I need to ignore negative values in an array, but not exit the function.
For example if the user enters:
1,2,3,4,-1,-2,0
the array would be
[1,2,3,4]
Is there a way to ignore these values?
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
View 4 Replies View Relatedignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
I have a problem with my assignment. I would like to ask how to transfer positive and negative values from array temperature to arrays positive and negative?
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int n=0, d=0, temperature[20], sum;
int positive[], negative[];
float avg;
[code]....
I have a function that rotates a vector 90 degrees. Only problem is, i never get negative values. For some strange reason, no matter what i do, the value of x is positive. And even if the x is negative. Once i put it into direction (struct with 2 values x and y) it turns again to positive. Im using VSC++2013 ultimate. At first direction was SDL_Point, so i thought it was SDL problem, but now it seems its something else.
if (c == '-') {
int x = direction.y;
x *= -1;
int y = direction.x;
direction = { x, y };
}
I just wanted to ask the reason that why is the below code not checking the case -1 while working for the other case values.
#include<stdio.h>
#include<conio.h>
int main() {
int i=-1;
switch(i-2) {
[Code] ....
So why in the below code the case -1 doesnt run,when the value evaluated by the switch construct is actually a negative integer constant.
Having error . I multiplied 0 by -4 and my result is -0 instead of 0. I tried to change the data type put It won't work. This is my code:
#include <iostream>
int main () {
double b, c;
std::cout<<"b: ";
std::cin>>b;
std::cout<<"c: ";
std::cin>>c;
std::cout<<b*c<<std::endl;
return 0;
}
I have an array of array with negative index. It is an array which has real dimensions [dim_y + 40][dim_x + 40] but the user uses the array like it has dimensions [dim_y][dim_x].
So i see the array's rows lets say from -20 to dim_y + 20 but a user sees only from 0 to dim_y.
First i had global and already defined the dimensions dim_x, dim_y, so i had this:
Code:
int map_boundaries[dim_y + 40][dim_x + 40];
int (*map)[dim_x+40] = (int(*)[dim_x+40])&map_boundaries[20][20]; In fact, 'map' points to 'map_boundaries' , map[0][0] is map_boundaries[20][20].
I did what is posted in the second post here: Negative array indexing - Everything2.com
I want 'map' to be global. Until now i had defined the dim_y and dim_x so that worked fine.Now i just need to read from a user the dim_x and dim_y.
Until now i have global
Code: int **map_boundaries;
and then in main i use calloc:
Code:
map_boundaries = (int **)calloc(dim_y + 40,sizeof(int*));
for(i = 0; i < dim_y + 40; i++){
map_boundaries[i] = (int *)calloc(dim_x + 40,sizeof(int));}
but i dont know how to declare this line now:
Code: int (*map)[dim_x+40] = (int(*)[dim_x+40])&map_boundaries[20][20];
I have an array of array with negative index. It is an array which has real dimensions [dim_y + 40][dim_x + 40] but the user uses the array like it has dimensions [dim_y][dim_x].
So I see the array's rows lets say from -20 to dim_y + 20 but a user sees only from 0 to dim_y.
First I had global and already defined the dimensions dim_x, dim_y, so i had this:
int map_boundaries[dim_y + 40][dim_x + 40];
int (*map)[dim_x+40] = (int(*)[dim_x+40])&map_boundaries[20][20];
In fact, 'map' points to 'map_boundaries' , map[0][0] is map_boundaries[20][20].
I did what is posted in the second post here: [URL] ....
I want 'map' to be global. Until now i had defined the dim_y and dim_x so that worked fine. Now I just need to read from a user the dim_x and dim_y. Until now i have global
int **map_boundaries;
and then in main i use calloc:
map_boundaries = (int **)calloc(dim_y + 40,sizeof(int*));
for(i = 0; i < dim_y + 40; i++){
map_boundaries[i] = (int *)calloc(dim_x + 40,sizeof(int));
}
But I dont know how to declare this line now:
int (*map)[dim_x+40] = (int(*)[dim_x+40])&map_boundaries[20][20];
So i have this program that takes in user input and stores them into an array and then prints them, removes duplicates, and sorts in ascending order. The user can also stop by inputting a sentinel value (in this case -1). But i am also supposed to ignore any negative value besides -1. When i input any other negative value into the program it messes up. How would i go about ignoring the negative values?
Code:
#include<stdio.h>
int main()
{
int input, nums[20], i, j, k, temp, count=0, count2=0;
for(i=0;i<20;i++)
[Code] .....
