I have my program all but done, but I can't get past this last part. I need to have the user input their height as a decimal. For example someone who is 5 foot 11 inches would need to enter it as 5.11, then I need to display there height in inches. Since i'm 5 foot 11, I would need to enter 5.11, then have it display 71 inches.
View 4 RepliesThis program must take user input(from stdin) that contains both a number and then a punctuation character, either a single quote(') or double quote(") that specifies feet or inches. It keeps prompting the user to enter a length until the user enters the sentinel value of 0. For example:
Enter a measurement and unit: 1'
Enter a measurement and unit: 2"
Enter a measurement and unit: 0
Total: 14 inches
The ultimate goal of this program is to then write an Assembly language program that is structurally similar and makes use of these 4 functions:
void printStr(char *)
Arguments:
edi = address of null-terminated string to print
Returns:
Nothing
[Code] ...
So here is what I have:
int main() {
char value[50];
char *end;
int sum = 0;
long conv;
while(conv !=0)
[Code] .....
I was told to use fgets instead of scanf for for stdin to parse the number and the quotation marks. I think I converted the number from string to integer correctly with strtol, but I really do not know how to obtain the (") or (') from user input so the program knows whether to convert the number to feet or just inches. No matter what I type in, even if it's without a quotation mark, it still multiplies the number by 12. In the IF and ELSE IF statement, it should state
if(value = ''')
and...
else if(value = '"')
I was given an assignment to enter two sets of numbers for yards, feet, and inches, and then add them together and convert it to inches. That part of the program is correct, but now I need to calculate the area. It is a working program, but my final answer is in inches, and it is supposed to be in yards, feet, and inches. How do I convert the calculated inches back to yards, feet, and inches?
Code: typedef struct {
int yards;
int feet;
float inches;
} yardfeetinches;
typedef struct {
[Code] ....
I am new to c++, and I have been going through some basic code to get used to the syntax etc. I have encountered a compiling issue with my current code. The purpose of this code is to convert feet and inches into meters and centimeters.
#include <iostream>
#include <cmath>
using namespace std;
int main () {
<<<xcode is saying I have an expected expression on this blank line>>>
double feet1, inch1, inch2, meter1, centimeter1;
cout << "Please enter a length in feet and inches " << endl;
cin >> feet1 >> inch1 >> ;
I have tried rewriting the #include through int main () expressions, I've tried copy/pasting the lines from other pieces of code...
I have to write a code to convert centimeters to yards feet and inches i have the code wrtten up and keep getting 2 errors saying im missing a ; before << but im not sure why ?
#include <iostream>//For cin and cout
using namespace std;
int main(void) {
doublecentimeters; //INPUT
[Code] ....
I need to write this program (shown below) for class but i'm not sure how to print out a table?
Write a program to display a centimeters-to-inches conversion table. The smallest and largest numbers of centimeters in the table are input values from the user. Your table should give conversions in 10-centimeter intervals. One centimeter equals 0.3937 inches.
Here is my code so far
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
[Code].....
Question: A computer uses 10 bits to store integers with 1 bit for a sign. It stores an approximation of real numbers in 10 bits. The first bit of the first five is the sign of the mantissa and the other four bits are the mantissa. The first bit of the second five is the sign of the exponent and the other four the exponent.
1)What is the range of integers?
2)what is the range of real numbers(Float Type)
The first question was simple. I just found the smallest 10 digit binary number 1000000000 = -512 and then found the largest 10 digit binary number which would have to be 0111111111 = 511, therefore the range of integers is from -512 to 511.
For the second question - I am either making this harder than it is, or it really is a challenging question. So I followed the steps and first I was thinking I would take the number 1000000000 and convert this to a decimal (assuming its a 10 bit float)...But, can you even do this with a 10 bit float??
I ended up getting 1000000000 (after denormalizing) = .000100000 = 0.625.. would that be the minimum range? If so, then I know what I need to do to find the maximum , but if not - then I am really lost.
My Process was:
1.00000 X 2^(-4) = my final result of 0.625 after converting.
i am having issues converting a fraction to a decimal, i think the code would go in the istream because it is working with input data but i just cant figure it out.
#include <cstdio>
#include <string>
#include <iostream>
using namespace std;
[Code].....
I am new at programming and I have some questions about converting decimal to hexadecimal WITHOUT using .net library. The problem is, that I don't know how to do vice versa. (if you type 1254, program returns 6,14,4. I want programm to return 4,14,6- this is almost hexadecimal number (14 is not converted to "E")). Also the task is, that program has to return value in string form.
static void Main(string[] args) {
int a = 0;
int result = 0;
int n=1000000;
int[] array = new int[n];
Console.WriteLine("Insert numbers");
a = int.Parse(Console.ReadLine());
[Code] ....
I'm trying to write a program that converts a decimal number to a binary one. I have most of the program written, but I am having a little bit of trouble. Whenever I enter a decimal number, the program will convert it correctly to binary, however, the last number is not included in the conversion. EX: Converting 37 into binary (0100101) yields 010010 when entered into the program. BTW the program must utilize recursion to achieve this goal.
#include <iostream>
using namespace std;
void decToBinary(int num1);
int main() {
int num1;
[code]....
This is the question: [URL] .....
Now I have the binary numbers printed out in my code, but I don't know how I can covert them into to decimal.
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;
int main() {
int numberOfDigits;
int numberOfRows;
char flag;
[Code] ....
