C++ :: Input Validation For 5-digit PIN Number Read From Integer
Oct 22, 2014
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
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Nov 3, 2013
I have been working on some C++ code that doesn't seem to be going right. I'm wanting it to read a (three-digit) integer representing the value to be encrypted, a (one-digit) integer representing the encryption key, encrypt the value and print the encrypted value. The encrypting method used is that each digit in the given number is replaced by ((the sum of that digit plus key) modulo 10) then the first and last “encrypted” digits are swapped.
For example, if the number entered was 216 and the key given was 7, after applying the encryption procedure described the first digit (2) would become 9, the middle digit (1) would become 8 and the last digit (6) would become 3. The first and last encrypted digits are then swapped. The program displays the encrypted number: that is 389 in this case.
#include <iostream>
using namespace std;
int main() {
int isolateDigits();
int replaceDigits();
int swapDigit1withDigit3();
[Code] ....
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Feb 18, 2015
Code:
int exploder(int number,int array[]) {
int functi = 0;
int digit = number % 10;
while (number > 0) {
[Code] ....
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Jan 23, 2015
I'm trying to create a program that takes an integer input and displays each digit on a new line from right to left.
An example of this would be:
Enter an integer: 657
Digit (1): 7
Digit (2): 5
Digit (3): 6
So far I have this:
#include <stdio.h>
#include <math.h>
int main() {
int i, input, output;
printf("Enter an integer: ");
scanf("%d", &input);
if(input == 0)
printf("Digit (1): 0");
[Code] ....
It works perfectly fine, but I just learned that I am not allowed to use the #include <math.h> so I have to take out floor, log, and pow.
I'm pretty sure I have to do some sort of while or for loop to get the results, but how to do it.
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Mar 9, 2013
Im trying to create a program that has the user input a 5 digit number. If it's between 10000 & 99999, it will do one thing..(just saying 'yes' for now. Outside those numbers will prompt the user to input again. However, if the user inputs the exact digits 76087, it should display 'term'.
This current code is displaying 'term' whenever the user inputs the 5 digits.
Code:
#include <iostream>
using namespace std;
int main() {
int pin;
cout << "Welcome to Movie Food
Enter your 5-digit pin code: " ;
[code]....
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Oct 26, 2014
Write a function which will take 3 arguments. The function needs to return a new number which is formed by replacing the digit on a given position in the number with a digit which is carried as an argument (the position in the number is counted from right to left, starting with one). Write a main program which will print the newly formed number.
Examples:
A function call of 2376, 3 and 5 should return the number 2576
A function call of 123456, 4 and 9 should return the number 129456
What I succeeded to do so far:
Figure out the logic for swapping the digit and write working code for it (in the main function).
What I failed to do so far:
Write a function which will return the desired result.
What is my problem:
I tried writing a function to do this, but as you see from my calculations, my result is divided in 3 parts. I don't know how to return more variables from a function.
Code:
#include <stdio.h>
int main() {
int inputNumber, swapPosition, swapDigit;
scanf("%d%d%d", &inputNumber, &swapPosition, &swapDigit);
int i, numberPart1 = inputNumber;
for (i = 1; i <= swapPosition; i++)
[Code] ...
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Oct 7, 2014
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h>
int * toarray(int *num);
int main(void)
{
int testCases;
}
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases
23456 //input number
6
2293452
4
2293700
1974439125
Process returned 0 (0x0) execution time : 4.152 s
Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
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Oct 19, 2013
this code :
#include <cstdlib>
#include <iostream>
#define TRUE 1
#define FALSE 0
using namespace std;
typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
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Mar 15, 2013
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/
#include<stdio.h>
int main(void)
{
//DECLARE VARIABLES
int num;
}
[code]....
I don't know how the program works if the integer is more than one digit.
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Mar 20, 2014
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream>
using namespace std;
int digcount (int x) {;
[Code]....
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Oct 10, 2014
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream>
#include <istream>
#include <cstdlib>
#include <cassert>
#include <string>
using namespace std;
int getIndex(int, int);
[Code] .....
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Jul 13, 2014
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
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Apr 24, 2014
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code:
#include <stdio.h>
int main (void)
{
int x, y = 0;
printf ("This program displays each digit of an integer in English.
