I was told to use a round function to round a number to give an integer number that is closer to the real value. (for example if the number is 114.67 I need to print an int value of 115 instead of 114)
I am not exactly sure how a round function works, but I am told to include math.h library. What I try doesn't seem to work.
I am a very very beginner at programming with C. Well, basically i have to generate a real number between 0 and 1 (which as the same as from 0 to 100 k and than dividing everything with 100 k).
Why I am constantly talking about 100 k? Because I would need approx 50 000 random numbers between 0 and 1. My code currently looks something like this:
Code:
int main(int argc, char** argv) { int min,max;
double number;
srand((unsigned)time(NULL));
number = 1 + rand()%100;
printf("The number is: %lf",number);
sleep(2);
return (EXIT_SUCCESS);
}
And If I am not mistaken, should generate numbers between 0 and 100. But I can't figure it out how to change to code in order to get enough numbers.
All I want is to let the user enter a value such as .55 or say, .34 and use that in a calculation.
I cannot get passed the errors.
double theRate;
double totalMileage;
double amountOwed;
private void btnCalculate_Click(object sender, EventArgs e)
[Code] ....
So how do you get numeric input from a user?
I need codes for a program in C or C++ that will show the real factor (the smallest one, without the number 1) when an integer is given as input.
When the program is started, it will ask to enter a number and press enter. After entering a number, it will first check if it is a prime number or not. If prime, it will notice that it is a prime number, otherwise, it will print the smallest real factor of the given integer.
For example, if 12 is entered, it will print, the smallest real factor for this number is: 2
If 27 is entered, it will print, the smallest real factor for this number is: 3
...and so on
How can I generate a pseudo-random real number from interval [0,1] ?
Can it be generalized to any interval? Like [0,a], where 'a' is a parameter?
I tried searching for it, I only found rand(), srand(), random(1), and randomize. None of it actually seems to work for me..
Later I actually succeeded with something like
srand( (unsigned)time( NULL ) );
printf( " %6d
", rand() );
but it only produces up to five digits integers and I cannot divide by 99999 to get it into [0,1].
I want to generate random numbers of normal distribution and use scentence like
std::default_random_engine generator;
std::normal_distribution<double> distribution(0,1);
arrayX[i][j]=distribution(generator);
But I find that each time the array I got are the same. So how should I generate random numbers with different seedings with normal distribution?
I must create a function with a integer number as parameterThis function use the parameter for a loop...example
n = 1
output
1
2
3
n = 2
1,1
1,2
1,3
2,1
2,2
2,3
3,1
3,2
3,3
I'm writing a function that stores a number into an array. If the number is greater that the lowest number in the array then it replaces it. The array size is 10. When the number is stored in the array. The lowest number must then be remove.
View 3 Replies View RelatedI want to write a function which take an integer and return the number of digits in it i.e
int i = 123456
func(i) {
some code
}
output
the number of the digits are 6
I'm saving the images in folder by using:
webClient.DownloadFile(href, sourcepath);
I don't want to give name as Current date and time..shown in given below code
string sub = @"Gadhada";
DirectoryInfo subFolder = dir1.CreateSubdirectory(sub);
Imagename = DateTime.Now.Year.ToString() + DateTime.Now.Month.ToString() +
[Code].....
I want to save my imagename as 1.jpg, 2.jpg, 3.jpg.
All my code is good, except the functions: findMacLoc and findMinLoc .They don't give me the correct array location of the max/min number in the array.I know is something simple I need to tweak in those two functions.
#include <iostream>
#include <time.h>
using namespace std;
void printArray(int a [], int & size)
{
int i;
for (i = 0; i < size; i++)
cout << a[i] << " ";
[code].....
i have only recently got into programming. i have this homework assignment that is frying my brains, the program needs to take a number from the user and give the 'reduced' sum. for example: if the user enters 888 then the sum should be: 6. it takes the number and adds its digits im just looking for a direction to where my problem is
#include "iostream.h"
int reduction (int number) {
return number/10+number%10;
}
int main() {
int number,loopcount;
cout<< "please enter a number"<<endl;
cin>>number;
[Code]...