Write a C++ program that adds three binary numbers of 8-bit each. Every number is stored into an array of 8 elements.
Example:
Array A
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array B
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array C
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
Store the result into an array D of 8 elements. Your program should show the decimal numbers for every binary number. Print screen of 6 answers. This means you should try your program six times with different numbers in every run and show the printed screen result.
I have the code working on converting a decimal number to base 1 through 16. I need getting the code to output the one's and two's complement.
Code:
#include <stdio.h>
int main(void) {
char base_digits[16] =
{'0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
int converted_number[64];
long int number_to_convert;
int next_digit, base, index=0, a;
/* get the number and base */
[Code] ....
User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code:
#include <stdio.h>#include <string.h>
int main () {
char A[100];
int length = 0;
int i;
[Code] .....
(Program) a. Write a C++ program to convert meters to feet. The program should request the starting meter value, the number of conversions to be made, and the increment between metric values. The display should have appropriate headings and list the meters and corresponding feet value. If the number of iterations is greater than 10, have your program substitute a default increment of 10. Use the relationship that 1 meter = 3.281 feet.
b. Run the program written in Exercise 6a on a computer. Verify that your program begins at the correct starting meter value and contains the exact number of conversions specified in your input data.
here is what have so far
#include<iostream>
#include <iomanip>
using namespace std;
// a programs to convert meter to feet
int main() {
const int MAXMETER = 10;
[Code] ....
I don't know how to have a setup where you input the values, and then will be provided the output.
Write a program to convert a measurement in centimeters to inches. The numbers of centimeters should be read as input. Define int variable for centimeters, inches, and feet. Convert the centimeters to inches, then convert the inches to feet and inches (use the % operator). Print the distance in all three units. There are 2.54 centimeters in each inch and 12 inches in each foot.
View 3 Replies View RelatedExerted by the rider's foot yet not exceed the stress placed on the crank arm's sprocket attachment, is provided by this formua:
r^3 = d*p/s*π
r is the radius of the cylindrical rod in inches. d is the length of the crank arm in inches. P is the weight placed on the pedal in lbs. S is the stress in lbs/in2
Using this information, design, write, compile, and execute a C++ program that computes the value of r for a crank arm that is 7 inches long, accommodates a maximum weight of 300 lbs, and is able to sustain a stress of 10,000 lbs/in2.
What I'm trying to accomplish is to ask the user what their floor plan is (in square feet), have them pick what kind of material they want and give them a general price.
Which is working out great so far, but I would also like to add a loop at the end that cycles back if they want to re-do the estimate with a different material selection and if not exit out the program.
I've been trying do while and if/else loops but i can't get them to work right.
#include <iostream>
#include <string>
using namespace std;
int main() {
string custName, selection;
int custNumber, floorSize, material, contactSystem;
[Code] ....
That's basically what I've come up with so far minus all the erroneous attempts. Though as is I technically complete the assignment, I would like the extra credit from making the last part loop.
I am attempting to write a simple C program, in which the user is asked to input their name and height in inches and the output is the user's height in centimeters.
I have attached my program and what happens when I try to run it.
Attached Images : PM.jpg (120.6 KB)
How would you go about converting a decimal value to hex and then do math? Every example of converting decimal to hex that I have seen creates an array and I wouldn't be able to do math if I did that. Something like this.
15 decimal to hex F
17 decimal to hex 11
F hex + 11 hex = 20
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h>
#include <math.h>
char* ReverseString (char _result[]) {
int start, end, length = strlen(_result);
char swap;
for (start = 0, end = length-1; start < end; start++, end--)
[code]....
How to do this program i can easily do it in a simple for loop but i have to do this program with the following directions:
1. Write a function called bitN() that returns the value of bit N in number, where number is the first parameter, and N is the second. Assume N of the least significant bit is zero and that both parameters are unsigned int's. (A simple one-liner will suffice)
2. Write a main() function that uses bitN() to convert a decimal integer into its binary equivalent. Obtain the integer to convert from the first command-line argument.
3. Use the expression
unsigned int numBits = sizeof(unsigned int)*CHAR_BIT;
to get the number of bits in an unsigned int. (Include limits.h to get the definition for CHAR_BIT.)
To one decimal place?
Code:
#include <stdio.h>
int main() {
double num, trunc, round;
printf("
Enter a Decimal:
}
[code]...
That's my code currently, I've gotten it to round as I want, but I want it to truncate to one decimal place as well.If i enter 4.157, It should truncate to 4.1, and round to 4.2.
I'm trying to make a program that takes up to a seven digit binary number and converts it to its decimal equivalent. I'm still a beginner, so this might be a simple question but how do I stop the user from entering anything but 1s and 0s? This means no decimals or numbers other than 1 or 0.I already made it so it won't accept anything below 0 or above 1111111.
View 1 Replies View RelatedI am trying to convert user inputted decimal to binary .
Code:
#include<stdio.h>
main() {
int a,b,c,d[30],i,j,e[30];
[Code].....
I just wrote code that is a program for a relativity calculator. However many of my outputs (because the values tend to be large) end up in scientific notation. Although useful, its not great for the laymen, or nice looking.
How can I change it so that output is not in scientific notation? here is the code:
// This program/converter is designed to find the desired 'real' values using Einstein's theory of relativity
#include<iostream>
#include<math.h>
#include<stdlib.h>
[Code]....