C++ :: Input Validation - Program Cannot Accept Negative Numbers
Nov 12, 2014
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
I need validation on what the user inputs. Input should not be an alphabet, empty, and not negative number. This program is for finding the GCD and LCM of multiple numbers.
#include <stdio.h> void bubble_sort(int numbers[], int len) { int i, j; int swapped;
I need a program to run that will accept an input for user id. It will take the customer input and capitalize the letters, and return invalid id with the user inputted values. Then if it's valid it will add a counter counting the number of letters and numbers. It will keep track until the user puts in !. It seems when I try to pass values from the array to my toUpper function to capitalize it it doesn't seem to work right.
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
I am making a program which is going to print out a head image according to the input values entered by the user. Here is the code:
Code: #include <iostream> #include <string> using namespace std; void Sides() // draws the sides to take proportion
[Code] .....
At first i tried to work program like:
Code: cout << "plase enter which way you want to print out the head, with parted hair or bald." << endl; cin >> headstyle; if (headstyle != "bald" || headstyle != "parted hair" )
But it also had given the same mistake. The program compiles BUT; even if I put in the values bald or parted hair the program prints out "wrong input" then exits.
I have to write a program that uses negative numbers in a conjecture algorithm. The program terminates when a number is reached that was already outputted. I can not get it to work and I have been racking my brain for a week.
#include <iostream> using namespace std; int main() { int x[1000], y[1000], i=0, j=0, count=0, w=0, z[1000], t = 0;
I having some issues with two different programs here... One of them crashes and returns random negative numbers whenever it reaches a "fscanf" function and the other displays a "Polink fatal error: access denied" error.
I thought the reason this kept crashing before was because I didn't type the data into the text file it was writing too correctly, but I made another program to do that, and it crashed whenever it got to fprintf. Program works perfect besides the file stuff...
I am having a problem with my "void Validation :: getId()" function its suppose to get the id number from the user but when I try and type a letter to see if it catches it, it goes into this continuous loop. Also with my "string Validation :: getName(string name)" function it suppose to catch the comma in the user input for their last name , first name but doesn't catch it and still returns the name back to main function.
#include "InputValidation.h" #include <iostream> using namespace std; Validation :: Validation() { name = " "; id = 0;
I have this function that is supposed to take a float as a parameter and then call the getLine() method to accept the users input. The function basically just checks to see if what the user input was of the same data type, if it is it returns the input value, if not then it keeps looping through taking new input until its correct. The problem is no matter what number you put in the output always returns as 140734799803512.
float InputValidation(){ float num; string strInput; while (true){ getline(cin, strInput);
How I could correctly validate user input when the user inputs a numeric value that will be float pay1, pay2, pay3, pay4. However, the if statement that I wrote crashes after I test the validation. I been told that scanf is dangerous, but strtol works best, but how to write a validation with strtol.
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <string.h> #include <conio.h> #define ARRAYSIZE 2 #define FORMAT "First Name Pago1 Pago2 Pago3 Pago4 Total Net" #define FORMATHEADER "Last Name "
I want to accept numbers from the user into an array and convert into corresponding alphabets. E.g 1 into A, 2 into B, and so on.
This is simple, but the problem is the user is supposed to enter the character # also which I want to display as it is in the output. How can I do this ? What type of array should be used - int or char?
What I want to do with my program is I want my length, width,volume and price to accept number values only. This is what I have so far.
// This program calculates and displays the pool's volume // the amount of water needed and the cost.
#include <iostream> #include <iomanip> using namespace std; int main() { // the double type accepts numbers including fractions for the following inputs. double length, width, depth, poolvolume, watervolume, price;
I'm trying to validate my input. I require for the user to enter six doubles and if they don't then I want them to re-enter the information. Here is my code:
Code: while (1>0) { printf("Please enter arguments in the order: negative mass, positive mass, initial x-position, initial y-position, initial x-velocity, initial y-velocity: ");
if ( scanf("%lf %lf %lf %lf %lf %lf",&MassMinus,&MassPlus,&Pos[0][0],&Pos[0][1],&Vel[0][0],&Vel[0][1]) != 6) { printf("Not all numbers were assigned!
[Code] .....
At the moment it just waits if you enter less than six numbers and if you enter any more than 6 it just ignores anything after the sixth number (so pretty much does nothing). Also if I entered 1 2 a b 3 4 instead of entering six numbers it would register that as 1 2 0 0 3 4 but I want it to make the user input the numbers again. I'm also aware that "while (1>0)" isn't good programming form but I'm not really sure what to use instead?
I have not completed this program yet, but I have already run into a snag. For the Input Validation part, every time you enter a number regardless if it is positive it will still display the cout statement: "Please enter positive values". The program runs correctly where I currently am at, but it just keeps reading that statement even if a user enters a positive value. I have run the debugger, but it really is not showing me anything other than I notice it jumping to that statement after every value that is entered.
Here is my code, once again I have not finished this yet, but I would really like to get this fixed first before I continue. I will keep debugging in the meantime...
Code: // A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write a program that stores this information in a two-dimensional 3 X 7 array, where each row represents a different monkey and each column represents a different day of the week. The program should first have the user input the data for each monkey. Then it should create a report that includes the following information:
// Average amount of food eaten per day by the whole family of monkeys. // The least amount of food eaten during the week by any one monkey. // The greatest amount of food eaten during the week by any one monkey.
// Input validation: Do not accept negative numbers for pounds of food eaten.
#include <iostream> #include <iomanip> using namespace std;
int main() { double totalAverage = 0; // variable to store the total average, initalized to zero
class Program { //Accept two input parameter and returns two out value public static void rect(int len, int width, out int area, out int perimeter) { area = len * width; perimeter = 2 * (len + width);
[Code] .....
why is the static keyword required in the method signature for the rect() method. It will not compile if it is absent. why?
the same is true for this example:
class Program { static void printvalues(params int[] passedin) { foreach (var printthis in passedin) { Console.WriteLine(printthis);
[Code] ....
This code won't compile without the static keyword in the printvalues() method signature. why?
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
I've been experimenting a bit and can't find a decent way to make a brute forcing script that accepts a password from standard input, and goes through all possible combinations until it is matched. How to structure the code?
I am trying to get this simple validation loop to work so that it only displays the error message when the input is outside the range 1-3. yet it always seems to display the message.
I am writing a program to display a triangular pattern using nested loops and user input for the size of the base and character used to generate the image. 99% of the program runs fine. However I am having trouble with some of my input validation.
When given an integer value for the base I can verify if it is within a certain range (0-80). However, when the user inters a "char" instead of an "int" the program enters an infinite loop.
Here is the piece of code giving me trouble. (I wont bother you with the entire chunk of code, I have commented out everything else to narrow down the problem bit)
// Pattern Displays // program that asks user for the size of the base of a triangle and then generates it in a character the user chooses
#include <iostream> #include <istream> #include <string> #include <cstdlib> using namespace std; int main () { char escape;
I have a program where the user inputs a line of numbers, and the two highest ones are displayed. It works fine, until negative values are entered at which point it shows 0 as the result.
Code: #include <iostream> using namespace std; int main( ) { int num = 0; int highest = 0;
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h> int * toarray(int *num); int main(void) { int testCases; }
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases 23456 //input number 6 2293452 4 2293700 1974439125
Process returned 0 (0x0) execution time : 4.152 s Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