[Code] ....
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Jul 6, 2013
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
#include <iostream>
using namespace std;
int main()
{
int num;
[code]....
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Jul 19, 2013
How do you do the input validation for date? I used:
char rec.date[SIZE];
cout<<"date"<<endl;
cin.getline(date,SIZE);
I want the user to write in this format (mm/dd/yy)
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Aug 14, 2014
// PROBLEM - Use INPUT VALIDATION so number entered is positive. I can't get it to work
#include <iostream>
#include <iomanip>
using namespace std;
int main(int argc, const char * argv[]) {
// SUM OF NUMBERS
// Enter a positive integer
[Code] ....
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Apr 15, 2014
I am having a problem with my "void Validation :: getId()" function its suppose to get the id number from the user but when I try and type a letter to see if it catches it, it goes into this continuous loop. Also with my "string Validation :: getName(string name)" function it suppose to catch the comma in the user input for their last name , first name but doesn't catch it and still returns the name back to main function.
#include "InputValidation.h"
#include <iostream>
using namespace std;
Validation :: Validation() {
name = " ";
id = 0;
[Code] ....
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Jul 11, 2014
I have this function that is supposed to take a float as a parameter and then call the getLine() method to accept the users input. The function basically just checks to see if what the user input was of the same data type, if it is it returns the input value, if not then it keeps looping through taking new input until its correct. The problem is no matter what number you put in the output always returns as 140734799803512.
float InputValidation(){
float num;
string strInput;
while (true){
getline(cin, strInput);
[Code] ....
You also need to include <string> and <sstream>.
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Feb 4, 2014
How I could correctly validate user input when the user inputs a numeric value that will be float pay1, pay2, pay3, pay4. However, the if statement that I wrote crashes after I test the validation. I been told that scanf is dangerous, but strtol works best, but how to write a validation with strtol.
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#include <conio.h>
#define ARRAYSIZE 2
#define FORMAT "First Name Pago1 Pago2 Pago3 Pago4 Total Net"
#define FORMATHEADER "Last Name "
[Code] ....
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Apr 9, 2014
write a c++ program that reads an unknown number of integer values and then print count, sum and average of odd values, even values, positive values, negative values!!
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Dec 20, 2014
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code:
while (1>0) {
printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity:
");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) {
printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
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Jul 18, 2013
I have not completed this program yet, but I have already run into a snag. For the Input Validation part, every time you enter a number regardless if it is positive it will still display the cout statement: "Please enter positive values". The program runs correctly where I currently am at, but it just keeps reading that statement even if a user enters a positive value. I have run the debugger, but it really is not showing me anything other than I notice it jumping to that statement after every value that is entered.
Here is my code, once again I have not finished this yet, but I would really like to get this fixed first before I continue. I will keep debugging in the meantime...
Code:
// A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write a program that stores this information in a two-dimensional 3 X 7 array, where each row represents a different monkey and each column represents a different day of the week. The program should first have the user input the data for each monkey. Then it should create a report that includes the following information:
// Average amount of food eaten per day by the whole family of monkeys.
// The least amount of food eaten during the week by any one monkey.
// The greatest amount of food eaten during the week by any one monkey.
// Input validation: Do not accept negative numbers for pounds of food eaten.
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
double totalAverage = 0; // variable to store the total average, initalized to zero
[Code] ......
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Nov 12, 2014
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
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Oct 23, 2014
I need validation on what the user inputs. Input should not be an alphabet, empty, and not negative number. This program is for finding the GCD and LCM of multiple numbers.
#include <stdio.h>
void bubble_sort(int numbers[], int len) {
int i, j;
int swapped;
[Code] .....
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Jun 23, 2014
it will not run and im not sure why. I have a couple of errors, but I'm not sure why.
Here is my code.
//Reads input from user to determine different discounts by number of units sold
#include <iostream>
#include <string>
using namespace std;
int main() {
//Declaration and Initialization of variables
int quantity;
double discount,price = 99.00,totalCost;
[Code] ....
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May 14, 2013
I am trying to get this simple validation loop to work so that it only displays the error message when the input is outside the range 1-3. yet it always seems to display the message.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int Menu ();
int ValidInt(int , int );
[Code] ....
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