This is the question: [URL] .....
Now I have the binary numbers printed out in my code, but I don't know how I can covert them into to decimal.
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;
int main() {
int numberOfDigits;
int numberOfRows;
char flag;
[Code] ....
I'm trying to write a program that converts a decimal number to a binary one. I have most of the program written, but I am having a little bit of trouble. Whenever I enter a decimal number, the program will convert it correctly to binary, however, the last number is not included in the conversion. EX: Converting 37 into binary (0100101) yields 010010 when entered into the program. BTW the program must utilize recursion to achieve this goal.
#include <iostream>
using namespace std;
void decToBinary(int num1);
int main() {
int num1;
[code]....
User enters sentence "The Smiths have two daughters, three sons, two cats and one dog." (The numbers may change depending on what the user chooses to enter. He told us the range would be from zero to nine.) and we have to convert the written numbers within the sentence into actual decimal numbers and print out the new sentence. Ex. The Smiths have 2 daughters, 3 sons...etc.
I have written the following bit of code which reads the string and finds all the "written numbers" but I am not sure how to proceed from there. I am stuck on how to print out the new sentence with the converted numbers as my professor mentioned something about creating the new string using dynamic memory allocation.
Code:
#include <stdio.h>#include <string.h>
int main () {
char A[100];
int length = 0;
int i;
[Code] .....
Write a C++ program that adds three binary numbers of 8-bit each. Every number is stored into an array of 8 elements.
Example:
Array A
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array B
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array C
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
Store the result into an array D of 8 elements. Your program should show the decimal numbers for every binary number. Print screen of 6 answers. This means you should try your program six times with different numbers in every run and show the printed screen result.
The code should convert binary numbers to decimal but it doesn't..
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
int main()
{
[Code] ....
Create a program that will ask the user to enter a decimal value (1-999999) then display its corresponding binary numbers. Repeat this process until the value entered is equal to 0. Use the following Function Prototype:
void BinCodes(int value);
Sample Input/Output:
Enter a Decimal: 35
Binary: 100011
Enter a Decimal: 184
Binary: 10111000
Enter a Decimal: 0
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3
10110101
11111111
10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
Question: A computer uses 10 bits to store integers with 1 bit for a sign. It stores an approximation of real numbers in 10 bits. The first bit of the first five is the sign of the mantissa and the other four bits are the mantissa. The first bit of the second five is the sign of the exponent and the other four the exponent.
1)What is the range of integers?
2)what is the range of real numbers(Float Type)
The first question was simple. I just found the smallest 10 digit binary number 1000000000 = -512 and then found the largest 10 digit binary number which would have to be 0111111111 = 511, therefore the range of integers is from -512 to 511.
For the second question - I am either making this harder than it is, or it really is a challenging question. So I followed the steps and first I was thinking I would take the number 1000000000 and convert this to a decimal (assuming its a 10 bit float)...But, can you even do this with a 10 bit float??
I ended up getting 1000000000 (after denormalizing) = .000100000 = 0.625.. would that be the minimum range? If so, then I know what I need to do to find the maximum , but if not - then I am really lost.
My Process was:
1.00000 X 2^(-4) = my final result of 0.625 after converting.
i am having issues converting a fraction to a decimal, i think the code would go in the istream because it is working with input data but i just cant figure it out.
#include <cstdio>
#include <string>
#include <iostream>
using namespace std;
[Code].....
I am new at programming and I have some questions about converting decimal to hexadecimal WITHOUT using .net library. The problem is, that I don't know how to do vice versa. (if you type 1254, program returns 6,14,4. I want programm to return 4,14,6- this is almost hexadecimal number (14 is not converted to "E")). Also the task is, that program has to return value in string form.
static void Main(string[] args) {
int a = 0;
int result = 0;
int n=1000000;
int[] array = new int[n];
Console.WriteLine("Insert numbers");
a = int.Parse(Console.ReadLine());
[Code] ....
I have my program all but done, but I can't get past this last part. I need to have the user input their height as a decimal. For example someone who is 5 foot 11 inches would need to enter it as 5.11, then I need to display there height in inches. Since i'm 5 foot 11, I would need to enter 5.11, then have it display 71 inches.
View 4 Replies View RelatedI have the code working on converting a decimal number to base 1 through 16. I need getting the code to output the one's and two's complement.
Code:
#include <stdio.h>
int main(void) {
char base_digits[16] =
{'0', '1', '2', '3', '4', '5', '6', '7',
'8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
int converted_number[64];
long int number_to_convert;
int next_digit, base, index=0, a;
/* get the number and base */
[Code] ....
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h>
#include <math.h>
char* ReverseString (char _result[]) {
int start, end, length = strlen(_result);
char swap;
for (start = 0, end = length-1; start < end; start++, end--)
[code]....
