The question is Create a counting program that counts backward from 100 to 1 in increments of 10.
#include <iostream>
using namespace std;
int main() {
int num = 1;
while (num<100) {
[Code] ....
It seems there are some errors.
Code:
char *ptr;
printf("Output: %d %d %d
",sizeof(ptr), ptr, ptr+1);
Output: 4 214734480 214734481
int *ptr;
printf("Output: %d %d %d
",sizeof(ptr), ptr, ptr+1);
Output: 4 214734480 214734484 when size of the pointer is the same "4 bytes" whether its a char pointer or a int pointer, but why a char pointer increments 1 where as int pointer increments 4.
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I'm trying to make a program who increments the value of all cells of an array but when i try to compile i get this error message:
Quote
error: incompatible types when assigning to type "int[9]" from type "int *"
The best I could come up with is this.
while(true){
wisdomCnt++;
_stprintf_s(szBuffer, _T("%i"), wisdomCnt/10000);
TextOut(hdc,120,10,szBuffer, _tcslen(space));
}
but the program is constantly loading and clicking anywhere causes it to stop responding. Is there a better way to do this especially in Win32 API?
I am trying to fill an array of size 16 A-P forward and backward but im having a hard time filling the array with A-P. Here's what i have so far.
#include<iostream>
#include<iomanip>
using namespace std;
int main() {
int arr[16];
char mych='A';
[Code] ....
I have a problem requiring me to :
enter loan amount:
Enter interest rate:
Enter length of loan (years)
It wants me to input the minimum amount for the loan, and the minimum interest rate. and then output a table that has 5 loan amounts across the top in $10000 increments and 4 interest rates along the side in .25% increments.
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
int main () {
double loan, interest, length, payment,ti;
//Enter loan price
[Code] .....
My program , it says there is no problem with the build but when exe. it displays a bunch of backward 'k' instead of reversing the words entered.
Problem: Enter in a C-string and use function to display the word backward. (it might work with a pointer but I am not sure how to go about it)
lab10_p2.cpp
I am working on a project in which I use DirectShow to Play / Pause / Stop the video. I am using slider bar to show the progress of the video. As the video starts playing, the slider bar moves in proportion to the video duration. Now when user moves/drags the slider bar to a new position, I want to forward the video in equivalent proportion.
Say if video duration is 50 seconds and max range of the slider bar is set to 100. slider will 2 steps for 1 second of video progress. Now if user drags the slider to 60 while video is playing, I want to increment/forward the video. if user moves the slider backward, video should move backward.
I have done with the slider moving along with the video and when user drags the slider. How to set the new position of the video, so that the video starts playing from that point.
I'm trying to print a single linked list backward with functions/classes. I have created the main file and 3 header files. But I'm getting an error on one of the header files, linkedListIterator after adding #include "linkedListType.h". It says that "linkedLlistType.h" is calling itself. And when I try to run it, I get an error of "too many header files." I have tried changing the headers many times, but nothing seems to work.
.cpp file:
/*(Printing a single linked list backward) Include the functions reversePrint and recursiveReversePrint, as discussed in this chapter, in the class linkedListType. Also, write a program function to print a (single) linked list backward. (Use either the class unorderedLinkedList or the class orderedLinkedList to test your function.)*/
#include "linkedListType.h"
#include "orderedLinkedList.h"
#include "linkedListIterator.h"
#include <iostream>
using namespace std;
struct nodeType
[Code] ....
header files:
[URL] .... (error in this header file)
[URL] ....
I am using a for loop to count down from 10 to 0 it's working to count down from 10 to 1 but when the program cames to the 0 then the program freezes by any reason.
Code:
#include <iostream>
using namespace std;
int main()
{
int number[2];
cout << "Enter number: ";
cin >> number[0];
if (number[0] == 1)
[Code] ....
I'm just trying to find out if the way I've setup my code currently allows me to count the letters as they occur? I don't yet see how to do it but I need clarification. Ideally the function letterCounter would do the counting but atm I'm just trying to figuring it out in the display function.
View 2 Replies View RelatedI have the following code to print a string to the LCD using my PIC32 Starter Kit; I have made this code work with success. I cannot, however, make the LCD print numbers.
#include<p32xxxx.h>
#define LCD_PRT PORTE //LCD DATA PORT
//#define LCD_DDR DDRE//LCD DDR
//#define LCD_PIN PINE//LCD PIN
[Code].....
