Store the result into an array D of 8 elements. Your program should show the decimal numbers for every binary number. Print screen of 6 answers. This means you should try your program six times with different numbers in every run and show the printed screen result.
I'm trying to write a program that converts a decimal number to a binary one. I have most of the program written, but I am having a little bit of trouble. Whenever I enter a decimal number, the program will convert it correctly to binary, however, the last number is not included in the conversion. EX: Converting 37 into binary (0100101) yields 010010 when entered into the program. BTW the program must utilize recursion to achieve this goal.
#include <iostream> using namespace std; void decToBinary(int num1); int main() { int num1;
Now I have the binary numbers printed out in my code, but I don't know how I can covert them into to decimal.
#include <iostream> #include <iomanip> #include <string> #include <cmath> using namespace std; int main() { int numberOfDigits; int numberOfRows; char flag;
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111 Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010 Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102 Number entered is not a binary number
#include <iostream> using namespace std; int main() { int num;
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h> #include <math.h> char* ReverseString (char _result[]) { int start, end, length = strlen(_result); char swap; for (start = 0, end = length-1; start < end; start++, end--)
I have a code and am asked to modify it so that it will take as input as unsigned binary number up to 16 digits in length and convert it into its equivalent decimal number and output that decimal number.
All I know is that I use library function strlen() in <cstring> to calculate the length of the input string.
I also know I have to use something called pow(2,4);
//pow (); is found in cmath
I was told to use sum = sum >>16-l; (l is the length of />/>
#include <iostream> using namespace std; int main() {
Create a program that will ask the user to enter a decimal value (1-999999) then display its corresponding binary numbers. Repeat this process until the value entered is equal to 0. Use the following Function Prototype:
void BinCodes(int value); Sample Input/Output: Enter a Decimal: 35 Binary: 100011 Enter a Decimal: 184 Binary: 10111000 Enter a Decimal: 0
My size of binary file is 1920 KB and my struct size is 124 kb. now to find number of records in file I divided 1920/124 and it gives me 15.4.... do I add 1 to 15.4 and make it 16 or do i take it as 15?
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){ char* binNum = decToBin(25); int i = 0; while(binNum != NULL){
I'm trying to figure out why the binary to decimal part is not working correctly when the binary value finishes with a 1. In those cases, the decimal value shown in one unit smaller than it should be.
Code:
#include <iostream> #include <cstdio> #include <cstdlib> using namespace std; void Binary_to_Decimal(), Decimal_to_Binary(); //prototype for the 2 functions that contain the converters int main() //the menu { int a_Choice; cout << "Enter 1 - for binary to decimal" << endl; cout << "Enter 2 - for decimal to binary" << endl;
I need the user to be able to input the number of decimal places they wish to have displayed in the output. Everything works fine as is, I just don't know how to allow for the user to input the number of decimal places they want the output to have.
Code:
#include<stdio.h> #include<math.h> #define PI 3.141592654 int main(void) { //Local Declarations int x; //desired number of decimal places float radius; //radius of circle float circumference; //circumference of circle
The program is supposed to convert a two digit hexadecimal number to its binary representation. My code runs without any problems but I do not know how to limit the user's input to two digits only. For example the person can input "1ABC" and the program will give the binary representation and I need it to only accept two digit only like for example "1A".
#include<stdio.h> #define MAX 1000 int main(){ char binaryNumber[MAX],hexaDecimal[MAX]; long int i=0; printf("Enter a two digit hexadecimal number: ");
Write a program in c++ to accept a number and convert this number into binary or hexa decimal or octal number according to the user choice using the concept of array.
This code is near complete, the only task that is left is allowing the user to input a decimal and then two integers, or automatically using .00 decimal.
The automatic part: /*This is not correct.
printf(".%.2d ", number); */
But that does no good for me. Question: Do I have to create a some sort of while loop again, to allow the user to input a decimal followed by integer?
Code: #include <iostream> #include <cstdlib> using namespace std; int main() { int j , i = 0, k = 0; int number;
Question: A computer uses 10 bits to store integers with 1 bit for a sign. It stores an approximation of real numbers in 10 bits. The first bit of the first five is the sign of the mantissa and the other four bits are the mantissa. The first bit of the second five is the sign of the exponent and the other four the exponent.
1)What is the range of integers?
2)what is the range of real numbers(Float Type)
The first question was simple. I just found the smallest 10 digit binary number 1000000000 = -512 and then found the largest 10 digit binary number which would have to be 0111111111 = 511, therefore the range of integers is from -512 to 511.
For the second question - I am either making this harder than it is, or it really is a challenging question. So I followed the steps and first I was thinking I would take the number 1000000000 and convert this to a decimal (assuming its a 10 bit float)...But, can you even do this with a 10 bit float??
I ended up getting 1000000000 (after denormalizing) = .000100000 = 0.625.. would that be the minimum range? If so, then I know what I need to do to find the maximum , but if not - then I am really lost.
My Process was:
1.00000 X 2^(-4) = my final result of 0.625 after converting.
i am having issues converting a fraction to a decimal, i think the code would go in the istream because it is working with input data but i just cant figure it out.
#include <cstdio> #include <string> #include <iostream> using namespace std;
I am new at programming and I have some questions about converting decimal to hexadecimal WITHOUT using .net library. The problem is, that I don't know how to do vice versa. (if you type 1254, program returns 6,14,4. I want programm to return 4,14,6- this is almost hexadecimal number (14 is not converted to "E")). Also the task is, that program has to return value in string form.
static void Main(string[] args) { int a = 0; int result = 0; int n=1000000; int[] array = new int[n]; Console.WriteLine("Insert numbers"); a = int.Parse(Console.ReadLine());
I have my program all but done, but I can't get past this last part. I need to have the user input their height as a decimal. For example someone who is 5 foot 11 inches would need to enter it as 5.11, then I need to display there height in inches. Since i'm 5 foot 11, I would need to enter 5.11, then have it display 71 inches.
How to do this program i can easily do it in a simple for loop but i have to do this program with the following directions:
1. Write a function called bitN() that returns the value of bit N in number, where number is the first parameter, and N is the second. Assume N of the least significant bit is zero and that both parameters are unsigned int's. (A simple one-liner will suffice)
2. Write a main() function that uses bitN() to convert a decimal integer into its binary equivalent. Obtain the integer to convert from the first command-line argument.
3. Use the expression unsigned int numBits = sizeof(unsigned int)*CHAR_BIT; to get the number of bits in an unsigned int. (Include limits.h to get the definition for CHAR_BIT.)
