I am a very very beginner at programming with C. Well, basically i have to generate a real number between 0 and 1 (which as the same as from 0 to 100 k and than dividing everything with 100 k).
Why I am constantly talking about 100 k? Because I would need approx 50 000 random numbers between 0 and 1. My code currently looks something like this:
Code:
int main(int argc, char** argv) { int min,max; double number; srand((unsigned)time(NULL)); number = 1 + rand()%100; printf("The number is: %lf",number); sleep(2); return (EXIT_SUCCESS); }
And If I am not mistaken, should generate numbers between 0 and 100. But I can't figure it out how to change to code in order to get enough numbers.
I'm trying to write a program that generates a random number between 50 and 200. I made a program that generates random numbers, but how to make those random numbers be in-between 50 and 200. Any example of a program that generates random numbers that are confined in-between certain values?
So I have to generate a random number between 1 and 6 and then store that same random number into an int variable. Eg, if the random number is 4, that must be stored into int i.
My program asks me to write a C++ program that generates a random number between 1-100, and lets the user guess the number until he/she guesses correctly.
I have every thing done but my loop will not end. I know I have to "update" the loop to end it but I don't know what that means.
#include <iostream> #include <iomanip> #include <ctime> using namespace std;
int main() { srand(time(NULL)); //the function that generates random numbers
I have to write a C++ program that picks a random number between 0 and 49. If the number is even lets say 30, then the computer will display 30, 32, 34, 36... all the way till 100, if its odd lets say 17, then the computer will display 17, 19.. till 99. I got the computer picking a random number, I just can't figure out how to display every other number using a for loop statement. Here's my code for random number generator:
#include <iostream> #include <cstdlib> #include <ctime> using namespace std; int main()
I've been currently stuck on a C++ problem. Here's the question:
Write a program that generates one hundred random integers between 0 and 9 and displays the count for each number. (Hint: Use rand()
% 10 to generate a random integer between 0 and 9. Use an array of ten integers, say counts, to store the counts for the number of O's, l 's, . .. , 9's.)
I think I'm pretty close, but I keep on getting "0" for the occurrences (or counts) of each random integer.
#include <iostream> #include <cstdlib> #include <ctime> #include <conio.h> #include <fstream> using namespace std; const int SIZE = 100;
I was told to use a round function to round a number to give an integer number that is closer to the real value. (for example if the number is 114.67 I need to print an int value of 115 instead of 114)
I am not exactly sure how a round function works, but I am told to include math.h library. What I try doesn't seem to work.
I'm having some trouble finishing my code, it's meant to give the number of twin primes between an interval e.g. 1 to 1000000 and the answer should be 8169 but all I can get it to is 8168
#include <stdio.h> int prime (int num) { int div; if (num == 2) return 1; if (num % 2 == 0) return 0; div = 3; while (div*div <= num) {
I need codes for a program in C or C++ that will show the real factor (the smallest one, without the number 1) when an integer is given as input.
When the program is started, it will ask to enter a number and press enter. After entering a number, it will first check if it is a prime number or not. If prime, it will notice that it is a prime number, otherwise, it will print the smallest real factor of the given integer.
For example, if 12 is entered, it will print, the smallest real factor for this number is: 2
If 27 is entered, it will print, the smallest real factor for this number is: 3
I'm trying to generate random numbers so that I can assign people to teams. So far I have come up with this
Code:
int generateTeam(){ int i, teamNumber, c, n; for (c = 0; c <= 5; c++) { n = rand()%100 + 1; }
[code]....
}//end generateTeam I'm not sure how to make it so that I can exclude the previous random number when generating the next one. As an example, I have 22 students and I get the number 19. Now I can't have 19 again because that guy already has it.
The program is to generate random numbers to a file and will have one integer parameter, Open a file and then using a loop write the required number of random numbers to the file. Scale the random numbers from 1 and 100 inclusive. Then closes the file .The last function will read the numbers in the file into your program. so far i have
so I'm creating a program that generates random sentences with structs..I'm trying to use structs and and create 4 different groupings article, noun, verb, and preposition. Then I'm trying to use "r = rand() % ;" to randomly pick one one word from each group to make a sentence. this is what i have
Code:
typedef enum article { the = 1, a, one, some, any } article; typedef enum noun { boy = 1, girl, dog, town, car }
I want to print different color names for "nb " times . I get the number " nb " from the user or from text file . if " nb = 3 " then I want to print any 3 different color names which means that I may print ( red , green , blue ) for example . and if " nb=5 " then I have to print any five different color names ( pink , blue , black , red ,white ) fore example .
Note : " nb " may be a large number ( 17 for example ). How can I do this ?
I am trying to generate 3 random numbers between 1 and 6 using a function called generate_rand. but everytime im having an error : no oprators "<<" matches these operands and the last error was :end of file found before the left brace
my program is the following :
# include<iostream> #include<cstdlib> using namespace std;
