector>
#include <string>
using namespace std;
int main() {
string x;
vector<string> arguments;
[Code]...
And the error message I receive, a simple but frustrating one, is as follows:
Enter arguments, enter STOP to stop: Segmentation fault...
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Jul 27, 2013
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I am not sure how to do this so for my attempt, I used the formula found in this website. A Formula for the nth Fibonacci number
Here is the program so far. It doesn't produce the correct output.
Code:
#include <stdio.h>
#include "genlib.h"
#include "simpio.h"
#include "math.h"
[Code]....
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Jan 20, 2013
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struct time
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short year;
short month;
short day;
short hour;
short min;
};
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I am wondering if this can be achieved using the standard library, or whether I just need to write a function to perform the appropriate arithmetic.
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Jan 15, 2013
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Mar 9, 2013
Im trying to create a program that has the user input a 5 digit number. If it's between 10000 & 99999, it will do one thing..(just saying 'yes' for now. Outside those numbers will prompt the user to input again. However, if the user inputs the exact digits 76087, it should display 'term'.
This current code is displaying 'term' whenever the user inputs the 5 digits.
Code:
#include <iostream>
using namespace std;
int main() {
int pin;
cout << "Welcome to Movie Food
Enter your 5-digit pin code: " ;
[code]....
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Oct 19, 2013
this code :
#include <cstdlib>
#include <iostream>
#define TRUE 1
#define FALSE 0
using namespace std;
typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
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Nov 3, 2013
I have been working on some C++ code that doesn't seem to be going right. I'm wanting it to read a (three-digit) integer representing the value to be encrypted, a (one-digit) integer representing the encryption key, encrypt the value and print the encrypted value. The encrypting method used is that each digit in the given number is replaced by ((the sum of that digit plus key) modulo 10) then the first and last “encrypted” digits are swapped.
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#include <iostream>
using namespace std;
int main() {
int isolateDigits();
int replaceDigits();
int swapDigit1withDigit3();
[Code] ....
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Oct 10, 2014
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream>
#include <istream>
#include <cstdlib>
#include <cassert>
#include <string>
using namespace std;
int getIndex(int, int);
[Code] .....
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Jul 13, 2014
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
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Code:
#include <stdio.h>
void calcul() {int mark;
char * grade;
if (!(scanf("%d",&mark))){printf("
}
[code]....
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Code:
int exploder(int number,int array[]) {
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[Code] ....
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compiled with -std=c99.
Code:
#include <stdio.h>
int main(){
int maxsize;
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[Code] .....
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Code:
#include <stdio.h>
#include <stdlib.h>
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int Menu ();
int ValidInt(int , int );
[Code] ....
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I have to do this without using vectors.
This is what i have, I cannot figure out what to put in main. I was thinking of a do-while?
Code:
#include <iostream>
using namespace std;
void resize(int *[], int);
int main() {
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[code].....
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Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
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[code]....
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Code:
#include <stdio.h>
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[Code]....
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Code:
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