I want to change the original code as little as possible, don't worry about my header files - they are fine.
i couldn't count the 2d string. my string is list[100][100] = {"Batuhan","Jeyhun","Tashtanbek"} this is a food line in cafeteria. i want to add a person to this list but i couldnt do it because i dont know the length of my list. it will be more than 3 after i add a person but what if i would add another person after that ? In that case i couldnt be able to tell how long is my line.And after i add people to my list i want to print that list. here is where i came so far:
case 1:
printf("Enter the name of the person to be added
");
printf(">>");
k=0;
[Code].....
I am using this code that to check a set of values from a text file and show it on the output.
Code: void MatchNumber(int b) {
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
double x1,y1,x2,y2;
while(theFile >> x1 >> y1 >> x2 >> y2 ){
rects.push_back(Rect(x1,y1, x2,y2));
}
int num=0;
[code]....
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5
The common number is = 6
The common number is = 4
The common number is = 5
The common number is = 5
The common number is = 8
The common number is = 9
The common number is = 6
The common number is = 6
[code]....
How can I do that?
a sample program using c language on how to count sentences in a paragraph...
View 3 Replies View RelatedI am new to c++. I am writing a program that reads in a text file and gives a count of how many times each letter appeared in the file. I got it to read the text file and do the letter count. B
X = 102
Y = 126
Z = 165
etc...
THAT IS WORNG
The sample output should be
E = 165
T = 126
A = 102
O = 93
etc...
I got it to sort from lowest to highest for the frequency, but cant seem to get the appropriate letter assigned to it.
#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
[code].....
iam trying to count the same numbers in an array just once like
38
38
40
38
40
37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream>
using namespace std;
int main(){
[Code].....
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
int IntegerArray::countBelowAverage(int numBelowAvg) {
avg=IntegerArray::getAvg();
for(int ct=0; ct<avg; ++ct) {
numBelowAvg=ct;
}
return numBelowAvg;
}
My output from this is always 0 and I know that there are numbers below the avg.
I was coding a program that can count space, new_line, and other characters in a paragraph, but it doesn't work.
#include <stdio.h>
int main(void)
{
[Code].....
I have a question regarding reference count of an object. How i'll be able to know that how many pointers are pointing to my object.....
View 3 Replies View Relatedhow to put 2 letters together and make them to count as 1?
provided that they must consecutive
for example:
p : count as 0
pxp : count as 0
pp : count as 1
xpxp: count as 0
ppxpp : count as 2
I want to count values in a struct.
typedef struct {
int x;
int test;
}TYPE_TEST;
TYPE_TEST My[6] ={
{16, 50},
{4, 51},
{50, 52},
{47, 53},
{10, 54},
{19, 55}
};
int Newbuffer[ ????? ]
Now I want to make the size of Newbuffer the sum of all "x", that is 146. Not the size of X.
But how to sum all "x".
I am trying to keep a count on a variable name stored within a structure as char*'s. They are of the same field and I do not know how many there will be so I would like to keep a standard name and append the count.
So say I have a variable name such as "desk", but as I have many of these said desks so I would like to call them "desk1", "desk2", "desk3" and so forth. Any recommendations on how I could do this?
Also since this is somewhat relevant is there an easy way to convert from an integer to a string, something that would work like atoi() in reverse? I wouldn't mind writing a method to do so myself but haven't a clue as to how.
I need a way to count lines in a .dat file using fscanf. I must use a regex to check that the characters in the file are alphanumeric. In essence I need to count the ' ' character. I know fscanf ignores this character. I need to exit if it detects anything other than alphanumeric with the digit that is "problem" along with the line number. My .dat file is:
Code:
howard jim dave
joe
(
Maggie My fileCheck.c is: Code: #include "main.h"
int fileCheck(FILE *fp)
{
int ret_val;
int line_count = 0;
char file[BUFF];
[Code]...
The output I am getting is:
Code:
file opened Digit: ( is not an alphanumeric character on line: 5 Program will exit! File closed As you can see, the character "(" is not on the 5th line but the 3rd. It is the 5th "string."
I also wanted to show the regex I am using.
Code:
#define to_find "^[a-zA-Z0-9]+$"
How this can be accomplished?
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int inputs[30];
int numofloops;
int maxvalue = inputs[0];
[Code]...