C++ :: How To Append Strings To The Front Of Other Strings
Apr 7, 2013
I am programming a translator, and I have it so that it detects words with spaces both in front of and behind them, so I did "string.append(space);" where space equals " ". That added a space to the end, but I still need a space added to the front.
I have a problem who must print the sentences who have lenght more than 20 characters. I dont know why, but it prints just the first words. Look what i made.
#include<stdio.h> #include<conio.h> int main()
[Code]....
For instance :
Give the number of sentences : 3
First sentence : I like the website bytes.com Second sentence : I like more the website bytes.com Third sentence : bytes.com
After I compile the program it should print the first two sentences.
1. I finished reading a beginning C book, and in the section about arrays, it says that one string can fit in a character array (char arrayname[]) but there cannot be a string array (string arrayname[]) that have multiple strings. Is
Code: string arrayname[4] = {"one", "two", "three"}; not valid?
My compiler lets me run it and it works, but why is the book saying it's wrong?
2. I know you can represent multiple strings in a character array by:
because [10][4] indicates that there should be four newarrays created with a max of 10 characters each, but is
Code: string multiplestrings[10][4] = ("i love you", "hello come to me", "i don't get C"; "hello world", "what are arrays"; "i am happy", "I am learning how to code"); valid?
Does multiplestrings[10][4] basically create 4 string arrays that have a maximum of 10 different strings within each string array?
How join two strings? basic reason is add given filename little text to end. I try do by hobby not school project program which converts files format x to format y.i dont say which formats becouse reading and writing is almost done. (only little amount code is needed).'
if (letter3==" "){ letter3==letter; PrintCharacterLineEnd();
This is a code. the string "letter3" contains the string " ". What I want to happen is when, letter3 contains the text " " I want to go to the function PrintCharacterLineEnd.
I need to make a small program with a function with this prototype: void f(char *a,char *b) that adds two numbers represented as strings without using conversion operators or other tricks.
I have a vector I want to add book titles to, then i want to print my updated vector. This is best I have come up with but the program fails at the getline line. why?
string book; cout << "Enter book to add: "<< endl; getline(cin, book); books.push_back(book); for(int i = 0; i < books.size(); ++i) { cout << i+1 << ". " << books[i] << endl; }
The problem with this code is that there are no errors showing, but when i compile the program, the if else statements do not carry out as they should do. Both if statements show the same answer, for example the second if statement. If I type Y or N then I get the same thing, 'You will now choose an event'. How do i get rid of this problem? Is char supposed to be used or string?
I am trying to figure out how to go about comparing two strings of numbers. I have two files that both contain numbers 1-50, one file has multiple repeating numbers while the other one just has 1-50.
I want to compare the files and count how many of each number a occurred and make a chart with * next to the number. First I figured I would use the strings like an array and compare them using nested loops. Then I noticed I have single and double digit numbers. The numbers in the files are printed as:
1 44 5 34 4 2 22 7 55 4 ...... etc
Compared too: 1 2 3 4 5 ...... 50
I thought about using string stream and converting the string to int but wouldn't it just be a huge number when set to the int variable? Then I thought about a array initialized with 1-50 and compared to the file but I still have the issue with single and double digit numbers.
My question is how can I just read one number at a time, either double or single digit?
Basically what i am trying to do is that sort the names of 10,000 movies and then write those names to a text file. It gives an error in the nested loop by underlining arr and tells that no suitable conversion function from std::string to const char* exists.
It appears that when you enter command line arguments or use fgets() to input a string you can assign that string to another string variable using the assignment operator. But when you read from a file, you can't do that, you get a segfault. It seems the only way to get around that is to malloc the string and use the strcpy function.
Code: #include <stdio.h> struct person { char *names[2]; }; void readFile(struct person p){ FILE *file = fopen("names", "r");
I thought that if I were to access Buffer1 via BufPtrs[0], I would simply just put an * to it before printf()-ing or store it in a char[] (equivalent to a string).
I am currently using Dev-C++ 4.9.9.2 compiler for creating a C project. I need few strings to be printed in a different color.
Code: #include<stdio.h> #include<conio.h> int main(void) { textcolor(RED); cprintf("Hello world "); system("pause"); }
While I use " textcolor(RED) " it says: 'RED' undeclared, first use in this function.
If i make it: " textcolor(3) ", it says: [Linker error] undefined reference to textcolor & undefined reference to cprintf.
have been searching for a solution on google since morning. At last I could make out that it is not the correct compiler with suitable library or outdated <conio.h> header file.
I had switched from turbo(or borland, I don't remember) to Dev-C++ compiler due to some kind of library issue. Now I guess I'll have to switch to some other IDE. Which one is that, I don't know yet. There was another thread also about this topic, but didn't provide any solution.
Is there any method to upgrade certain header file (I don't think so)? What would be the best IDE with updated libraries?
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
Code:
#include <stdio.h> int main () { /* variable definition: */
This code i made divided a user input into characters and non character. The problem im having is that if a mixed sentence is created, such as 32B, it will only print the 'char string' and not the 'non char string'. But when the sentence is just non characters like 32 it will print the 'non-char string'. So essentially if a mixed sentences is created both of the strings won't be created or printed.(This is only a function by the way).