C++ :: Find K Nearest Neighbors Of All Points On 2D Space?

Oct 8, 2014

In this project you are asked to find K nearest neighbors of all points on a 2D space. The distance metric that you are going to use is simply the Euclidean distance example;

inputs:
10 2
3.57 3.18
84.91 27.69
93.40 4.62
67.87 9.71
75.77 82.35
74.31 69.48
39.22 31.71
65.55 95.02
17.12 3.44
70.60 43.87

Outputs:

1 9 7
2 10 3
3 2 4
4 2 3
5 6 8
6 5 10
7 10 9
8 5 6
9 1 7
10 2 6

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C++ :: Store Coordinates As X And Y In A Vector To Find Nearest Neighbor Of Given Points

Oct 13, 2014

Lets say that i have the coordinates of a 2D space (x and y), I want to store the coordinates as x and y in a vector to find the nearest neighbor of given points like i have:

#3.57 3.18#
#84.91 27.69
#93.40 4.62
#67.87 9.71
#75.77 82.35
#74.31 69.48
#39.22 31.71
#65.55 95.02
#17.12 3.44
#70.60 43.87

Each coordinates is like x y and it shows points 1 to 10 (like 3.57 3.18 is point 1 in 2D space ). My question is that how i add all x and y coordinates in vector? I started like this;

`struct point{
int x;
int y;

[Code] ....

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Nov 19, 2014

I have to do a project where a file with 60 rows and 17 columns is stored in an array. The purpose of the project is to find all the "peaks" and "valleys". A peak is considered a number that has a higher value than all 8 of its neighbors, while a valley is a number that has a lower value than all 8 of its neighbors. Here is an example where peaks are bolded and valleys are underlined.

2558632321342150
3245434041323027
3440383936283035
4045424832342932
3939404247492730
3131313232334435

I'm having trouble coming up with the code that will find values that are higher/lower than all 8 of their neighbors.

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Nov 3, 2014

Example: In a 2-D space, point A=(a1,a2) is bigger than point B=(b1,b2), if a1>b1 and a2>b2.

How do I write a presudo code to find all the maximal points among the given n points?

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May 7, 2013

I would like a to plot a 3d graph that connects with lines some points in 3d space.

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Jul 3, 2013

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C :: Rounding To The Nearest Cent?

Feb 4, 2014

I'm having trouble with rounding to the nearest cent in this program. It's the only thing that i need. The result i need is just off by one cent. I tried multiplying the interest amount by 100 and adding .5 then dividing all that by 100 but that just made it worse. Here's the code:

Code:
#include <stdio.h>
int main()
{
int count=0;

[Code]....

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Mar 9, 2014

How do I round to the nearest half integer?

Example;
0 to 0.2 = 0
0.3 to 0.5 = 0.5
0.6-0.9 = 1

What's the formula for C++?

I found a way to do it in math but I want to know what I'd have to put in C++. It's (x*2+.5)remove decimal numbers and divide by 2. What do I put in place of "remove decimal"?

For ex; x = 8.4 using (x*2+.5)remove decimal then divide by 2.
8.4 * 2 = 16.8
16.8 + .5 = 17.3
17.3 - decimal = 17
17/2 = 8.5

I want to do something like;

cout << " Half number: << (x*2+.5)remove decimal/2 << endl;

What would I have to put in place of "remove decimal"?

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C Sharp :: Rounding Up To Nearest 100

Jul 28, 2012

Rounding a numerical figure up to the nearest hundred. E.G.:

256 >> 300
654 >> 700
15 >> 100

I would like to know the formula to enter into Visual Basic 2008. I'm making a calculator Program, and i need a function that rounds up to the nearest 100...

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Nov 19, 2013

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C++ :: Angle Between Two Points

Apr 19, 2014

i'm working on a robotics project, to move the robot from it's current position to target position i need to calculate the angle first before i can move the robot.this the code I use to calculate the angle:

double cal_angle ( int current_x , int current_y , int tar_x , int tar_y )
{
return atan2(tar_y - current_y, tar_x - current_x);
}
int main ()

[code]....

as u can see the angle between x4,y4 to x1,y1 should be 3.14 (180)however , the result are correct as long as the distance from the current position to target position > 1 (not sure actually).

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Apr 14, 2013

Write a program that creates the output shown in the Output Layout section below. The program should create 2 points with x and y coordinates as integers, prompt the user to input the x and y values for one of the points and randomly set the other (-99 to 99 range) and output the length of the radius line segment and the area of the circle that radius defines. The program should then end. Include an SDM for the program and any other appropriate documentation.

Special Calculations:
Distance between 2 points equation:
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Output Layout: (bold text represents user input)

Please enter the location of your first point.
Enter a value from -99 to 99 for your x coordinate: -2
Enter a value from -99 to 99 for your y coordinate: 17

The location of your second randomly set point.
Your x coordinate: 45
Your y coordinate: -89

The length of the radius line segment from point one to point two is 115.
The area of the circle with a radius of 115 is 41546.33.

Other:

int pAx;
int pAy;
int pBx;
int pBy;

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Nov 7, 2013

I have 2D points written in {x1, y1, x2, y2, x3, y3, .....}

#include <iostream>
#include <vector>
#include <math.h>
#include <algorithm>
using namespace std;
int main() {
vector<double> vec;
vector<double> vec_ordered;

[Code] .....

Result.

6 4
6 3
6 2
6 1
5 5
5 1
4 4
4 1
3 3
3 1
2 2
2 1
1 1

which wrong result

I wanted to make

6 3
6 2
6 1
5 1
4 1
3 1
2 1
1 1
2 2
3 3
4 4
5 5

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"main.cpp"
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[code]....

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--------------------------------------------------------------------------------

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PS : Finding the min. distance between sorted x right and x left works fine , only problem is with the strip.

#ifndef CLOSESTPAIR_H_
#define CLOSESTPAIR_H_
#include <float.h>
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My program will compile correctly but when attempting to run the actual program it doesnt do anything and some how completely skips over my main function...

Code:

#include <stdio.h>
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[Code] ....

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unsigned int * find_factors_using_recursion(unsigned int x ) {
unsigned int * factor = new unsigned int[];//do i put x in here ?
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if(x % i == 0) {
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*factor = (factor[i] = i);
} }
return factor;
delete [] factor;
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#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
using namespace std;
int main(int nNumberofArgs, char* pszArgs[]){
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[Code]...

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1111
1111
1111

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1101
1111
1111

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