Goal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
to:
char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
cin>>a2[i];
Place the even lucky numbers in an array called evenList, the odd lucky numbers in an array called oddList, and the negative lucky numbers in an array called negList.
//So in main main i passed the array as parameter and the size;
void lucknumberlist(int favnum[], int size) {
int even = 0, odd = 0, neg = 0;
int evenArray[even];
int oddArray[odd];
int negArray[neg];
if(favnum[even] % 2 == 0) {
evenArray[even] = favnum[even];
[Code] .....
I'm using a Windows.System.Forms.Webbrowser and the document text contains
...<style type="text/css">
Table {
page-break-after: always;
}
table:last-of-type {
page-break-after: auto
}
</style>...
As soon as call ShowPrintPreviewDialog() to show the print preview dialog, it appears to be ignoring
table:table:last-of-type
because the last page in the document is blank.
How I can manipulate certain strings. This program here is supposed to randomly scramble any word/sentence input. However, I notice that even the empty spaces get moved; is there any way to stop that from happening? I would want the empty spaces to stay in their input positions.
#include <iostream>
#include <string.h>
#include <ctime>
#include <cstdlib>
#include <fstream>
#include <string>
using namespace std;
[Code] ....
Now, I have an assignment in which I am to accept arguments from the command line and copy them into a cstring and display said cstring unmolested. Then I should store it into another cstring but ignore all punctuation, spaces and capital letters. Like this:
./a5 Marge lets Norah see Sharon's telegram
As is: Marge lets Norah see Sharon's telegram
---->: margeletsnorahseesharonstelegram
<----: margeletsnorahseesharonstelegram
Sequence entered is a palindrome
=======================================================
Finally I am to chaeck to see if it is a palindrome. Most of it works and if no spaces are entered nor punctuation it works. However, punctuation causes it to malfunction.
char *FormSeqProc (int argc, char *argv[], char seqAsIs[]) {
int len = 0,
n = 0;
for (int p = 1; p < argc; ++p) {
len += strlen(argv[p]);
[Code] ....
It should report whether or not, ignoring case, they are the same.
#include <stdio.h>
#include <string.h>
using namespace std;
[Code].....
My program had a requirement to ignore an input beginning with a # sign. The input is entered by user from keyboard. I wanted to know how to use cin.ignore to achieve this.
#include <iostream>
#include <algorithm>
#include <string>
#include <iomanip>
#include <limits>
#include <stdio.h>
using namespace std;
[Code] ....
The output:
Enter the string
# Comment
This is the # comment string.
Answer:
This is the string.
My random number generator isn't working properly. It seems to be ignoring my conditions when it compiles and I enter the input. The program is supposed to accomplish the following.
1. Let the user input how many digits he or she would like to have in the random numbers.
2. Let the user type in how many of the numbers that he or she wants.
3. It will then generate the numbers.
4. It will display the minimum or maximum number it can be with the number of digits the user entered. And display the number of numbers that the user wanted. It also is supposed to check and output only up to the max of that digit range.
so if someone entered they wanted a digit of 1(1-9) but said they wanted 300 numbers it would only output 9
Example:
the user says that she would like 3 digits to be in the numbers generated. So it will output numbers between 100 and 999. then the user says that they would like only 3 random numbers. So it will output three random numbers in between 100 and 999. Also all of the numbers need to be unique so they can't output more then one of the same number.
I am not sure why but it ignores my conditions. Ill type that I want 7 but it just outputs a bunch of random numbers. it dosen't stay in the ranges.
Class file.
Code:
#include "stdafx.h"
#include <fstream>
#include <iomanip>
#include <iostream>
#include <string>
#include <conio.h>
#include "TargetGen.h"
using namespace std;
[Code] .....
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
But it can the other way around
Code:
static_Array= dynamic_Array;
dynamic_Array = static_Array;
The second statement works and i'm able to print out both arrays with equal values but with the first
[code] static_Array = dynamic_Array;I get incompatible types in assignment of 'int*' to 'int [7]' is the error I get [/code]
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) {
int rs=secfunc(array1;size1;array2[q])
if(rs>=0) {
cout<<rs << "";
[Code] .....
use 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replies View RelatedHow can I Figure out and store the sum of EACH COLUMN in the 2D array values in a 1D array? And to the same for the average?
View 1 Replies View RelatedIts output is not correct
#include <stdio.h>
void main() {
int n,i,j,option;
int evensum=0;
int oddsum=0;
[Code] ....
I tried sorting arr2 from lowest to highest value, but it only gives me 4 values and then the rest are zero.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
cout << fixed << setprecision(1);
[code].....