Code:
int exploder(int number,int array[]) {
int functi = 0;
int digit = number % 10;
while (number > 0) {
[Code] ....
I have two unassigned variables A,B . My program goes as follows
#include <iostream>
#include <string>
#include <cmath>
#include <stdlib.h>
using namespace std;
bool die (const string & msg);
[Code] ....
This a program that makes a calculator in which this is a small portion of it, all the exponent numbers work exceptfor anything ending in 5.
Examples go as follow 2^3=8, 3^2=9, 5^2=24
I want to why this happens, is it because they are unassigned variables?
I have created an error message if the user inputs the wrong selection number
if (choices < 1 || choices > 5)
{
cout << "
Please Enter a number between 1-5
";
}
How would i create a error message if the user inputs letters/words instead of a number.
I am currently working on an assignment.
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
char letter;
int count = 0;
double ppl = 0;
double finalCost = ppl * (count - 1);
[Code] ....
I am trying to create a word counter program that asks for the price per letter and then asks for the sentence they are writing. The app should then calculate the number of letters and give the total cost similar to:
You have 40 letters at $3.45 per letter, and your total is $138.00.
Everything compiles fine but when I run it the inputs don't work and it outputs:
You have -1 per letter, and your total cost is $-0.
I have a float values I'd like to round off to the nearest integer value.
That is to say, if the float value is 44.234533, the integer value should be 44. If the float value is 44.682101, the integer value should be 45.
How do I do this?
0 down vote favorite
I want to perform operation like prime,armstrong finding etc on in C using very large number, bigger data types supported by C. scanf and print. I tried CLN and GNUMP library but I did not get clue how to use it...
I need to read a float number and show the rest of his division by an integer, but i'm having the following error message:
Quote
error: invalid operands of types 'float' and 'int' to binary 'operator%'
how I would easily round a double or a float to the nearest cent. It was easy enough to do it in visual basic or java, But i cannot figure out how to do it in C.
View 6 Replies View RelatedWrite a program that reads four integers from a file ‘input.txt’.
The program will then create a single integer number from the four integers. The output of the program will be the single number and single number + 600.
#include <iostream>
using namespace std;
int main () {
int number , a;
cout<<"enter en integer number";
cin>>number;
cout<<"add 600 to the number"
cin>>a=number+600;
return 0;
}
I am working on an assignment about converting an integer number to its 2's complement presentation. The binary representation is consisting of a single linked list.
As we all know, the steps of this converting is to taking the reminder of the absolute value, then flipping the 1 to be 0, and the 0 to be 1 in the binary number. And the last step will be to add 1 to the binary number invers.
I wrote a code that implements every thin correctly. However, when I reached the part of adding 1, the program was hanged.
int Absolute; //the first step is to convert the number to the binry reprezentation
Absolute = abs (value);// by take the Absolute value of the negative number, then find the
while (Absolute !=0) //the binary reprezentation {
int res;
res= (Absolute % 2);
pushFront (res);
Absolute /=2 ;
[Code] .....
Write a program that asks the user to prompt an Integer number and then test whether it is Palindrome Numbers or not.
The following are Palindrome numbers:
1.22
2.333
3.67876
4.44444
5.123454321
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
View 2 Replies View RelatedWrite a program that plays the game of guess the number.the program chooses the number to be guessed by choosing an integer at random in the range 1-1000. The program then types 'i have a number between 1 and 1000,can you guess number? Then the player then types the first guess, the program responds.
View 1 Replies View RelatedThe function uses a "for" loop to print the given character the number of times specified by the integer.
How can I make a for loop to do that?
So.. my code looks like this:
// cpp : Defines the entry point for the console application
//
#include "stdafx.h"
#include <iostream>
using namespace std;
void printMyInteger(int myInteger, char myChar) {
[Code] ....
So.. here is my error:
Error1error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
Error2error C2143: syntax error : missing ';' before ')'d:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp101Week 6
3IntelliSense: expected an expressiond:workspaceuniversity ools for games and animationworkshopsweek 6week 6week 6week 6.cpp107Week 6