How to do this program i can easily do it in a simple for loop but i have to do this program with the following directions:
1. Write a function called bitN() that returns the value of bit N in number, where number is the first parameter, and N is the second. Assume N of the least significant bit is zero and that both parameters are unsigned int's. (A simple one-liner will suffice)
2. Write a main() function that uses bitN() to convert a decimal integer into its binary equivalent. Obtain the integer to convert from the first command-line argument.
3. Use the expression
unsigned int numBits = sizeof(unsigned int)*CHAR_BIT;
to get the number of bits in an unsigned int. (Include limits.h to get the definition for CHAR_BIT.)
I'm trying to make a program that takes up to a seven digit binary number and converts it to its decimal equivalent. I'm still a beginner, so this might be a simple question but how do I stop the user from entering anything but 1s and 0s? This means no decimals or numbers other than 1 or 0.I already made it so it won't accept anything below 0 or above 1111111.
View 1 Replies View RelatedI am trying to convert user inputted decimal to binary .
Code:
#include<stdio.h>
main() {
int a,b,c,d[30],i,j,e[30];
[Code].....
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int N=0, counter=0, counter1=0,counter2=0, temp=0, temp1=0,dec=0,result=0, moder=0;
[Code] .....
This is Binary to Decimal Converter. It's not working. Although Dry Run of this program works fine.
#include<iostream>
#include<conio.h>
using namespace std;
void main() {
int num1,num2,ans,rem;
[Code] .....
I have a code and am asked to modify it so that it will take as input as unsigned binary number up to 16 digits in length and convert it into its equivalent decimal number and output that decimal number.
All I know is that I use library function strlen() in <cstring> to calculate the length of the input string.
I also know I have to use something called pow(2,4);
//pow (); is found in cmath
I was told to use sum = sum >>16-l; (l is the length of />/>
#include <iostream>
using namespace std;
int main() {
[Code]....
So I tried debugging this program almost 10 times, each time finding a problem then making code to fix it, I used to get wrong values but then now after I changed the calculation from an infinity while loop to a for loop (because after some changes I realized that now I know the number of entries, meaning the start and the end of the loop) the program now displays no values at all. I checked it thoroughly and until the calculation process its functioning exactly the way it should but then the calculation breaks hell loose . Also the for loop that raises 2 to the power needed works fine too so it must be something with the other processes included in the calculation....
This used to be a function of a multiple value types conversion program, I isolated it for easier analysis as a lone standing program.
Code:
#include<iostream>
using namespace std;
int main() {
int d[10],e[10],anse=1,r,limit;
short int counterd=0,i,j;
float bind=0;
[Code] ....
I had an exercise to convert from decimal to binary with base 2, it was simple simple i did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
[Code] .....
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ......
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
Code:
#include <stdio.h>
#include <stdlib.h>
#define MAX_LEN 20
void translate_dec_bin(char s[]){
char st[sizeof(unsigned)*20] = { 0 };
}
[code]....
I was trying to program an decimal to binary converter (8-bits) in C. I am a complete beginner so I tried to put the 1's and 0's of the binary number as they come without reversing the order for beginning. I have seen example on the internet but didn't understand them so I decided to write it as I understood it. So, I typed the code as shown below:
Code:
#include <stdio.h>
#include <stdlib.h>
int main() {
int number;
int BitNum[8], x;
[Code] ....
The problem with the code is that if binary form has 0s in it then program displays a random number instead of a 0. For example if decimal is 7, it should print out 11100000 but it displays only 111(and some stupid numbers instead of 0). I have tried to solve it but failed.
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) {
int remainder = 0;
while ( num > 0) {
remainder = num % 2;
cout << remainder;
num = num / 2;
[Code] .....
Basically I have 2 questions.
1. Because of how limited integers are in terms of storage, the largest binary number i can give seems to be 1 111 111 111. Anything larger breaks the program. Is there any way to increase the largest input I can give without completely rewriting the program? I tried changing the num/numCounter (and the typecasting) to long doubles, but it just messed stuff up (or I did).
2. I'd also like to make it so that if someone inputs a non-binary number my program tells them so and stops. I figured a switch statement within the while loop would work (for when numCounter/divisor is negative or greater than 1), but I was wondering if instead it was possible to use an if statement that could break the while loop?
Anyway, here's the code:
Code:
#include <QtCore/QCoreApplication>
#include <iostream>
#include <cstdlib>
#include <iomanip>
#include <cmath>
using namespace std;
int main(int argc, char *argv[]) {
QCoreApplication a(argc, argv);
[code]....
I'm trying to figure out why the binary to decimal part is not working correctly when the binary value finishes with a 1. In those cases, the decimal value shown in one unit smaller than it should be.
Code:
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;
void Binary_to_Decimal(), Decimal_to_Binary(); //prototype for the 2 functions that contain the converters
int main() //the menu {
int a_Choice;
cout << "Enter 1 - for binary to decimal" << endl;
cout << "Enter 2 - for decimal to binary" << endl;
[code]....